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Use the axioms of probability to show the following: a. For any event \(E, P\left(E^{\prime}\right)=1-P(E)\). b. \(P(\varnothing)=0\) c. If \(A\) is contained in \(B\), then \(P(A) \leq P(B)\).

Short Answer

Expert verified
The solutions are: a) \(P(E') = 1 - P(E)\), b) \(P(\varnothing) = 0\), c) \(P(A) \leq P(B)\).

Step by step solution

01

Understand the Axioms of Probability

The axioms of probability state that for any event \(E\), \(0 \leq P(E) \leq 1\) and that for the sample space \(S\), \(P(S) = 1\). If \(A_1, A_2, \dots\) are mutually exclusive events, then \(P(A_1 \cup A_2 \cup \dots) = P(A_1) + P(A_2) + \dots\). These axioms provide the foundation for solving each part of the problem.
02

Show that \(P(E') = 1 - P(E)\)

Since \(E\) and \(E'\) are complementary events, their union equals the sample space \(S\), so \(E \cup E' = S\). According to the axioms, \(P(S) = 1\). Additionally, \(E\) and \(E'\) are mutually exclusive, meaning \(P(E \cup E') = P(E) + P(E')\). Thus, \(1 = P(E) + P(E')\), which implies \(P(E') = 1 - P(E)\).
03

Show that \(P(\varnothing) = 0\)

The empty set \(\varnothing\) has no outcomes, so adding probabilities from an empty set results in \(0\) because there is nothing to add together. Specifically, since \(\varnothing\) and \(S\) are complementary and \(P(S) = 1\), \(P(\varnothing) + P(S) = 1\). Therefore, \(P(\varnothing) = 0\).
04

Show that \(P(A) \leq P(B)\) if \(A \subseteq B\)

If \(A\) is contained within \(B\), then \(B = A \cup (B \setminus A)\) where \(A\) and \(B \setminus A\) are mutually exclusive. Therefore, the axiom of additivity gives \(P(B) = P(A) + P(B \setminus A)\). Since probabilities are non-negative, \(P(B \setminus A) \geq 0\) and thus \(P(B) \geq P(A)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complementary Events
Complementary events are a fundamental concept in probability theory. When we say that two events, say event \(E\) and its complement \(E'\), are complementary, it means that together, they account for all possible outcomes of an experiment. In other words, either \(E\) happens or \(E'\) happens, but not both at the same time. For instance, if you flip a coin, the probability that it lands on heads is \(P(E)\) and the probability of tails, which is the complement, is \(P(E')\).

Understanding the relationship between these events is crucial. The axiom of complementary events states that the sum of their probabilities equals one. Mathematically, this is expressed as \(P(E) + P(E') = 1\). Therefore, to find the probability of the complement \(E'\), you simply take \(1 - P(E)\), which gives \(P(E') = 1 - P(E)\). This equation is incredibly useful for solving problems where you know the probability of an event and need to find its complement.

To visualize, think of complementary events as slices of a pie: together, they make a whole pie, which represents the sample space, or all possible outcomes together.
Mutually Exclusive Events
When discussing probability, the concept of mutually exclusive events is vitally important. Two or more events are mutually exclusive if the occurrence of one event means that none of the others can happen. An everyday example is when you roll a die: getting a 2 and getting a 3 are mutually exclusive events because the die cannot show both numbers at the same time.

The probability rule for mutually exclusive events is straightforward and essential: if \(A_1, A_2, \ldots\) are mutually exclusive events, then the probability of any one of these events occurring is the sum of their individual probabilities. Mathematically, this is represented as \(P(A_1 \cup A_2 \cup \dots) = P(A_1) + P(A_2) + \dots\). This rule allows us to easily compute the probability of one or another mutually exclusive event occurring.

It's important to note that mutually exclusive events cannot happen together. Therefore, if \(E\) and \(E'\) are mutually exclusive events—as complements usually are— then \(P(E \cap E') = 0\). This highlights that mutually exclusive events have no overlap.
Probability Inequality
The probability inequality is an integral concept when comparing the likelihood of different events. It involves understanding how the probabilities of certain events relate to one another. Specifically, if one event \(A\) is a subset of another event \(B\), this implies that whenever event \(A\) occurs, event \(B\) must also have occurred.

In terms of probability, this concept is crucial because it helps set constraints on probabilities. If \(A \subseteq B\), then by the axioms of probability, \(P(A) \leq P(B)\). This inequality makes intuitive sense: the probability of the smaller event can never exceed that of the larger event, as \(A\) can happen only when \(B\) does.

This principle is particularly useful in problem-solving, as it guides us when evaluating events. The concept of probability inequality thus allows us to understand and predict the range within which probabilities can fall, ensuring that probability estimations adhere to basic logical rules.

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Most popular questions from this chapter

Decide whether a discrete or continuous random variable is the best model for each of the following variables: a. The time until a projectile returns to earth. b. The number of times a transistor in a computer memory changes state in one operation. c. The volume of gasoline that is lost to evaporation during the filling of a gas tank. d. The outside diameter of a machined shaft.

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