Chapter 1: Problem 4
Find two asymptotic power series for \(1 /(z+1)\) as \(z \rightarrow \infty\) based on the two asymptotic sequences $$ \left\\{z^{-2 n}\right\\} \text { and }\left\\{(-1)^{n} z^{-3 n}\right\\}, n=0,1, \ldots $$
Short Answer
Expert verified
The two asymptotic series are: \( \frac{1}{z} - \frac{1}{z^3} + \frac{1}{z^5} - \cdots \) and \( 1 - \frac{1}{z^3} + \frac{1}{z^6} - \cdots \).
Step by step solution
01
Understand the Function and the Goal
The function we are analyzing is \( f(z) = \frac{1}{z+1} \). We need to find two asymptotic power series as \( z \to \infty \) using two different sequences: \( \{z^{-2n}\} \) and \( \{(-1)^n z^{-3n}\} \). An asymptotic series approximates the behavior of a function as the variable approaches a limit.
02
Express the Function for Large z
For large \( z \), rewrite \( f(z) = \frac{1}{z+1} \) as \( \frac{1}{z(1+\frac{1}{z})} = \frac{1}{z} \frac{1}{1+\frac{1}{z}} \). Using the geometric series \( \frac{1}{1 - x} = 1 + x + x^2 + \cdots \) for \( x = -\frac{1}{z} \), the expression becomes \( \frac{1}{z}(1 - \frac{1}{z} + \frac{1}{z^2} - \cdots) \).
03
Applying the First Asymptotic Sequence \(\{z^{-2n}\}\)
Using \( \{z^{-2n}\} \), modulate terms by \( z^2 \) because the sequence suggests terms like \( z^{-2}, z^{-4}, \ldots \). Recognize \( \frac{1}{z+1} \approx \frac{1}{z} - \frac{1}{z^3} + \frac{1}{z^5} - \cdots \), thus primarily using odd powers of \( z^{-1} \) for this series.
04
Format the Series using \(\{z^{-2n}\}\)
The power series using \( \{z^{-2n}\} \) becomes: \[ \frac{1}{z} - \frac{1}{z^3} + \frac{1}{z^5} - \frac{1}{z^7} + \cdots \]
05
Applying the Second Asymptotic Sequence \(\{(-1)^n z^{-3n}\}\)
Now apply \( \{(-1)^n z^{-3n}\} \). Notice the periodicity and alternation introduced by \((-1)^n\). Rearrange the geometric expansion to fit: \( \frac{1}{z^0} \rightarrow (-1)^0, \frac{1}{z^3} \rightarrow (-1)^1, \frac{1}{z^6} \rightarrow (-1)^2,\ldots \). Thus, use powers that are multiples of 3.
06
Format the Series using \(\{(-1)^n z^{-3n}\}\)
The power series using \( \{(-1)^n z^{-3n}\} \) becomes: \[ 1 - \frac{1}{z^3} + \frac{1}{z^6} - \frac{1}{z^9} + \cdots \]
07
Finalize the Two Asymptotic Series
We have derived two asymptotic power series as \( z \to \infty \):1. Using \( \{z^{-2n}\} \): \( \frac{1}{z} - \frac{1}{z^3} + \frac{1}{z^5} - \cdots \).2. Using \( \{(-1)^n z^{-3n}\} \): \( 1 - \frac{1}{z^3} + \frac{1}{z^6} - \cdots \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Asymptotic Series
An asymptotic series is a series of functions that approximates another function as the input approaches a specific limit, like infinity. They are helpful if you want a simpler form to understand a complex function's behavior
as the variable grows very large. The key here is that instead of matching the original function,an asymptotic series aims to provide a closely matching set of terms.
as the variable grows very large. The key here is that instead of matching the original function,an asymptotic series aims to provide a closely matching set of terms.
- It's not always convergent, meaning the series might not sum to the original function, especially after a certain number of terms.
- It's very useful in practical applications where exact solutions are difficult or impossible to attain.
- When using in calculations, generally, only the first few terms are used, as these provide a close approximation of the function's behavior.
Power Series
A power series is an infinite series in terms of powers of a variable. It's akin to a polynomial with infinitely many terms, used to express functions more flexibly. For instance, we often see power series like:\[ a_0 + a_1 z + a_2 z^2 + a_3 z^3 + \cdots \]Here are a few critical aspects:
- Power series are useful for representing a broad array of functions and are pivotal in calculus and mathematical analysis.
- The more terms included, the closer the approximation to the actual function.
- Convergence depends on the point where the series is evaluated, governing how close the series sums to the intended function.
Geometric Series
A geometric series is a series where each term is a fixed multiple of the previous one. This type is a bit simpler than the power series but incredibly useful in approximations.The general form is:\[ a + ar + ar^2 + ar^3 + ar^4 + \cdots \]where \(a\) is the first term, and \(r\) is the common ratio:
- If \(|r| < 1\), the series converges to \(\frac{a}{1-r}\).
- Used most simply in finance, physics, and numerous real-life applications, it's a foundation for understanding regular growth processes.