Chapter 7: Problem 16
Prove Proposition 7.4.6. That is, let \((X, d)\) be a complete metric space and \(E \subset X\) a closed set. Show that \(E\) with the subspace metric is a complete metric space.
Short Answer
Expert verified
Closed subsets of complete metric spaces are complete with the subspace metric.
Step by step solution
01
Understand Definitions
Recall the definitions: A metric space \((X, d)\) is complete if every Cauchy sequence in \(X\) converges to a limit that is also within \(X\). A subset \(E\) of a metric space \((X, d)\) is closed if every limit of a convergent sequence of points in \(E\) is also in \(E\). In the subspace metric, the metric \(d\) is restricted to \(E\).
02
Select a Cauchy Sequence in E
Select a sequence \((x_n)\) that is a Cauchy sequence in \(E\) with the subspace metric. We aim to show that this sequence converges to a point in \(E\).
03
Sequence in X
Since \(E\subset X\) and \((x_n)\) is a sequence in \(E\), it is also a Cauchy sequence in \(X\) because \(d_E\) is a restriction of \(d\). Therefore, \((x_n)\) is a Cauchy sequence in \(X\).
04
Use Completeness of X
Since \((X, d)\) is a complete metric space, the Cauchy sequence \((x_n)\) converges to some limit \(x_0 \in X\).
05
Show Limit is in E
Since \((x_n)\) is entirely contained in the closed set \(E\), and \(E\) is closed in \(X\), the limit \(x_0\) of \((x_n)\) must also be in \(E\) by the definition of a closed set.
06
Conclude Completeness of E
Thus, every Cauchy sequence in \(E\) converges to a limit in \(E\), meaning \((E, d_E)\) is a complete metric space where \(d_E\) is the subspace metric of \(d\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cauchy Sequence
A Cauchy sequence is a fundamental concept in analysis. It is a sequence of points in a metric space that eventually gets arbitrarily close to each other. In more formal terms, a sequence \(x_n\) is a Cauchy sequence if for every positive number \varepsilon\, there exists an integer \N\ such that for all integers \m, n \geq N\, the distance \(d(x_m, x_n) < \varepsilon\) holds true.
- This concept is essential because it helps us understand convergence, even if we do not know what the sequence converges to.
- Cauchy sequences are crucial when discussing the completeness of metric spaces, as demonstrated in the original exercise.
Closed Set
In the world of topology and metric spaces, a closed set is an important concept. A set \(E\) within a metric space is called closed if it contains all its limit points. This means that if a sequence of points in \(E\) is convergent, then the limit of that sequence is also in \(E\).
- Closed sets are always complete when they are considered with the subspace metric.
- Being able to identify closed sets can simplify the process of showing completeness for subspaces.
Convergent Sequence
A convergent sequence in a metric space is a sequence that approaches a particular point, called the limit, as the sequence progresses. Formally, a sequence \(x_n\) in a metric space \(X\) converges to a limit \(L\) if for every positive number \varepsilon\, there exists an integer \N\ such that for all integers \ greater than or equal to \N\, the distance \(d(x_n, L) < \varepsilon\).
- The limit \(L\) is in the same metric space as the sequence.
- Convergent sequences in complete metric spaces never "escape" the space, due to completeness.
Subspace Metric
When dealing with subsets of a metric space, we often use what is known as a subspace metric. This is essentially the same distance function as the original space, but now it is restricted to a subset \(E\). If \(d\) is the metric on the space \(X\), then for any two points \(x, y \in E\), the subspace metric \(d_E(x, y)\) is the same as \(d(x, y)\).
- Using a subspace metric allows us to examine properties of \(E\) with the same underlying structure as \(X\).
- The subspace metric retains all distance comparisons within \(E\), aiding in analyses like establishing completeness.