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A melting point test of \(n=10\) samples of a binder used in manufacturing a rocket propellant resulted in \(\bar{x}=154.2^{\circ} \mathrm{F}\). Assume that the melting point is normally distributed with \(\sigma=1.5^{\circ} \mathrm{F}\). (a) Test \(H_{0}: \mu=155\) versus \(H_{1}: \mu \neq 155\) using \(\alpha=0.01\). (b) What is the \(P\) -value for this test? (c) What is the \(\beta\) -error if the true mean is \(\mu=150 ?\) (d) What value of \(n\) would be required if we want \(\beta<0.1\) when \(\mu=150 ?\) Assume that \(\alpha=0.01\)

Short Answer

Expert verified
(a) Fail to reject \(H_0\). (b) \(P\)-value \(\approx 0.182\). (c) \(\beta \approx 1\). (d) \(n \approx 62\).

Step by step solution

01

State the Hypotheses

We are given the null hypothesis \( H_0: \mu = 155 \) and the alternative hypothesis \( H_1: \mu eq 155 \). This is a two-tailed test since the alternative hypothesis is testing for differences either above or below 155.
02

Determine the Test Statistic

To determine the test statistic for a normally distributed variable, use the formula for the Z-test statistic:\[z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}}\]Substitute the given values \(\bar{x} = 154.2\), \(\mu = 155\), \(\sigma = 1.5\), and \(n = 10\):\[z = \frac{154.2 - 155}{\frac{1.5}{\sqrt{10}}} = \frac{-0.8}{0.4743} \approx -1.687\]
03

Determine the Critical Z-Value

For a significance level \( \alpha = 0.01 \) and a two-tailed test, the critical Z-values are the percentiles that separate the bottom 0.5% and the top 0.5% of the normal distribution, which are approximately \( -2.576 \) and \( 2.576 \).
04

Make a Decision Regarding the Null Hypothesis

Compare the test statistic to the critical values. Since \( -2.576 < -1.687 < 2.576 \), we fail to reject the null hypothesis \( H_0 \). This means there is not enough evidence to suggest that the mean melting point differs from 155 at the 0.01 significance level.
05

Calculate the P-Value

The P-value is the probability that the test statistic will fall in the tail or tails of the distribution. For \( z = -1.687 \), the P-value is twice the area to the left of the test statistic. Using a Z-table or calculator, this area is approximately 0.091. Thus, the P-value is approximately 0.182.
06

Beta Error Calculation

To calculate \( \beta \), we need the true mean \( \mu' = 150 \). Calculate the Z-value corresponding to \( \mu' \):\[z = \frac{\mu' - \mu}{\frac{\sigma}{\sqrt{n}}} = \frac{150 - 155}{\frac{1.5}{\sqrt{10}}} = \frac{-5}{0.4743} \approx -10.544\]Calculate \( \beta \): since \( z < -2.576 \), \( \beta \approx 1 \), indicating a very high probability of not rejecting \( H_0 \) when \( \mu' = 150 \).
07

Determine Required Sample Size for a Given Beta

To find sample size \( n \) where \( \beta < 0.1 \) for \( \mu' = 150 \), equate the acceptance region's critical Z to the power:\[\beta = P( z < -z_{\alpha/2} - \frac{\Delta}{\frac{\sigma}{\sqrt{n}}} ) = 0.1 \]\(-1.28 = -2.576 - \frac{5}{1.5 / \sqrt{n}}\)Solving gives:\[\sqrt{n} = \frac{5}{1.5} \frac{1}{1.28 + 2.576} \approx 7.85\]\( n \approx 62 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Test
A Z-test is a statistical test used to determine whether two population means are different when the variances are known and the sample size is large. However, it can also be applied for smaller sample sizes under the assumption of a normal distribution, as seen in this exercise involving melting point analysis.

In our example, the Z-test helps in understanding if the average melting point of the samples differs significantly from the hypothesized mean of 155°F. By calculating a Z-test statistic, we compare the sample's mean to the hypothesized population mean, using the population standard deviation in the computation. This is done through the formula:
  • \( z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}} \)
This equation tells us how many standard deviations our sample mean is from the hypothesized population mean. In essence, the Z-test transforms the distribution of the sample mean to standard normal distribution, making it easier to calculate probabilities and critical values.
Two-Tailed Test
A two-tailed test examines whether a sample is significantly greater or less than a certain range or value, rather than focusing on a deviation in a single direction. Using a two-tailed test means we are checking for any possibility of deviation in both directions—above and below.

In the context of our melting point test, we have the null hypothesis that the true mean is exactly 155°F. The alternative hypothesis is that the true mean is not equal to 155°F, indicating the mean may be less than or greater than this. In a two-tailed test, such hypotheses allow us to look at both tails of the distribution.

Two critical Z-values are established for each tail of the distribution, corresponding to the selected significance level (\( \alpha = 0.01 \) results in critical values around +/-2.576 for this test). These critical values mark the boundary of the region where we would reject the null hypothesis, thus maintaining a balance in testing for deviation on either side.
Beta Error
Beta error, often denoted as \( \beta \), is the risk of incorrectly accepting the null hypothesis when it is false. This is also referred to as a Type II error. It is particularly important in hypothesis testing when determining how confident we want to be in detecting a real effect.

In the exercise, calculating beta error involves understanding the scenario where the true mean is 150°F, yet we wrongly fail to reject the hypothesis that it is 155°F. Based on our calculations and due to a small sample size and large effect difference, the beta error is extremely high, nearly 1. This indicates almost no power to detect this shift under current conditions.

Beta error shows the sensitivity of a test, and striving for a lower beta increases the power of the test. Typically, researchers aim for \( \beta \) levels lower than 0.2 (achieving a power of 0.8 or higher). Understanding and managing beta error is crucial for reliable statistical conclusions.
Sample Size Determination
Sample size determination is vital to achieving meaningful results in statistics. It ensures that a study has enough power to reliably detect an effect, if one exists. In hypothesis testing, increasing sample size decreases the margin of error and increases the power of the test (reducing '\( \beta \)').

In this exercise, to ensure \( \beta < 0.1 \) for the true mean of 150°F, the sample size calculation uses critical values from the Z-table and differences in hypothesized and true means. The formula set up to find required sample size \( n \) is derived from rearranging the formula for power (1-\( \beta \)).
  • \( \sqrt{n} = \frac{\Delta}{\frac{\sigma}{\sqrt{Z_{\alpha/2} + Z_{1-\beta}}}} \)
  • \( \Delta \) is the difference between the true mean and the hypothesized mean, i.e., 5°F.
The calculations reveal that approximately 62 samples are necessary to potentially reduce beta error to acceptable limits, showing how adequately powered sample size improves the reliability of results in hypothesis testing.

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