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91Ó°ÊÓ

Provide a reasonable description of the sample space for each of the random experiments in Exercises \(2-1\) to \(2-17\). There can be more than one acceptable interpretation of each experiment. Describe any assumptions you make. Each of three machined parts is classified as either above or below the target specification for the part.

Short Answer

Expert verified
The sample space has 8 outcomes: (A, A, A), (A, A, B), (A, B, A), (A, B, B), (B, A, A), (B, A, B), (B, B, A), (B, B, B).

Step by step solution

01

Understanding the Experiment

In this experiment, we have three machined parts, each of which can be classified into one of two categories: above the target specification or below the target specification. Our task is to identify all the possible outcomes of this classification process, which will constitute our sample space.
02

Identify Possible Outcomes for Each Part

Since each part can be either above (A) or below (B) the target specification, we identify the possible outcomes for a single part as either 'A' or 'B'.
03

Formulate Sample Space for Three Parts

For three parts, each having two possible outcomes, we need to consider all possible combinations. Using the basic principle of counting, for 3 parts and 2 outcomes each, we have a total of \(2^3 = 8\) outcomes. Thus, we list them as follows: (A, A, A), (A, A, B), (A, B, A), (A, B, B), (B, A, A), (B, A, B), (B, B, A), and (B, B, B).
04

Construct the Sample Space

The sample space \(S\) is the set of all these possible ordered triples: \[ S = \{(A, A, A), (A, A, B), (A, B, A), (A, B, B), (B, A, A), (B, A, B), (B, B, A), (B, B, B)\} \]. These represent all possible classification outcomes for the three parts.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Experiments
A random experiment is an action or process that leads to one of several possible outcomes, where the outcome is not predictable with certainty. The underlying principle is that each trial of the experiment has a well-defined set of outcomes. In our context, the random experiment involves inspecting three machined parts. Each of these parts will be classified as either above or below a certain target specification.

When conducting a random experiment, you cannot predict which part will be classified in which way beforehand. Therefore, all possibilities are taken into account to form a set known as the sample space. Random experiments are fundamental in probability because they provide the basis for uncertainty.
  • They involve unpredictable results.
  • All possible outcomes are enumerated.
  • In our exercise, classifying each part adds complexity due to multiple parts involved.
Classification Outcomes
Classification outcomes refer to the results obtained from a process where items are categorized based on certain criteria. In this exercise, each machined part is categorized as either above or below the target specification. These results are simple binary outcomes, labeled as 'A' for above and 'B' for below.

Understanding classification outcomes is crucial as they provide a structured way to organize the results of a random experiment. Here, for each part, there are only two possible outcomes; however, when dealing with multiple parts, one must consider all possible combinations of these binary outcomes. This forms the basis of listing out the entire sample space.

To easily manage and visualize outcomes, it's helpful to think in terms of ordered pairs or triples, where the sequence matters:
  • In a single part outcome, combinations are 'A' or 'B'.
  • Multiple parts lead to more complex outcome combinations, like (A, B, A).
Basic Principle of Counting
The basic principle of counting helps in determining the total possible number of outcomes for a series of events. It's a fundamental concept in probability and combinatorics.

In this scenario, each part can have 2 possible classifications: above or below specification. Therefore, when determining the total possible outcomes for three parts, we apply the basic principle of counting: multiply the number of outcomes for each event. For three parts:
  • First part: 2 possible outcomes
  • Second part: 2 possible outcomes
  • Third part: 2 possible outcomes
This multiplication gives us a total of \(2 \times 2 \times 2 = 2^3 = 8\) possible outcomes. These outcomes represent the sample space, where each set of three letters represents one of the 8 possible ways the parts can be classified.
Probability Theory
Probability theory is the mathematical framework that quantifies uncertainty and helps in predicting the likelihood of various outcomes. In this exercise, once the sample space is determined, probability theory can be applied to assess the likelihood of specific configurations, such as all parts being above specification.

For a simple probability calculation, each outcome in the sample space is considered equally likely due to the binary nature (either above or below). Thus, each of the 8 outcomes has a probability of \(\frac{1}{8}\), assuming there's no bias in the classification process.
  • Probability of (A, A, A): \(\frac{1}{8}\)
  • Probability of any specific outcome: \(\frac{1}{8}\)
Using this theory, more complex probability questions could be answered, such as the probability of at least one part being below specification. Probability theory not only helps in calculating these individual probabilities but also in understanding the overall experimental outcomes' uncertainty.

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Most popular questions from this chapter

In light-dependent photosynthesis, light quality refers to the wavelengths of light that are important. The wavelength of a sample of photosynthetically active radiations (PAR) is measured to the nearest nanometer. The red range is \(675-700\) \(\mathrm{nm}\) and the blue range is \(450-500 \mathrm{nm}\). Let \(A\) denote the event that PAR occurs in the red range, and let \(B\) denote the event that PAR occurs in the blue range. Describe the sample space and indicate each of the following events: (a) \(A\) (b) \(B\) (c) \(A \cap B\) (d) \(A \cup B\)

A computer system uses passwords that are exactly seven characters and each character is one of the 26 letters \((a-z)\) or 10 integers \((0-9)\). You maintain a password for this computer system. Let \(A\) denote the subset of passwords that begin with a vowel (either \(a, e, i, o,\) or \(u\) ) and let \(B\) denote the subset of passwords that end with an even number (either \(0,2,4,6,\) or 8 ). (a) Suppose a hacker selects a password at random. What is the probability that your password is selected? (b) Suppose a hacker knows that your password is in event \(A\) and selects a password at random from this subset. What is the probability that your password is selected? (c) Suppose a hacker knows that your password is in \(A\) and \(B\) and selects a password at random from this subset. What is the probability that your password is selected?

It is known that two defective copies of a commercial software program were erroneously sent to a shipping lot that now has a total of 75 copies of the program. A sample of copies will be selected from the lot without replacement. (a) If three copies of the software are inspected, determine the probability that exactly one of the defective copies will be found. (b) If three copies of the software are inspected, determine the probability that both defective copies will be found. (c) If 73 copies are inspected, determine the probability that both copies will be found. (Hint: Work with the copies that remain in the lot.)

A lot of 100 semiconductor chips contains 20 that are defective. (a) Two are selected, at random, without replacement, from the lot. Determine the probability that the second chip selected is defective. (b) Three are selected, at random, without replacement, from the lot. Determine the probability that all are defective.

A computer system uses passwords that contain exactly eight characters, and each character is one of the 26 lowercase letters \((a-z)\) or 26 uppercase letters \((A-Z)\) or 10 integers \((0-9)\). Let \(\Omega\) denote the set of all possible password, and let \(A\) and \(B\) denote the events that consist of passwords with only letters or only integers, respectively. Suppose that all passwords in \(\Omega\) are equally likely. Determine the following robabilities: (a) \(P\left(A \mid B^{\prime}\right)\) (b) \(P\left(A^{\prime} \cap B\right)\) (c) \(P\) (password contains exactly 2 integers given that it contains at least 1 integer)

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