/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 122 Suppose that \(P(A \mid B)=0.2, ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that \(P(A \mid B)=0.2, P\left(A \mid B^{\prime}\right)=0.3,\) and \(P(B)=0.8 .\) What is \(P(A) ?\)

Short Answer

Expert verified
P(A) = 0.22

Step by step solution

01

Understanding Conditional Probability

We have two conditional probabilities given: \(P(A \mid B)\) which is the probability of event \(A\) occurring given that \(B\) has occurred, and \(P(A \mid B')\) which is the probability of \(A\) occurring given that \(B\) has not occurred. We also have \(P(B)\), the probability of \(B\). Our goal is to find the unconditional probability \(P(A)\).
02

Using the Law of Total Probability

The law of total probability tells us how to evaluate the probability of \(A\) in relation to \(B\) and \(B'\). It is given by the formula:\[ P(A) = P(A \cap B) + P(A \cap B') \]Using the definition of conditional probability, \(P(A \cap B) = P(A \mid B) P(B)\) and \(P(A \cap B') = P(A \mid B') P(B')\).
03

Calculate \(P(A \cap B)\)

Apply the definition of conditional probability:\[ P(A \cap B) = P(A \mid B) P(B) = 0.2 \times 0.8 = 0.16 \]
04

Calculate \(P(A \cap B')\)

First, find \(P(B')\) which is the complement of \(P(B)\):\[ P(B') = 1 - P(B) = 0.2 \]Now apply the definition of conditional probability:\[ P(A \cap B') = P(A \mid B') P(B') = 0.3 \times 0.2 = 0.06 \]
05

Compute \(P(A)\)

Now use the values obtained to find \(P(A)\):\[ P(A) = P(A \cap B) + P(A \cap B') = 0.16 + 0.06 = 0.22 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Total Probability
The Law of Total Probability is a fundamental principle in probability theory that helps us manage complex scenarios by breaking them down into simpler parts. This rule is particularly useful when you're dealing with conditional probabilities and you want to find the overall probability of an event.

If you have partitions of your sample space, this law allows you to evaluate the overall probability of an event by considering all possible ways the event can occur. In our exercise, the probability of event \(A\) is divided over two mutually exclusive scenarios: when \(B\) occurs and when \(B'\) (not \(B\)) occurs.

The formula for the Law of Total Probability is:
  • \[ P(A) = P(A \cap B) + P(A \cap B') \]
Using conditional probabilities, this becomes:
  • \[ P(A) = P(A \mid B) P(B) + P(A \mid B') P(B') \]
This law allows us to compute the probability of complex events by summing the probabilities from each portion of the sample space.
Unconditional Probability
Unconditional probability refers to the probability of an event occurring without any precondition or restriction. It's also known as marginal probability.

In our example, we're interested in finding the unconditional probability \(P(A)\), which represents the likelihood of event \(A\) occurring regardless of whether \(B\) happens or not.

Unconditional probability is foundational because it provides a comprehensive view of an event's likelihood in the absence of any other condition.

To find it, we used previously determined conditional probabilities \(P(A \mid B)\) and \(P(A \mid B')\) and the probability of \(B\), using the Law of Total Probability to piece together the complete picture:
  • \[ P(A) = 0.16 + 0.06 = 0.22 \]
Here, we added the probabilities from each scenario (\(B\) and \(B'\)) to get the unconditional probability.
Probability of Events
Probability of events refers to the likelihood or chance of an event happening. Probability evaluates how likely it is for a given event to occur out of all possible outcomes. Each event in a probability space has an associated probability value between 0 and 1, where 0 means the event cannot happen, and 1 means it certainly will happen.

The exercise we're discussing involves conditional probabilities as well as their use to derive other types of probabilities. The example given uses information about the event \(A\) with respect to another event \(B\) and its complement \(B'\).

Viewing probability through the lens of events:
  • Conditional Probability: Likelihood of an event given another event has occurred (e.g., \(P(A \mid B)\)).
  • Unconditional Probability: Overall likelihood of an event (e.g., \(P(A)\)).
Understanding how to compute these different probabilities empowers you to see how events happen and interact within a given sample space.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Web ad can be designed from four different colors, three font types, five font sizes, three images, and five text phrases. A specific design is randomly generated by the Web server when you visit the site. Let \(A\) denote the event that the design color is red, and let \(B\) denote the event that the font size is not the smallest one. Are \(A\) and \(B\) independent events? Explain why or why not.

A sample of two items is selected without replacement from a batch. Describe the (ordered) sample space for each of the following batches: (a) The batch contains the items \(\\{a, b, c, d\\}\). (b) The batch contains the items \(\\{a, b, c, d, e, f, g\\}\). (c) The batch contains 4 defective items and 20 good items. (d) The batch contains 1 defective item and 20 good items.

The edge roughness of slit paper products increases as knife blades wour, Only \(1 \%\) of products slit with ncw bladcs have rough edges, \(3 \%\) of products slit with blades of average sharpness exhibit roughness, and \(5 \%\) of products slit with worn bladcs cxhibit roughncss. If \(25 \%\) of the bladcs in manufacturing are ncw, \(60 \%\) are of average sharpncss, and \(15 \%\) are worn, what is the proportion of products that exhibit edge roughness?

A batch of 140 semiconductor chips is inspected by choosing a sample of 5 chips. Assume 10 of the chips do not conform to customer requirements. (a) How many different samples are possible? (b) How many samples of five contain exactly one nonconforming chip? (c) How many samples of five contain at least one nonconforming chip?

A manufacturing operation consists of 10 operations. However, five machining operations must be completed before any of the remaining five assembly operations can begin. Within each set of five, operations can be completed in any order. How many different production sequences are possible?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.