/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 Verify that the following functi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Verify that the following functions are probability mass functions, and determine the requested probabilities. \(f(x)=\frac{2 x+1}{25}, \quad x=0,1,2,3,4\) (a) \(P(X=4)\) (b) \(P(X \leq 1)\) (c) \(P(2 \leq X<4)\) (d) \(P(X>-10)\)

Short Answer

Expert verified
(a) \(\frac{9}{25}\), (b) \(\frac{4}{25}\), (c) \(\frac{12}{25}\), (d) 1.

Step by step solution

01

Verify PMF

To verify that a function is a probability mass function (PMF), the sum of probabilities for all possible values must be equal to 1. Calculate the sum: \[\sum_{x=0}^{4} f(x) = \sum_{x=0}^{4} \frac{2x+1}{25} = \frac{1}{25} (1 + 3 + 5 + 7 + 9) = \frac{25}{25} = 1.\] Thus, the function is a valid PMF.
02

Calculate P(X=4)

Using the given PMF, calculate the probability for \(X = 4\): \[f(4) = \frac{2 \times 4 + 1}{25} = \frac{9}{25}.\] Thus, \(P(X=4) = \frac{9}{25}\).
03

Calculate P(X \leq 1)

Calculate the probability for \(X \leq 1\): \[P(X \leq 1) = f(0) + f(1).\] First, calculate \(f(0)\): \[f(0) = \frac{2 \times 0 + 1}{25} = \frac{1}{25}\] and \(f(1)\): \[f(1) = \frac{2 \times 1 + 1}{25} = \frac{3}{25}.\] Thus, \[P(X \leq 1) = \frac{1}{25} + \frac{3}{25} = \frac{4}{25}.\]
04

Calculate P(2 \leq X < 4)

Calculate the probability for \(2 \leq X < 4\): \[P(2 \leq X < 4) = f(2) + f(3).\] First, calculate \(f(2)\): \[f(2) = \frac{2 \times 2 + 1}{25} = \frac{5}{25}\] and \(f(3)\): \[f(3) = \frac{2 \times 3 + 1}{25} = \frac{7}{25}.\] Thus, \[P(2 \leq X < 4) = \frac{5}{25} + \frac{7}{25} = \frac{12}{25}.\]
05

Calculate P(X > -10)

Since all possible outcomes (\(x = 0, 1, 2, 3, 4\)) are greater than -10, \[P(X > -10) = 1.\] The total probability is 1 because we verified it as a PMF in Step 1.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Discrete Random Variable
A discrete random variable is a fundamental concept in probability and statistics that represents a variable with a countable number of distinct outcomes. Imagine it like rolling a die; the outcome can only be one of the six integers (1, 2, 3, 4, 5, or 6). In the context of the given exercise, the random variable \(X\) is limited to the values 0, 1, 2, 3, and 4. Each of these values has a certain probability assigned by the function \(f(x) = \frac{2x+1}{25}\).

Discrete random variables are often analyzed using probability mass functions (PMFs). A PMF provides the probability that a discrete random variable is exactly equal to some value. This characteristic makes PMFs extremely useful in various applications such as quality control, risk assessment, and in optimizing business processes. Always remember, a discrete random variable deals with events that occur in distinct steps.
Probability Theory
Probability theory is the branch of mathematics concerned with analysis of random phenomena. The core idea here is to model uncertainty in a mathematically logical way. Events in probability theory are unpredictable in the short term, but fairly predictable in the long term when patterns emerge.

In our exercise, to understand how likely each outcome is, we use probability mass functions. For example, calculating \(P(X=4)\) means determining how likely it is that \(X\) equals 4. Probability theory not only helps us define these specific probabilities, but it also assists in understanding larger concepts like cumulative probabilities, independence, and expected values.

By verifying that the total sum of probabilities equals 1, we ensure the setup adheres to the laws of probability, indicating no outcome is overlooked and that probabilities are correctly distributed across all possibilities.
Probability Calculation
Probability calculation is the practical application of probability theory to determine the likelihood of different events. In the context of our problem, after confirming that the function \(f(x)\) behaves as a valid probability mass function, we use it to calculate specific probabilities. Such calculations can answer questions about distinct outcomes or ranges of values.

For instance, calculating \(P(X \leq 1)\) requires sum probabilities of \(f(0)\) and \(f(1)\). This is an example of determining cumulative probabilities, where you find the total probability for a range of outcomes. Similarly, the probability \(P(2 \leq X < 4)\) is calculated by adding \(f(2)\) and \(f(3)\), representing probabilities within a specified range.

These calculations help provide clear, quantitative insights into the likelihood of various scenarios, making them crucial for decision-making processes wherever uncertainty is present.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An electronic scale in an automated filling operation stops the manufacturing line after three underweight packages are detected. Suppose that the probability of an underweight package is 0.001 and each fill is independent. (a) What is the mean number of fills before the line is stopped? (b) What is the standard deviation of the number of fills before the line is stopped?

The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a mean of 0.02 failures per hour. (a) What is the probability that the instrument does not fail in an 8 -hour shift? (b) What is the probability of at least one failure in a 24 -hour day?

Suppose that \(X\) has a Poisson distribution with a mean of 0.4 . Determine the following probabilities: (a) \(P(X=0)\) (b) \(P(X \leq 2)\) (c) \(P(X=4)\) (d) \(P(X=8)\)

A total of 12 cells are replicated. Freshly synthesized DNA cannot be replicated again until mitosis is completed. Two control mechanisms have been identified \(-\) one positive and one negative- -that are used with equal probability. Assume that each cell independently uses a control mechanism. Determine the following probabilities. (a) All cells use a positive control mechanism. (b) Exactly half the cells use a positive control mechanism. (c) More than four but fewer than seven cells use a positive control mechanism.

A company performs inspection on shipments from suppliers to detect nonconforming products. Assume that a lot contains 1000 items and \(1 \%\) are nonconforming. What sample size is needed so that the probability of choosing at least one nonconforming item in the sample is at least \(0.90 ?\) Assume that the binomial approximation to the hypergeometric distribution is adequate.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.