Chapter 9: Problem 2
Suppose that of 1000 customers surveyed, 850 are satisfied or very satisfied with a corporation's products and services. a. Test the hypothesis \(H_{0}: p=0.9\) against \(H_{1}: p \neq 0.9\) at \(\alpha=0.05 .\) Find the \(P\) -value. b. Explain how the question in part (a) could be answered by constructing a \(95 \%\) two-sided confidence interval for \(p\).
Short Answer
Step by step solution
Define the Null and Alternative Hypotheses
Calculate Sample Proportion
Compute Standard Error
Calculate Test Statistic
Determine P-value
Construct a 95% Confidence Interval
Interpretation of Confidence Interval
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sample Proportion
- \( x \) is the number of successes (satisfied customers, which is 850 in this case), and
- \( n \) is the total number of trials or observations (1000 customers surveyed).
Standard Error
- \( p \) = 0.9 (the hypothesized true population proportion), and
- \( n \) = 1000 (total surveyed population).
Confidence Interval
- \( \hat{p} \) = 0.85 (sample proportion),
- \( z_{\alpha/2} \) = 1.96 (z-value from the standard normal distribution for 95% confidence), and
- \( SE \) = 0.0095 (from the previous calculation).
Test Statistic
- \( \hat{p} \) is the sample proportion (0.85),
- \( p \) is the hypothesized population proportion (0.9), and
- \( SE \) is the standard error (0.0095).