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Let \(X\) be a binomial random variable with \(p=0.25\) and \(n=3\). Determine the probability distribution of the random variable \(Y=X^{2}\)

Short Answer

Expert verified
The probability distribution of \(Y\) is \([0.421875, 0.421875, 0.140625, 0.015625]\) for \(Y = 0, 1, 4, 9\).

Step by step solution

01

Understand the Binomial Distribution

A binomial random variable \(X\) with parameters \(n = 3\) and \(p = 0.25\) represents the number of successes in 3 independent trials, each with a success probability of 0.25. The values \(X\) can take are 0, 1, 2, and 3.
02

Calculate Individual Probabilities for X

Use the binomial probability formula \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \) to calculate the probabilities for \(X = 0, 1, 2, 3\). For \(X = 0\): \(P(X=0) = \binom{3}{0} (0.25)^0 (0.75)^3 = 0.421875\)For \(X = 1\): \(P(X=1) = \binom{3}{1} (0.25)^1 (0.75)^2 = 0.421875\)For \(X = 2\): \(P(X=2) = \binom{3}{2} (0.25)^2 (0.75)^1 = 0.140625\)For \(X = 3\): \(P(X=3) = \binom{3}{3} (0.25)^3 (0.75)^0 = 0.015625\).
03

Define the Transformation Y = X^2

The transformation \(Y = X^2\) maps possible values of \(X\) to \(Y\). Compute \(Y\) for each value of \(X\): \(Y = 0\) if \(X = 0\), \(Y = 1\) if \(X = 1\), \(Y = 4\) if \(X = 2\), \(Y = 9\) if \(X = 3\). This gives \(Y\) possible values: 0, 1, 4, and 9.
04

Determine the Probability Distribution of Y

For \(Y = 0\), it occurs when \(X = 0\): \(P(Y=0) = P(X=0) = 0.421875\).For \(Y = 1\), it occurs when \(X = 1\): \(P(Y=1) = P(X=1) = 0.421875\).For \(Y = 4\), it occurs when \(X = 2\): \(P(Y=4) = P(X=2) = 0.140625\).For \(Y = 9\), it occurs when \(X = 3\): \(P(Y=9) = P(X=3) = 0.015625\).Thus, the probability distribution of \(Y\) is :- \(P(Y=0) = 0.421875\)- \(P(Y=1) = 0.421875\)- \(P(Y=4) = 0.140625\)- \(P(Y=9) = 0.015625\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
In statistics, a probability distribution describes how the values of a random variable are distributed. It provides the possible values the random variable can take, along with their associated probabilities.

In this exercise, we're dealing with a discrete random variable, namely the square of a binomially distributed variable. A probability distribution gives us a clear view of where each value stands in terms of probability, showing us which outcomes are more or less likely.
  • Each outcome represents a potential realization of the variable.
  • The sum of all the probabilities should equal 1, since the variable must take on some value in the set defined by the distribution.
To illustrate, let's consider the probability distribution of the random variable \(Y = X^2\) derived from our exercise. We calculated the probabilities for \(Y=0\), \(Y=1\), \(Y=4\), and \(Y=9\) as follows:
  • \(P(Y=0) = 0.421875\)
  • \(P(Y=1) = 0.421875\)
  • \(P(Y=4) = 0.140625\)
  • \(P(Y=9) = 0.015625\)
These calculations indicate how likely each outcome is for this specific transformation of the binomial variable \(X\).
Random Variables
A random variable is a key concept in probability and statistics acting as a numerical description of the outcomes of a statistical experiment. When dealing with binomial distribution, like in this exercise, the random variable often represents the number of successes out of a fixed number of trials.

There are two types of random variables:
  • Discrete Random Variable: Takes on a finite number of values, like the outcome of rolling a die or flipping a coin.
  • Continuous Random Variable: Takes on an infinite number of values, often representing measurements. Examples include height or temperature.
Here, \(X\) is a discrete random variable representing the number of successes in three trials (a binomial scenario). The transformation \(Y = X^2\) still results in a discrete random variable but changes the potential outcomes.

Understanding how to work with random variables is crucial for interpreting both theoretical exercises and practical data analysis, as it allows you to predict and manage uncertainty in various situations.
Probability Theory
Probability theory is the branch of mathematics that deals with the analysis of random events. It provides the theoretical foundation for understanding and calculating the likelihood of events.

Key concepts in probability theory include:
  • Experiments: Any process that yields a random result. For example, flipping a coin or rolling a die.
  • Outcomes: The result of a single trial of an experiment.
  • Events: A collection of outcomes. If you roll a die, the event 'rolling an even number' includes the outcomes 2, 4, and 6.
  • Probability: The measure of how likely an event is to occur, often expressed as a number between 0 (impossible) and 1 (certain).
In this exercise, probability theory helps us to establish the likelihood of various outcomes for both \(X\) and \(Y = X^2\). By using formulas derived from probability theory, such as the binomial probability formula, we can compute these probabilities rigorously and confidently. This not only aids in understanding theoretical concepts but also in applying these principles to real-world problems.

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