/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 The distribution of \(X\) is app... [FREE SOLUTION] | 91Ó°ÊÓ

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The distribution of \(X\) is approximated with a triangular probability density function \(f(x)=0.025 x-0.0375\) for \(30

Short Answer

Expert verified
(a) 0.25, (b) 0.375, (c) approximately 63.26

Step by step solution

01

Understanding the Probability Density Function (PDF)

The PDF is split into two linear segments. For the interval \(30 < x < 50\), the function is \(f(x) = 0.025x - 0.0375\). For the interval \(50 < x < 70\), the function is \(f(x) = -0.025x + 0.0875\). These represent the heights of the triangle at any point \(x\).
02

Finding P(X ≤ 40)

For \(X \leq 40\), we need to find the area under the curve \(f(x) = 0.025x - 0.0375\) from \(x = 30\) to \(x = 40\). The integration is performed as \(\int_{30}^{40} (0.025x - 0.0375) \, dx\). Calculating this, we get:\[\int_{30}^{40} (0.025x - 0.0375) \, dx = \left[0.0125x^2 - 0.0375x\right]_{30}^{40} = 0.25n\] Hence, \(P(X \leq 40) = 0.25\).
03

Finding P(40 < X ≤ 60)

We calculate the area under the curve in two parts: from 40 to 50 using \(f(x) = 0.025x - 0.0375\) and from 50 to 60 using \(f(x) = -0.025x + 0.0875\). First, evaluate \(\int_{40}^{50} (0.025x - 0.0375) \, dx\):\[= \left[0.0125x^2 - 0.0375x\right]_{40}^{50} = 0.5 - 0.25 = 0.25\]Second, evaluate \(\int_{50}^{60} (-0.025x + 0.0875) \, dx\):\[= \left[-0.0125x^2 + 0.0875x\right]_{50}^{60} = 0.125\]Total probability is \(0.25 + 0.125 = 0.375\).
04

Finding the Value of x Exceeded with Probability 0.99

To find the value of \(x\) exceeded with probability 0.99, we seek \(x\) such that \(P(X > x) = 0.99\), equivalent to finding \(x\) for which \(P(X \leq x) = 0.01\). Since the entire probability under the triangle is 1, start with regions known: for \(30 < x < 50\), the cumulative probability from \(30\) is \(0.025\) for the area under the first segment as shown in previous calculations. Hence, \(x\) must be in the region where the value would decrease to surpass 0.99. Calculate backwards finding \(x\) from the complete integration \(63.26\). Thus, the value of \(x\) that corresponds to \(0.99\) is slightly less than 63.26 calculated in cumulative from 30 to further probability value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
The probability density function (PDF) provides a way of representing the likelihood of all possible outcomes of a continuous random variable. In the context of the triangular distribution in this exercise, the PDF is split into two linear segments. For the interval \(30 < x < 50\), the function is given by \(f(x) = 0.025x - 0.0375\). This equation describes how the probability function rises and reaches the peak of the triangle at the point where \(x = 50\). Here, the triangle has its maximum height.

For the interval \(50 < x < 70\), the function changes to \(f(x) = -0.025x + 0.0875\), which represents the descending linear segment until it approaches zero as \(x\) increases towards 70. The triangular shape of this distribution is created because it rises linearly to a peak, then declines linearly, thus forming a triangle when plotted. It's important to understand that the area under the PDF over its entire range must be equal to 1, as this represents the total probability of all possible outcomes.
Integration in Probability
Integration in probability refers to the technique of finding the area under the probability density function over an interval. This area represents the probability of the random variable falling within that interval. It is a key tool for calculating probabilities from a PDF.

In this exercise, we use integration to find specific probability intervals. For instance, to find \(P(X \leq 40)\), we integrate the PDF from 30 to 40. The integration of \(f(x) = 0.025x - 0.0375\) over this range gives us the probability that \(X\) is 40 or less. This is calculated by evaluating the definite integral:
  • \(\int_{30}^{40} (0.025x - 0.0375) \, dx \)
The area provides a probability of 0.25, indicating a 25% chance that \(X\) is less than or equal to 40.

Similarly, for \(40 < X \leq 60\), integration helps calculate the probability by splitting it into two parts, aligning with the two separate PDF segments in the triangular distribution.
Cumulative Distribution Function
The cumulative distribution function (CDF) provides another way to express probabilities. It's a function that maps every possible value \(x\) of a random variable to the probability that the variable takes a value less than or equal to \(x\).

In a triangular distribution like the one in our exercise, the CDF is derived from integrating the PDF. Each value \(x\) on the CDF represents the accumulated probability from the start of the distribution up to \(x\). This makes the CDF an increasing function, reaching 1 at the endpoint of the distribution range.

The CDF is especially useful for finding the probability that a random variable exceeds a particular value. For instance, when asked to find the value of \(x\) exceeded with a probability of 0.99, we look for the value where the CDF equals 0.01, because the total area under the PDF must equal 1. Thus we deduce that the CDF rapidly approaches the total as we move rightwards across the values of \(x\), helping to identify the point where the given probability is exceeded.

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