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An article in Proceedings of the \(33 \mathrm{rd}\) International ACM SIGIR Conference on Research and Development in Information Retrieval ["Understanding Web Browsing Behaviors Through Weibull Analysis of Dwell Time" \((2010,\) pp. \(379-386\) ) \(]\) proposed that a Weibull distribution can be used to model Web page dwell time (the length of time a Web visitor spends on a Web page). For a specific Web page, the shape and scale parameters are 1 and 300 seconds, respectively. Determine the following: a. Mean and variance of dwell time b. Probability that a Web user spends more than 4 minutes on this Web page c. Dwell time exceeded with probability 0.25

Short Answer

Expert verified
Mean: 300 seconds; Variance: 90000; Probability: 0.4493; Exceeded time: ~415.889 seconds.

Step by step solution

01

Weibull Mean Calculation

The mean of a Weibull distribution is given by \( \mu = \eta \Gamma(1 + 1/k) \), where \( \eta \) is the scale parameter, \( k \) is the shape parameter, and \( \Gamma \) is the Gamma function. Here, \( \eta = 300 \) and \( k = 1 \), so \( \mu = 300 \times \Gamma(2) = 300 \times 1 = 300 \).
02

Weibull Variance Calculation

The variance of a Weibull distribution is \( \sigma^2 = \eta^2 \left[ \Gamma(1 + 2/k) - \Gamma^2(1 + 1/k) \right] \). With \( k = 1 \), we have \( \sigma^2 = 300^2 \left[ 2 - 1^2 \right] = 300^2 = 90000 \).
03

Convert Minutes to Seconds for Probability

Calculate the time in seconds for 4 minutes to align with the scale parameter given in seconds. Therefore, 4 minutes is \( 4 \times 60 = 240 \) seconds. This will be used as the value \( t \) in the probability calculation.
04

Probability Calculation for More Than 4 Minutes

The probability that a web user spends more than a certain time \( t \) is given by the survival function: \( P(T > t) = e^{-(t / \eta)^k} \). Substitute \( t = 240 \), \( \eta = 300 \), and \( k = 1 \): \( P(T > 240) = e^{-(240/300)^1} = e^{-0.8} \approx 0.4493 \).
05

Exceeding Time for Probability 0.25

The time \( t \) exceeded with a probability of \( 0.25 \) is given by solving the equation \( P(T > t) = 0.25 \), which is equivalent to \( e^{-(t/\eta)^k} = 0.25 \). Solving for \( t \) gives \( -(t/300) = \ln(0.25) \), or \( t = -300 \ln(0.25) \approx 415.887 \) seconds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gamma Function
The Gamma function is a crucial concept in statistics, often denoted as \( \Gamma(n) \), and is an extension of factorial function to real and complex numbers. Where regular factorial \( n! \) applies to positive integers, the Gamma function is defined for all real and complex numbers except the negative integers.
For any positive integer \( n \), \( \Gamma(n) = (n-1)! \) demonstrates this connection. In calculations involving the Weibull distribution, the primary role of the Gamma function is to determine means and variances, especially when the shape parameter \( k \) is other than 1.
In our Weibull distribution problem, \( k = 1 \), the Gamma function simplifies to \( \Gamma(2) = 1 \), aligning with \( 1! \). This aid simplifies statistical models across varied disciplines, including survival analysis and risk modeling.
Probability Calculations
Probability calculations can determine how likely an event is to occur using statistical models like the Weibull distribution. In our example, to find the likelihood that a web user spends more than a certain time on a webpage, we employ the survival function; it's crucial when interest lies in 'time until event' scenarios.
The exercise asks for the probability that the user spends more than 4 minutes (240 seconds). By converting minutes to seconds, we align units with those given in the distribution's scale parameter. Calculating \( P(T > 240) \) involves the exponential function, yielding \( e^{-0.8} \) or approximately 0.4493. This means there is around a 44.93% chance that a user will spend more than 240 seconds on the page.
Statistical Modeling
Statistical modeling is a process used to predict future events or understand existing patterns based on data. The Weibull distribution is a versatile tool in these models, especially when analyzing lifespan or duration data, such as time spent on web pages. In our exercise, the Weibull distribution is applied to model web dwell time.
This statistical modeling can determine not only averages and variances but can also help businesses optimize user experience by predicting user engagement levels. This application in web browsing is significant because it guides design improvements that can enhance user interaction.
  • The shape parameter \( k \) determines the distribution curve type: below 1 indicates a decreasing event rate, equal to 1 indicates a constant event rate, and above 1 indicates an increasing event rate.
  • The scale parameter \( \eta \) defines the distribution's scale, which directly affects the spread of the data.
Survival Function
The survival function, denoted as \( S(t) \, or \, P(T > t) \), calculates the probability that a random variable exceeds a certain threshold, valuable in various fields like engineering, biology, and internet analytics, for assessing reliability or durations.
This function is essential in the problem of web browsing and the Weibull distribution. Here, the survival function represents the probability a user remains on the page past a certain time—4 minutes for this exercise. The equation \( S(t) = e^{-(t/\eta)^k} \) calculates this, reflecting a 44.93% probability of user dwell time exceeding 240 seconds.
Additionally, solving for \( t \) when the survival probability \( S(t) \) is 0.25, helps determine the time users are likely to stay, up to which 75% of users will remain. In this case, \( t \approx 415.887 \) seconds, indicating tailored content insights crucial for strategic web development.

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