/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 Suppose that the random variable... [FREE SOLUTION] | 91Ó°ÊÓ

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Suppose that the random variable \(X\) represents the length of a punched part in centimeters. Let \(Y\) be the length of the part in millimeters. If \(E(X)=5\) and \(V(X)=0.25,\) what are the mean and variance of \(Y ?\)

Short Answer

Expert verified
The mean of Y is 50, and the variance of Y is 25.

Step by step solution

01

Understand the relationship between X and Y

The random variable \(X\) is given in centimeters, and the random variable \(Y\) is given in millimeters. Since there are 10 millimeters for every centimeter, we have the relationship \(Y = 10X\).
02

Calculate the mean of Y

Given that \(E(X) = 5\), the expected value (or mean) of \(Y\), which is \(E(Y)\), can be calculated using the linear transformation property of expectation: \(E(Y) = E(10X) = 10E(X) = 10 \times 5 = 50\).
03

Calculate the variance of Y

We are given \(V(X) = 0.25\). To find \(V(Y)\), we use the property of variance for a linear transformation, which states \(V(aX) = a^2V(X)\). Therefore, \(V(Y) = V(10X) = (10^2)V(X) = 100 \times 0.25 = 25\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Variable Transformation
In probability and statistics, when we talk about random variable transformation, we are describing how the characteristics of a random variable change under different operations. In this example, the transformation involves converting measurements from centimeters to millimeters. This idea can be generalized to various types of transformations using a function.
  • For example, we are transforming the variable from the unit of centimeters (\(X\)) to millimeters (\(Y\)).
  • The transformation is achieved using the relationship \(Y = 10X\), reflecting the conversion ratio between centimeters and millimeters.
Understanding transformations is crucial because it preserves the essence of measurements while scaling or modifying the random variable. Converting to a different unit impacts how we interpret the data and calculate related statistical measures. Thus, knowing how to handle these transformations is core to statistical analysis.
Expected Value
The expected value, or mean, of a random variable signifies the central tendency or the average value. It is analogous to the "center of gravity" for a probability distribution. For a transformed random variable, the expected value calculates similarly.
  • Consider \(E(X) = 5\), which is the mean of the original variable \(X\).
  • For a transformation like \(Y = 10X\), the expected value is \(E(Y) = 10E(X)\).
This is due to the linearity of expectation, which allows scaling operations to be applied directly. By calculating \(E(Y) = 50\), we find the average length in millimeters. Expectation is linear, meaning even if \(X\) were a complex combination of variables, this property would still hold true. This principle simplifies many calculations in probability.
Variance Calculation
Variance quantifies the spread or dispersion of random variables in a dataset. It can be thought of as a measure of how much the values of a random variable deviate from its mean. Variance plays an important role when transforming random variables.
  • For the given example, the initial variance \(V(X) = 0.25\).
  • When transforming to \(Y = 10X\), you use \(V(Y) = (10^2) \cdot V(X)\).
This results in a new variance \(V(Y) = 25\). The multiplicative factor affects the variance by its square, meaning transformations greatly alter the spread of distribution, not just its center. Knowing how to compute variance under transformation ensures accurate analysis and interpretation of data in various units or scalings.

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