/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Solve. $$ 48,916 \cdot x=14,... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Problem 68

Solve. $$ 48,916 \cdot x=14,332,388 $$

Short Answer

Expert verified
x = 293

Step by step solution

01

- Understand the Equation

The given equation is \(48,916 \times x = 14,332,388\). This is a basic linear equation where the goal is to solve for \(x\).
02

- Isolate the Variable

To find the value of \(x\), isolate \(x\) by dividing both sides of the equation by \(48,916\).
03

- Perform the Division

Divide \(14,332,388\) by \(48,916\) to get \(x\): \[ x = \frac{14,332,388}{48,916} \] Simplifying this division yields \(x = 293\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Equations
Solving equations is a fundamental skill in algebra. An equation is a statement that two expressions are equal. In a linear equation like this one, we aim to find the value of the variable that makes the equation true. To do this, we use operations that will help simplify the equation and isolate the variable. It鈥檚 like a puzzle where each piece needs to fit in the correct place! We often encounter equations in the form of \(a \cdot x = b\), where the goal is to find the unknown variable, represented as \(x\). Here, \(a\) and \(b\) are constants.
Division
In this exercise, the key operation is division. To isolate the variable \(x\), we divide both sides of the equation by the same number. This step is crucial because it simplifies the equation and helps us find the value of \(x\). For example, starting with the equation \(48,916 \times x = 14,332,388\), we divide each side by \(48,916\) to get \[ x = \frac{14,332,388}{48,916} \]. Division helps us break down the problem into smaller, more manageable parts. Once we complete the division, we find that \(x = 293\).
Mathematical Isolation
Mathematical isolation involves rearranging an equation to get the variable alone on one side. This is done through inverse operations. In this exercise, our goal was to isolate \(x\). We started with \(48,916 \times x = 14,332,388\). To isolate \(x\), we needed to eliminate the coefficient 48,916 by dividing both sides by it. This left us with \(x = \frac{14,332,388}{48,916} = 293\). By isolating the variable, we simplify the equation and make it easier to understand and solve. This skill is fundamental for solving more complex equations and is widely used in algebra and beyond!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A box of mailing labels contains 750 labels on 25 sheets. How many labels are on each sheet?

Divide. $$ 699 \div 3 $$

Round to the nearest ten. $$ 798 $$

Add. $$ \begin{array}{r} 9002 \\ +4587 \\ \hline \end{array} $$

Estimate each sum or difference by first rounding to the nearest ten. Show your work. $$ \begin{array}{r} 673 \\ -\quad 28 \\ \hline \end{array} $$
See all solutions

Recommended explanations on Math Textbooks

Theoretical and Mathematical Physics

Read Explanation

Discrete Mathematics

Read Explanation

Pure Maths

Read Explanation

Statistics

Read Explanation

Probability and Statistics

Read Explanation

Logic and Functions

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.