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For each of the following exercises, determine the range (possible values) of the random variable. Wood paneling can be ordered in thicknesses of 1 8, 1 4, or 3 8 inch. The random variable is the total thickness of paneling in two orders.

Short Answer

Expert verified
The range of the random variable is \(\frac{1}{4}\), \(\frac{3}{8}\), \(\frac{1}{2}\), \(\frac{5}{8}\), \(\frac{3}{4}\) inches.

Step by step solution

01

Identify the Possible Thickness Values for One Order

The possible values for the thickness of wood paneling in one order are \(\frac{1}{8}\), \(\frac{1}{4}\), and \(\frac{3}{8}\) inches.
02

Calculate Sum Combinations of Two Orders

For two orders, calculate all possible sums of thickness values. For example, ordering \(\frac{1}{8}\) inch twice results in a total thickness of \(\frac{1}{8} + \frac{1}{8} = \frac{2}{8} = \frac{1}{4}\) inch, ordering \(\frac{1}{8}\) and \(\frac{1}{4}\) results in \(\frac{1}{8} + \frac{1}{4} = \frac{3}{8}\), and so on. List all possible sum combinations.
03

List All Unique Thickness Sums

The unique sums you can get from two orders of paneling are: \(\frac{1}{4}\), \(\frac{3}{8}\), \(\frac{1}{2}\), \(\frac{5}{8}\), and \(\frac{3}{4}\) inches. These represent all the possible values for the total thickness of paneling across two orders.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Range of Random Variables
A random variable is essentially a numerical outcome of a random process or experiment. In our example about wood paneling, the random variable is the total thickness from two orders. To find the range of this random variable, we need to understand what values it can possibly take.

  • Start by listing individual possible outcomes for one order. We have \(\frac{1}{8}\), \(\frac{1}{4}\), and \(\frac{3}{8}\) inches.


Next, consider all combinations of two orders and their resulting totals. Adding these outcomes results in values like \(\frac{1}{8} + \frac{1}{8} = \frac{1}{4}\) and \(\frac{1}{8} + \frac{1}{4} = \frac{3}{8}\), and so forth.

Ultimately, the range consists of the summed unique thicknesses that can be obtained: \(\frac{1}{4}\), \(\frac{3}{8}\), \(\frac{1}{2}\), \(\frac{5}{8}\), and \(\frac{3}{4}\) inches.

By understanding all possible combinations, we define what the random variable's range can be, offering a complete picture of potential outcomes for the total panel thickness in this scenario.
Diving into Probability
Probability helps us predict how likely certain outcomes are when we perform random experiments, such as determining the totals of wood thickness.

In our wood paneling example, each thickness from one order has a distinct chance of occurring. To better comprehend probabilities, consider each unique sum (our random variable outcomes).

  • If each thickness has an equal chance of occurring, we count ways a specific thickness sum can be made and compare it to the total possible combinations.


For example, the probability of getting a total thickness of \(\frac{1}{4}\) is based on how many ways you can achieve that outcome divided by all possible thickness outcomes. Similarly, check for all other sums: \(\frac{3}{8}\), \(\frac{1}{2}\), \(\frac{5}{8}\), and so on.

Grasping probability allows us to understand which thickness totals are more or less likely, providing insight into the randomness of our scenario.
Exploring Combinatorics
Combinatorics, a field of mathematics, deals with combinations of objects and helps solve complex problems, such as determining thickness totals.

When ordering wood panels, you deal with combinations to find out all possible outcomes and pairings. Combinatorics teaches us how to combine objects (inches of thickness) in a systematic way.

  • For instance, determine all possible pairings of two orderings: (\(\frac{1}{8}, \frac{1}{8}\)), (\(\frac{1}{8}, \frac{1}{4}\)), and so forth.
  • This analysis leads to understanding all possible sums of wood thickness.


With combinatorics, break down a seemingly complex problem into manageable parts by analyzing it as an organized set of combinations that you calculate methodically.

In our wood panel example, itertools assist in systematically calculating combinations of potential thickness outcomes, enabling us to better evaluate the various configurations of total thickness resulting from two orders.

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Most popular questions from this chapter

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Suppose that \(X\) has a Poisson distribution with a mean of 0.4 . Determine the following probabilities: (a) \(P(X=0)\) (b) \(P(X \leq 2)\) (c) \(P(X=4)\) (d) \(P(X=8)\)

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