Chapter 3: Problem 57
Divide and simplify: \(\frac{4}{5} \div \frac{7}{10}\).
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Chapter 3: Problem 57
Divide and simplify: \(\frac{4}{5} \div \frac{7}{10}\).
These are the key concepts you need to understand to accurately answer the question.
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A cubic meter of concrete mix contains \(420 \mathrm{~kg}\) of cement, \(150 \mathrm{~kg}\) of stone, and \(120 \mathrm{~kg}\) of sand. What is the total weight of a cubic meter of the mix? What part is cement? stone? sand? Add these fractional amounts. What is the result?
Simplify. $$ \frac{\frac{1}{40}}{\frac{1}{50}} $$
Simplify. $$ \left(3 \frac{1}{2}-2 \frac{1}{3}\right)^{2}+6 \cdot 2 \frac{1}{2} \div 32 $$
Simplify. Find the prime factorization of \(150 .[2.1 \mathrm{~d}]\)
Simplify. $$ \frac{4}{6} $$
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