Chapter 8: Problem 60
Simplify. $$ 1+\frac{1}{2}+\left(\frac{1}{2}\right)^{2}+\left(\frac{1}{2}\right)^{3} $$
Short Answer
Expert verified
The sum is \( \frac{15}{8} \).
Step by step solution
01
Identify the Series
Recognize that the expression is a geometric series. A geometric series is a series of the form \( a + ar + ar^2 + ar^3 + \text{...} \), where \( a \) is the first term and \( r \) is the common ratio. Here, \( a = 1 \) and \( r = \frac{1}{2} \).
02
Apply the Sum Formula for a Finite Geometric Series
The sum \( S_n \) of the first \( n \) terms of a geometric series can be found using the formula \[ S_n = a \frac{1 - r^n}{1 - r} \]. For the given series, we have 4 terms: \( 1, \frac{1}{2}, \left( \frac{1}{2} \right)^2, \left( \frac{1}{2} \right)^3 \).
03
Insert Values into the Formula
Substitute \( a = 1 \), \( r = \frac{1}{2} \), and \( n = 4 \) into the formula: \[ S_4 = 1 \frac{1 - (\frac{1}{2})^4}{1 - \frac{1}{2}} \].
04
Simplify the Expression
First, calculate \( (\frac{1}{2})^4 \): \( (\frac{1}{2})^4 = \frac{1}{16} \).Next, substitute back for the formula: \[ S_4 = \frac{1 - \frac{1}{16}}{1 - \frac{1}{2}} \]Then simplify numerator: \[ 1 - \frac{1}{16} = \frac{16}{16} - \frac{1}{16} = \frac{15}{16} \].
05
Finalize the Calculation
Now divide the fraction to find the sum: \[ S_4 = \frac{\frac{15}{16}}{\frac{1}{2}} \]Invert and multiply by the reciprocal of the denominator \[ S_4 = \frac{15}{16} \times 2 = \frac{30}{16} = \frac{15}{8} \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Finite Geometric Series
A finite geometric series is a series with a finite number of terms, where each term after the first is found by multiplying the previous term by a constant called the 'common ratio'. For example, in the series given in the exercise:
- First term, \(a = 1\)
- Second term is \(ar = 1 \times \frac{1}{2} = \frac{1}{2}\)
- Third term is \(ar^2 = 1 \times (\frac{1}{2})^2 = \frac{1}{4}\)
- Fourth term is \(ar^3 = 1 \times (\frac{1}{2})^3 = \frac{1}{8}\)
Sum Formula
To find the sum of the first \(n\) terms of a finite geometric series, we use the sum formula: equation: \( S_n = a \frac{1 - r^n}{1 - r} \). In this formula:
- \(S_n\) is the sum of the first \(n\) terms
- \(a\) is the first term
- \(r\) is the common ratio
- \(n\) is the number of terms
Mathematical Simplification
Simplifying mathematical expressions is a crucial step in finding the solution. For the sum formula, we need to calculate and substitute the values correctly. First, we substitute \(a = 1\), \(r = \frac{1}{2}\), and \(n = 4\) into the sum formula: equation: \( S_4 = 1 \frac{1 - (\frac{1}{2})^4}{1 - \frac{1}{2}} \). Next, we calculate \((\frac{1}{2})^4\): equation: \((\frac{1}{2})^4 = \frac{1}{16}\) Then, substitute back into the formula: equation: \(S_4 = \frac{1 - \frac{1}{16}}{1 - \frac{1}{2}}\) Simplify the numerator: equation: \(1 - \frac{1}{16} = \frac{16}{16} - \frac{1}{16} = \frac{15}{16}\) Finally, divide to get the sum: equation: \(S_4 = \frac{\frac{15}{16}}{\frac{1}{2}} = \frac{15}{16} \times 2 = \frac{30}{16} = \frac{15}{8}\).
Common Ratio
The common ratio in a geometric series is the factor by which each term after the first is multiplied to get the next term. It is a crucial element in determining the series and applying the sum formula.In the series \(1, \frac{1}{2}, (\frac{1}{2})^2, (\frac{1}{2})^3\), the common ratio \(r\) is \(\frac{1}{2}\). To identify the common ratio:
- Divide the second term by the first term: \(\frac{\frac{1}{2}}{1} = \frac{1}{2}\)
- Divide the third term by the second term: \(\frac{\frac{1}{4}}{\frac{1}{2}} = \frac{1}{2}\)
- Check that this pattern holds for subsequent terms