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If the range of \(X\) is the set \\{0,1,2,3,4\\} and \(P(X=x)=0.2,\) determine the mean and variance of the random variable.

Short Answer

Expert verified
The mean is 2.0 and the variance is 2.0.

Step by step solution

01

Verify the Probability Distribution

The range of the random variable \(X\) is \(\{0, 1, 2, 3, 4\}\). Each value \(x\) has a probability \(P(X=x) = 0.2\). First, confirm that these probabilities add up to 1. Since there are 5 values and each has a probability of 0.2, the sum is \(0.2 \times 5 = 1.0\), which confirms this is a valid probability distribution.
02

Calculate the Mean

The mean of a discrete random variable is calculated using the formula \( \mu = \sum (x_i \cdot P(X=x_i)) \). For this problem, the calculation is as follows: \[ \mu = (0 \times 0.2) + (1 \times 0.2) + (2 \times 0.2) + (3 \times 0.2) + (4 \times 0.2) \]. Simplifying this, we get \[ \mu = 0 + 0.2 + 0.4 + 0.6 + 0.8 = 2.0 \]. Therefore, the mean is 2.0.
03

Calculate the Variance

The variance of a discrete random variable is calculated using the formula \( \sigma^2 = \sum ((x_i - \mu)^2 \cdot P(X=x_i)) \). With \( \mu = 2.0 \), the calculation is: \[ \sigma^2 = ((0-2)^2 \times 0.2) + ((1-2)^2 \times 0.2) + ((2-2)^2 \times 0.2) + ((3-2)^2 \times 0.2) + ((4-2)^2 \times 0.2) \]. Simplifying, we have: \[ \sigma^2 = (4 \times 0.2) + (1 \times 0.2) + (0 \times 0.2) + (1 \times 0.2) + (4 \times 0.2) = 0.8 + 0.2 + 0 + 0.2 + 0.8 = 2.0 \]. Therefore, the variance is 2.0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean of a Discrete Random Variable
The mean of a discrete random variable, often denoted by \( \mu \), can be thought of as the "center of gravity" of the probability distribution. It provides a measure of the central tendency, or the average value, of the variable. To find the mean, you need to multiply each possible value of the random variable by its probability and then sum up all these products. This can be represented by the formula:
  • \( \mu = \sum (x_i \cdot P(X=x_i)) \)

In our example, the random variable \( X \) has possible values \{0, 1, 2, 3, 4\}, each with a probability of 0.2. Therefore, the mean, or expected value, is calculated as follows:
  • \( \mu = (0 \times 0.2) + (1 \times 0.2) + (2 \times 0.2) + (3 \times 0.2) + (4 \times 0.2) \)
  • \( \mu = 0 + 0.2 + 0.4 + 0.6 + 0.8 = 2.0 \)

This tells us that, on average, the value of \( X \) is 2.0. This straightforward approach to finding the mean helps summarize the distribution's expected behavior.
Variance of a Discrete Random Variable
Variance is a crucial concept that measures the spread or variability of a data set. For a discrete random variable, variance indicates how much the values differ from the expected value (the mean). The formula to compute variance, denoted as \( \sigma^2 \), is:
  • \( \sigma^2 = \sum ((x_i - \mu)^2 \cdot P(X=x_i)) \)

Let's explain this step by step. You first subtract the mean \( \mu \) from each value \( x_i \) of the random variable, square the result to remove negative values, then multiply by the probability of that value. The final step is summing up these products to get the variance.
For our problem, with \( \mu = 2.0 \), this calculation goes as follows:
  • \( \sigma^2 = ((0-2)^2 \times 0.2) + ((1-2)^2 \times 0.2) + ((2-2)^2 \times 0.2) + ((3-2)^2 \times 0.2) + ((4-2)^2 \times 0.2) \)
  • \( \sigma^2 = (4 \times 0.2) + (1 \times 0.2) + (0 \times 0.2) + (1 \times 0.2) + (4 \times 0.2) = 2.0 \)

The resulting variance, 2.0, indicates the degree to which each number differs from the mean. A higher variance means the data points are spread out more widely.
Random Variables
Random variables play a fundamental role in probability and statistics. They are used as a way to quantify the outcomes of a random process. Essentially, a random variable assigns a numerical value to each event in a sample space. There are two types of random variables:
  • Discrete Random Variables: These take on a countable number of distinct values, like our example \(X\) that can be 0, 1, 2, 3, or 4.
  • Continuous Random Variables: These can take any real number value within a given range, like heights or weights.

In our exercise, we focused on a discrete random variable. It comes with a probability distribution that specifies the probability of each of its possible values. For the random variable \(X\) given, each value from the set has an equal chance of occurring, with \(P(X=x) = 0.2\).
A solid understanding of random variables is essential, as they are the foundation for more complex statistical concepts. They help create models to predict and infer data behavior, allowing us to deal with uncertainty in a quantifiable manner.

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Most popular questions from this chapter

SS An assembly consists of three mechanical components. Suppose that the probabilities that the first, second, and third components meet specifications are \(0.95,0.98,\) and \(0.99,\) respectively. Assume that the components are independent. Determine the probability mass function of the number of components in the assembly that meet specifications.

The number of cracks in a section of interstate highway that are significant enough to require repair is assumed to follow a Poisson distribution with a mean of two cracks per mile. a. What is the probability that there are no cracks that require repair in 5 miles of highway? b. What is the probability that at least one crack requires repair in \(1 / 2\) mile of highway? c. If the number of cracks is related to the vehicle load on the highway and some sections of the highway have a heavy load of vehicles whereas other sections carry a light load, what do you think about the assumption of a Poisson distribution for the number of cracks that require repair?

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For each of the following exercises, determine the range (possible values) of the random variable. A batch of 500 machined parts contains 10 that do not conform to customer requirements. Parts are selected successively, without replacement, until a nonconforming part is obtained. The random variable is the number of parts selected.

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