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Find a convergent subsequence of the sequence \(\left\\{(-1)^{n}\right\\}\).

Short Answer

Expert verified
Subsequences \(1, 1, 1, \ldots\) and \(-1, -1, -1, \ldots\) are convergent, to \(1\) and \(-1\) respectively.

Step by step solution

01

Understanding the Sequence

The sequence given is \((-1)^n\), which alternates between \(1\) and \(-1\). For even \(n\), it produces \(1\) (since \((-1)^{2k} = 1\)), and for odd \(n\), it produces \(-1\) (since \((-1)^{2k+1} = -1\)).
02

Identifying Subsequences

A subsequence is derived by selecting some elements from the original sequence while maintaining the order. From \((-1)^n\), we can make subsequences by selecting elements corresponding to all the even index terms or odd index terms.
03

Choosing the Convergent Subsequences

For even values of \(n\), let \(n = 2k\). Hence, the subsequence becomes \(\{1, 1, 1, \ldots\}\), and similarly, for odd \(n\), let \(n = 2k+1\). The subsequence becomes \(\{-1, -1, -1, \ldots\}\).
04

Proving Convergence

Let us prove the convergence:1. Consider the subsequence \(1, 1, 1, \ldots\). As each term is \(1\), this subsequence converges to \(1\).2. Consider the subsequence \(-1, -1, -1, \ldots\). As each term is \(-1\), this subsequence converges to \(-1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Subsequences
A subsequence is a concept in mathematics where we derive a new sequence from an original sequence by selecting certain elements and maintaining their original order. Think of it as picking certain terms from the list of a sequence, but you must keep them in the same order they appear in the original sequence. For example, if we consider the simple sequence of even numbers \( \{2, 4, 6, 8, \ldots\} \), a subsequence could be \( \{2, 6, \ldots\} \), where we just picked every other number. It's essential to note that subsequences can be infinite even if taken from an infinite sequence. This concept helps in analyzing the behavior of sequences, particularly in convergence where we look for parts of the sequence that tend towards a limit.
Sequence
A sequence is a list of numbers ordered in a specific manner where each number is called a term. In mathematics, sequences are functions whose domain is natural numbers. An example of a sequence is \( \{3, 6, 9, 12, \ldots\} \), known as the sequence of multiples of 3. Sequences can be either finite, meaning they have a last term, or infinite, with no end or last term.
  • A sequence can be increasing, where each number is larger than the previous or decreasing, where each number is smaller.
  • They can also be constant, like the sequence \( \{5, 5, 5, \ldots\} \), where all terms are identical.
  • Another important property of sequences is their convergence, where a sequence approaches a particular value as the number of terms goes to infinity.
Understanding sequences and their behavior is crucial in various fields of mathematics and plays a vital role in real analysis.
Alternating Sequence
An alternating sequence is one where the terms alternate in sign or follow a pattern of variation. In our original problem, the sequence \((-1)^n\) alternates between 1 and -1 depending on whether \(n\) is even or odd. This gives us a sequence that looks like \(\{1, -1, 1, -1, \ldots\}\). Alternating sequences have interesting properties:
  • They often do not converge, as there is no single value that all terms approach.
  • However, they can contain convergent subsequences, as seen in our exercise where subsequences like \(\{1, 1, 1, \ldots\}\) converge to 1.
Alternating sequences are especially important when studying series and their convergence, as they can affect the overall behavior of a mathematical expression.
Real Analysis
Real analysis is a branch of mathematics dealing with real numbers and sequences and functions of real numbers. It involves the rigorous study of the properties of sequences, including their limits and convergence. The foundational concepts of real analysis include:
  • Understanding limits and being able to determine when and how sequences converge.
  • Delving into the behavior of functions, continuity, differentiation, and integration.
  • Exploring the completeness of real numbers, which ensures that every Cauchy sequence of real numbers has a limit that is also a real number.
In real analysis, identifying convergent subsequences within a sequence, such as the those in the step-by-step solution given, is crucial for analyzing the overall behavior and properties of sequences, especially when they do not converge as a whole.

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Most popular questions from this chapter

Suppose \(\sum a_{n} x^{n}\) converges for \(x=1\). a) What can you say about the radius of convergence? b) If you further know that at \(x=1\) the convergence is not absolute, what can you say?

In the following exercises, feel free to use what you know from calculus to find the limit, if it exists. But you must prove that you found the correct limit, or prove that the series is divergent. Is the sequence \(\left\\{\frac{n}{n+1}\right\\}\) convergent? If so, what is the limit?

a) Prove that if \(\sum x_{n}\) and \(\sum y_{n}\) converge absolutely, then \(\sum x_{n} y_{n}\) converges absolutely. b) Find an explicit example where the converse does not hold. c) Find an explicit example where all three series are absolutely comvergent, are not just finite sums, and \(\left(\sum x_{n}\right)\left(\sum y_{n}\right) \neq \sum x_{n} y_{n} .\) That is, show that series are not multiplied term-by- term.

Suppose \(\left\\{x_{n}\right\\}\) is a bounded sequence, and \(\varepsilon>0\) is given. Prove that there exists an M such that for all \(k \geq M\) we have $$ x_{k}-\left(\limsup _{n \rightarrow \infty} x_{n}\right)<\varepsilon \quad \text { and } \quad\left(\liminf _{n \rightarrow \infty} x_{n}\right)-x_{k}<\varepsilon. $$

a) Prove that \(\lim n^{1 / n}=1 .\) Hint: Write \(n^{1 / n}=1+b_{n}\) and note \(b_{n}>0 .\) Then show that \(\left(1+b_{n}\right)^{n} \geq \frac{n(n-1)}{2} b_{n}^{2}\) and use this to show that \(\lim b_{n}=0 .\) b) Use the result of part a) to show that if \(\sum a_{n} x^{n}\) is a convergent power series with radius of convergence \(R\), then \(\sum n a_{n} x^{n}\) is also convergent with the same radius of convergence.

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