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The net weight in pounds of a packaged chemical herbicide is uniform for \(49.75

Short Answer

Expert verified
(a) Mean: 50, Variance: 0.0208; (b) CDF: \(F(x) = \frac{x - 49.75}{0.5}\) for \(49.75 \leq x \leq 50.25\); (c) \(P(X < 50.1) = 0.7\).

Step by step solution

01

Understanding the Uniform Distribution

Since the problem states that the weight is uniform for \(49.75 < x < 50.25\), this implies a continuous uniform distribution over the interval \([49.75, 50.25]\). The probability density function for a uniform distribution is constant between these bounds and zero elsewhere.
02

Calculating the Mean

For a uniformly distributed random variable on the interval \([a, b]\), the mean is given by \( \frac{a + b}{2} \). Here, \(a = 49.75\) and \(b = 50.25\), so the mean is \( \frac{49.75 + 50.25}{2} = 50 \).
03

Calculating the Variance

The variance of a uniformly distributed random variable on the interval \([a, b]\) is given by \( \frac{(b-a)^2}{12} \). Substituting \(a = 49.75\) and \(b = 50.25\), we have \( \frac{(50.25 - 49.75)^2}{12} = \frac{0.5^2}{12} = \frac{0.25}{12} = 0.0208 \).
04

Writing the Cumulative Distribution Function (CDF)

The cumulative distribution function for a uniform distribution on \([a, b]\) increases linearly from 0 to 1. For \(49.75 < x < 50.25\), the CDF is given by \( F(x) = \frac{x - a}{b - a} \). Substituting \(a = 49.75\) and \(b = 50.25\), we have \( F(x) = \frac{x - 49.75}{0.5} \) for \(49.75 \leq x \leq 50.25\).
05

Calculating Probability \(P(X < 50.1)\)

With the CDF determined, \(P(X < 50.1)\) is found using \( F(50.1) = \frac{50.1 - 49.75}{0.5} = \frac{0.35}{0.5} = 0.7 \). This means that there is a 70% chance a randomly chosen package weighs less than 50.1 pounds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Variance
When working with a uniform distribution, both the mean and variance offer insights into the expected average and the spread of data within a specific interval. For a continuous uniform distribution defined on the interval \(a, b\), the probability density function is constant, which suggests that every outcome in this range is equally likely.

To calculate the **mean** of a uniform distribution, you simply average the endpoints of the interval. The formula is \( \frac{a + b}{2} \). In this exercise, with \(a = 49.75\) and \(b = 50.25\), the mean becomes \( \frac{49.75 + 50.25}{2} = 50 \). This mean value represents the balance point, or center, of the distribution.

The **variance** measures how spread out the values are around the mean. For a uniform distribution, the variance is calculated using the formula \( \frac{(b-a)^2}{12} \). Here, the interval \(49.75, 50.25\) leads to a variance of \( \frac{(50.25 - 49.75)^2}{12} = 0.0208 \). Thus, you can expect a slight spread around the mean of 50 pounds.
Cumulative Distribution Function
The cumulative distribution function (CDF) of a uniform distribution provides insights into the probability that a random variable will be less than or equal to a certain value. It is particularly useful for understanding how probabilities accumulate over an interval.

For a uniform distribution over the interval \(a, b\), the CDF formula is \( F(x) = \frac{x - a}{b - a} \). This function transitions linearly from 0 at the start of the interval to 1 at the end. Specifically, within the range \(49.75 \leq x \leq 50.25\), the CDF can be expressed as \( F(x) = \frac{x - 49.75}{0.5} \).

This formulation allows one to determine the probability of observing a value below any specific point within the interval. By substituting different \(x\) values into this formula, you observe how the probability grows progressively larger as \(x\) approaches the upper bound.
Probability Calculation
Probability in the context of a uniform distribution is straightforward once the cumulative distribution function (CDF) is established. By using the CDF, you can find the likelihood of a random variable falling below a certain point.

For example, to compute \( P(X < 50.1) \), you utilize the CDF expression: \( F(x) = \frac{x - 49.75}{0.5} \). By inserting \(x = 50.1\) into this formula, the probability calculation becomes \( F(50.1) = \frac{50.1 - 49.75}{0.5} = 0.7 \).

This result, 0.7, signifies that there is a 70% chance that a randomly selected package weighs less than 50.1 pounds. This probability calculation exemplifies the practical application of the CDF in estimating the likelihood of outcomes within this distribution.

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