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Consider a sequence of independent Bernoulli trials with \(p=0.2\). (a) What is the expected number of trials to obtain the first success? (b) After the eighth success occurs, what is the expected number of trials to obtain the ninth success?

Short Answer

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(a) 5 trials; (b) 5 additional trials.

Step by step solution

01

Understanding the Geometric Distribution

The sequence of independent Bernoulli trials follows a geometric distribution where the probability of success is given as \(p = 0.2\). The question asks us to find the expected number of trials needed to obtain the first success.
02

Calculating the Expected Value for First Success

For a geometric distribution with probability \(p\), the expected number of trials until the first success is given by \(E[X] = \frac{1}{p}\). Substituting the given \(p = 0.2\), we have \(E[X] = \frac{1}{0.2} = 5\). This means, on average, it will take 5 trials to observe the first success.
03

Understanding the Negative Binomial Distribution

To find the expected number of trials to obtain the ninth success after the eighth success, we can use the negative binomial distribution. This distribution models the number of trials needed to achieve a fixed number of successes, where each trial is independent and has a probability \(p\) of success.
04

Calculating the Additional Trials for Ninth Success

Once the eighth success has been achieved, we expect the next success (the ninth success) to happen in the same manner as a geometric distribution. Thus, the expected number of additional trials to achieve the next success is again \(\frac{1}{p}\). Therefore, the expected number of additional trials after the eighth success is \(5\), with \(p = 0.2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bernoulli Trials
Bernoulli trials are named after the Swiss mathematician Jacob Bernoulli. They represent experiments where each trial has only two possible outcomes: success or failure.
These trials are foundational in probability theory because they allow us to analyze real-world situations with clear-cut results, such as flipping a coin or rolling a die to achieve a certain outcome.
In the context of the problem, each trial has a fixed probability, denoted as \(p\), of achieving success, while the probability of failure is \(1-p\).
  • The trials are independent, which means the outcome of one trial does not affect the other.
  • Each trial has the same probability of success, ensuring consistency throughout the experiment.
Understanding Bernoulli trials is crucial when dealing with problems involving sequences of experiments, as they serve as the building blocks for more complex distributions like the geometric and negative binomial distributions.
Negative Binomial Distribution
The negative binomial distribution extends the concept of Bernoulli trials. It determines the probability of achieving a fixed number of successes, \(r\), in a sequence of independent Bernoulli trials, each with the probability \(p\) of success.
Unlike the geometric distribution, which focuses on the number of trials needed for the first success, the negative binomial deals with scenarios requiring multiple successes.
In the exercise, we are tasked with finding out how many extra trials are needed to secure the ninth success after the eighth has already occurred. This situation perfectly fits the negative binomial distribution framework, where the problem boils down to finding trials for just one more success.
  • The number of trials includes both successes and failures leading up to the final success.
  • The framework is adaptable to various real-life situations that involve repeated experiments and their successes.
Using this distribution helps handle more intricate problems that go beyond a single binary outcome.
Expected Value
Expected value is a fundamental concept in probability and statistics that provides a measure of the center of a distribution. It represents the average outcome we'd expect if we were to repeat an experiment many times.
For a single Bernoulli trial, calculating the expected value is straightforward. However, in the context of sequences like those found in geometric and negative binomial distributions, it becomes meaningful in determining the average number of trials needed to achieve success.
  • In a geometric distribution, the expected number of trials until the first success is calculated as \(E[X] = \frac{1}{p}\), exemplified by our given \(p = 0.2\), resulting in \(5\) trials.
  • Similarly, for negative binomial scenarios (like achieving the 9th success), once you have already achieved \(r-1\) successes, the expected additional trials required is still \(\frac{1}{p}\).
Applying expected value principles allows us to quantify and anticipate outcomes, providing valuable insight into probabilistic events. Understanding expected value empowers students to better predict outcomes and make informed decisions based on statistical expectations.

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