/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 A computer system uses passwords... [FREE SOLUTION] | 91Ó°ÊÓ

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A computer system uses passwords that contain exactly eight characters, and each character is one of 26 lowercase letters \((a-z)\) or 26 uppercase letters \((A-Z)\) or 10 integers \((0-9) .\) Let \(\Omega\) denote the set of all possible passwords, and let \(A\) and \(B\) denote the events that consist of passwords with only letters or only integers, respectively. Suppose that all passwords in \(\Omega\) are equally likely. Determine the probability of each of the following: a. \(A \quad\) b. \(B\) c. A password contains at least 1 integer. d. A password contains exactly 2 integers.

Short Answer

Expert verified
a: \(P(A) = \frac{52^8}{62^8}\), b: \(P(B) = \frac{10^8}{62^8}\), c: \(1 - \frac{52^8}{62^8}\), d: \(\frac{\binom{8}{2} \times 10^2 \times 52^6}{62^8}\).

Step by step solution

01

Calculate Total Possible Passwords

The total number of characters that can be used for each position in the password is the sum of lowercase letters, uppercase letters, and digits, which is \(26 + 26 + 10 = 62\). For a password with 8 characters, the total number of possible passwords is:\[ 62^8 \]
02

Calculate Probability of Event A (Only Letters)

For a password consisting only of letters, each character can be one of 52 possible options (26 lowercase + 26 uppercase letters). Therefore, the number of such passwords is:\[ 52^8 \]The probability of event \(A\) is the number of eight-character letter-only passwords divided by the total possible passwords:\[ P(A) = \frac{52^8}{64^8} \]
03

Calculate Probability of Event B (Only Integers)

For a password consisting only of integers, each character can be one of 10 digits. Therefore, the number of such passwords is:\[ 10^8 \]The probability of event \(B\) is the number of eight-digit-only passwords divided by the total possible passwords:\[ P(B) = \frac{10^8}{62^8} \]
04

Calculate Probability of Having at Least 1 Integer

The probability of having at least one integer can be calculated by finding the complement of the probability of having no integers (only letters). We have already calculated the probability of all letters in Step 2.The probability of at least one integer is:\[ P(\text{at least 1 integer}) = 1 - P(A) \]
05

Calculate Probability of Exactly 2 Integers

To calculate the probability of exactly 2 integers, we need to select 2 positions out of 8 for integers, which can be done in \(\binom{8}{2}\) ways. The 2 integer positions can each be filled in 10 ways (0-9), and the remaining 6 positions can each be filled in 52 ways (letters only).The number of such passwords is:\[ \binom{8}{2} \times 10^2 \times 52^6 \]The probability of exactly 2 integers is given by:\[ P(\text{exactly 2 integers}) = \frac{\binom{8}{2} \times 10^2 \times 52^6}{62^8} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a branch of mathematics that deals with counting, arranging, and grouping objects. It plays a crucial role in determining the number of possible combinations in various scenarios, such as creating passwords. In the exercise, combinatorics helps us find how many different eight-character passwords can be made using letters and digits.
When forming an eight-character password, each position can be filled by any of the 62 available characters (26 lowercase letters, 26 uppercase letters, and 10 digits). Hence, the total number of passwords can be computed by calculating the number of possibilities for each position using the formula:
  • \( 62^8 \)
This represents all the possible variations for eight-character passwords. Combinatorics also helps us calculate probabilities by understanding the number of specific outcomes, like the number of passwords that only contain letters or only contain digits. By using permutations and combinations, we can determine the number of ways to arrange or select items, which is key to finding the probability of different events.
Password Security
Password security is crucial in protecting sensitive information and ensuring data integrity. Understanding the different combinations of characters that can form passwords gives insights into their potential strength and resistance to hacking attempts. More varied characters in a password increase the difficulty for someone to guess or crack it.
In our exercise, knowing only 52 options for each character (letters only) versus all 62 available options (letters and digits) affects a password's security level. This variance is crucial because passwords that include all characters are harder to guess due to the higher number of possible combinations.
  • Using both letters and numbers increases complexity.
  • Unique, lengthy passwords are typically more secure.
As a general rule, mixing different types of characters (uppercase, lowercase, digits, special symbols) in a password exponentially increases its security. Understanding how combinatorics affect password creation can help in designing more robust password policies.
Probability Distribution
Probability distribution reflects how the probabilities of different outcomes are spread out across all possible events. In the context of creating passwords, it shows us how likely it is for a password to have only letters, only numbers, or a mix of both.
To calculate the probability of certain password configurations:
  • For event \(A\) (only letters), we calculate \( P(A) = \frac{52^8}{62^8} \).
  • For event \(B\) (only numbers), we compute \( P(B) = \frac{10^8}{62^8} \).
  • For at least one integer, we use the complement method: \( P(\text{at least 1 integer}) = 1 - P(A) \).
Each of these calculations gives insight into how often each type of password might appear given that each option is equally likely. Understanding probability distribution allows for predictions about which types of passwords will be more common or rare, helping to inform security policies and potential vulnerabilities.

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Most popular questions from this chapter

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