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Suppose that \(f(x)=e^{-x}\) for \(0

Short Answer

Expert verified
a. \( e^{-1} \); b. \( e^{-1} - e^{-2.5} \); c. 0; d. \( 1 - e^{-4} \); e. \( e^{-3} \); f. \( -\ln(0.10) \); g. \( -\ln(0.90) \).

Step by step solution

01

Understand the Function

Begin by understanding that the given function \( f(x) = e^{-x} \) for \( x > 0 \) represents the PDF of an exponential distribution where the rate parameter is \( \lambda = 1 \). This can be used to find cumulative probabilities and other properties associated with exponential distributions.
02

Solve for Part a: P(1 < X)

For the exponential distribution, \( P(X > a) = 1 - F(a) \), where \( F(x) = 1 - e^{-x} \) is the CDF. Thus, \( P(1 < X) = 1 - F(1) = 1 - (1 - e^{-1}) = e^{-1} \).
03

Solve for Part b: P(1 < X < 2.5)

Using the CDF, \( P(1 < X < 2.5) = F(2.5) - F(1) = (1 - e^{-2.5}) - (1 - e^{-1}) = e^{-1} - e^{-2.5} \).
04

Solve for Part c: P(X = 3)

For continuous distributions like this exponential distribution, \( P(X = x) = 0 \) for any specific \( x \). Thus, \( P(X = 3) = 0 \).
05

Solve for Part d: P(X < 4)

For the CDF, \( P(X < 4) = F(4) = 1 - e^{-4} \).
06

Solve for Part e: P(3 \leq X)

Since \( P(X \geq 3) \) and \( P(X > 3) \) are the same for continuous distributions, \( P(3 \leq X) = 1 - F(3) = e^{-3} \).
07

Solve for Part f: Find x such that P(x < X) = 0.10

We require \( 1 - F(x) = 0.10 \) so \( F(x) = 0.90 \). Solving \( 1 - e^{-x} = 0.90 \), we get \( e^{-x} = 0.10 \). Taking natural logs gives \( x = -\ln(0.10) \).
08

Solve for Part g: Find x such that P(X \leq x) = 0.10

This is equivalent to solving \( F(x) = 0.10 \), which means \( 1 - e^{-x} = 0.10 \). Therefore, \( e^{-x} = 0.90 \) and by taking natural logs, we find \( x = -\ln(0.90) \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a mathematical concept used to determine the likelihood of events occurring. It's significant when dealing with random phenomena like rolling dice or choosing a card from a deck. For any event, whether it's simple or complex, probabilities range between 0 and 1. - A probability of 0 means the event will not happen. - A probability of 1 means the event will definitely occur. For continuous probability distributions, like the exponential distribution, probabilities for exact points are zero because there are infinitely many possible values within any interval. Instead, we talk about the probability of a variable falling within a range of values. For instance, in an exponential distribution, you might be asked to find the probability that a variable exceeds a certain value, like in the problem, "Find P(1 < X)".
Cumulative Distribution Function
The Cumulative Distribution Function (CDF) is a fundamental tool in probability and statistics. The CDF of a random variable, like in our exponential distribution example, provides the probability that the variable will take a value less than or equal to a certain number.For an exponential distribution, the CDF is \[ F(x) = 1 - e^{-x} \] This function grows from 0 to 1 as x moves from 0 towards infinity, reflecting increasing certainty that the variable will be less than or within the value of x.The CDF can be used to solve various problems, such as finding the probability that a variable lies within an interval. This involves computing differences between two CDF values. Additionally, you can rearrange the CDF equation to find specific values of x corresponding to a particular probability.
Continuous Distribution
Continuous distributions differ from discrete distributions by involving random variables that can take on any value within a certain range. Unlike discrete variables that have a finite set of outcomes, continuous variables can assume an infinite number of possible values. One hallmark of continuous distributions, like the exponential distribution, is that the probability at any specific point is zero. Hence, when working with continuous data, we always consider probabilities over an interval, not at a point.Another feature is that continuous distributions have probability density functions (PDFs) instead of simple probabilities for individual points. For example, the exponential distribution's PDF is \( f(x) = e^{-x} \) for \( x > 0 \), which helps define the shape and spread of the distribution.
Exponential Function
The exponential function forms the backbone of the exponential distribution and is key in modeling various processes such as radioactive decay or the time until an event occurs. An exponential function in mathematics typically takes the form \(e^{kx}\), where \( e \) is the base of natural logarithms, and \( k \) is a constant.For the exponential distribution, the PDF is represented as\[ f(x) = e^{-x} \] The negative exponent indicates decay, thereby modeling processes where events occur continuously and independently at a constant average rate.This function is critical in calculating probabilities with the associated CDF, \( F(x) = 1 - e^{-x} \). Understanding the behavior and properties of exponential functions is crucial for grasping how continuous random variables behave over time or space.

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