Chapter 9: Problem 81
Consider the test of \(H_{0}: \sigma^{2}=5\) against \(H_{1}: \sigma^{2}<5 .\) Approximate the \(P\) -value for each of the following test statistics. (a) \(x_{0}^{2}=25.2\) and \(n=20\) (b) \(x_{0}^{2}=15.2\) and \(n=12\) (c) \(x_{0}^{2}=4.2\) and \(n=15\)
Short Answer
Expert verified
Calculate each \(P\)-value using chi-square distribution tables or software given the provided test statistics and sample sizes.
Step by step solution
01
Understand the Hypothesis Test
We are conducting a chi-square test for variance.The null hypothesis, \(H_0\), is that the variance \(\sigma^2 = 5\), and the alternative hypothesis, \(H_1\), is that \(\sigma^2 < 5\). We will use the critical value of the chi-square distribution to approximate the \(P\)-value.
02
Define the Chi-Square Statistic Formula
The chi-square statistic is computed as: \(\chi^2 = \frac{(n-1)s^2}{\sigma_0^2}\), where \(s^2\) is the sample variance and \(\sigma_0^2\) is the hypothesized population variance (5, in this case). Here, we have been provided test statistics \(x_0^2\) as 25.2, 15.2, and 4.2, for different sample sizes.
03
Identify the Degrees of Freedom
The degrees of freedom (df) are calculated as \(n-1\). We will compute df for each part of the problem:- For \(n=20\), df = 19.- For \(n=12\), df = 11.- For \(n=15\), df = 14.
04
Calculate P-Value for (a)
With \(x_0^2 = 25.2\), \(n = 20\), and df = 19:To find the \(P\)-value, we look at the right tail of the chi-square distribution. We look for the probability that a chi-square random variable with 19 degrees of freedom is greater than 25.2 using chi-square tables or software. This provides the \(P\)-value.
05
Calculate P-Value for (b)
With \(x_0^2 = 15.2\), \(n = 12\), and df = 11:Again, check the right tail of the chi-square distribution with df = 11 for a value of 15.2. This provides the \(P\)-value for part (b).
06
Calculate P-Value for (c)
With \(x_0^2 = 4.2\), \(n = 15\), and df = 14:Look for the probability in the left tail of the chi-square distribution with 14 degrees of freedom that corresponds to 4.2. This provides the \(P\)-value for part (c).
07
Interpret the P-Values
\(P\)-values help determine if we reject \(H_0\). A small \(P\)-value (usually \(< 0.05\)) indicates strong evidence against \(H_0\), so we reject it in favor of \(H_1\). Calculate \(P\)-values for each scenario using chi-square distribution tables or software, comparing them each to a significance level (e.g., 0.05).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Variance Hypothesis Testing
Variance hypothesis testing is a statistical method used to determine if there is a significant difference between a sample variance and a hypothesized population variance. It helps in assessing whether the variability observed in the sample data is due to chance or some significant effect.
In the given exercise, we are testing a hypothesis about the variance using a chi-square test. The null hypothesis (\( H_0 \) ) states that the population variance (\( \sigma^2 \) ) is equal to a specified value (5 in this case), while the alternative hypothesis (\( H_1 \) ) proposes the variance is less than this specified value. This is known as a one-sided test, aiming to detect a decrease in variance. Hypothesis testing for variance can reveal insights into the stability or consistency of a process or quality characteristic.
In the given exercise, we are testing a hypothesis about the variance using a chi-square test. The null hypothesis (\( H_0 \) ) states that the population variance (\( \sigma^2 \) ) is equal to a specified value (5 in this case), while the alternative hypothesis (\( H_1 \) ) proposes the variance is less than this specified value. This is known as a one-sided test, aiming to detect a decrease in variance. Hypothesis testing for variance can reveal insights into the stability or consistency of a process or quality characteristic.
- Null Hypothesis (\( H_0 \) ): States what is assumed to be true for the population variance.
- Alternative Hypothesis (\( H_1 \) ): Contradicts the null, suggesting a different variance.
- Statistical Inference: We use test statistics to decide whether the observed variance aligns with \( H_0 \) or supports \( H_1 \) .
Degrees of Freedom
Degrees of freedom (df) are an important concept in hypothesis testing that reflect the number of values in the final calculation of a statistic that are free to vary. In many statistical tests, including the chi-square test for variance, degrees of freedom are crucial for determining the distribution that applies to the test statistic.
For the chi-square test, the degrees of freedom are calculated as \( n-1 \) , where \( n \) is the sample size. This accounts for the fact that one parameter was estimated (the sample variance, \( s^2 \) , for example), and so we adjust for that by reducing the freedom typically by one.
For the chi-square test, the degrees of freedom are calculated as \( n-1 \) , where \( n \) is the sample size. This accounts for the fact that one parameter was estimated (the sample variance, \( s^2 \) , for example), and so we adjust for that by reducing the freedom typically by one.
- In part (a) of the exercise: \( df = 20 - 1 = 19 \)
- In part (b): \( df = 12 - 1 = 11 \)
- In part (c): \( df = 15 - 1 = 14 \)
Chi-Square Distribution
The chi-square distribution is a continuous distribution that is particularly useful in hypothesis testing concerning variances. It is used in the context of the chi-square test to analyze the goodness-of-fit of the observed data with the assumed distribution under the null hypothesis. This approach is primarily useful for testing hypotheses about the variance of a single population.
In this exercise, the chi-square distribution helps calculate test statistics, which, in combination with degrees of freedom, are used to find the P-values.
In this exercise, the chi-square distribution helps calculate test statistics, which, in combination with degrees of freedom, are used to find the P-values.
- Right-tailed Test: As variance increases, the chi-square statistic moves towards the right tail of the distribution.
- Left-tailed Test: If the test is to determine if variance decreases, as in the given problem, interest lies in the left tail.
- Shape: Varies with df; more degrees of freedom result in a wider and flatter distribution.
P-value Calculation
The P-value is a critical part of hypothesis testing, representing the probability of obtaining a test statistic equal to or more extreme than the one observed, under the assumption that the null hypothesis is true. A low P-value indicates that such an extreme result is unlikely under the null hypothesis, suggesting that the null may not hold.
In this exercise, we calculate the P-value for the given test statistics using the chi-square distribution. It's essential to know the degrees of freedom to select the correct chi-square distribution curve. For instance, with a test statistic of 25.2 and df of 19, we look in chi-square tables or algorithms to find this probability.
In this exercise, we calculate the P-value for the given test statistics using the chi-square distribution. It's essential to know the degrees of freedom to select the correct chi-square distribution curve. For instance, with a test statistic of 25.2 and df of 19, we look in chi-square tables or algorithms to find this probability.
- Interpretation: A P-value less than \( 0.05 \) commonly indicates significant results, leading to rejecting the null hypothesis.
- Exact Calculation: Typically done using statistical software or chi-square distribution tables.
- Critical Value: Comparison point that helps decide between retention or rejection of \( H_0 \) .