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You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and the model sum of squares is 750 (a) What is the value of \(R^{2}\) for this model? (b) What is the adjusted \(R^{2}\) for this model? (c) What is the value of the \(F\) -statistic for testing the significance of regression? What conclusions would you draw about this model if \(\alpha=0.05 ?\) What if \(\alpha=0.01 ?\) (d) Suppose that you add a third regressor to the model and as a result, the model sum of squares is now \(785 .\) Does it seem to you that adding this factor has improved the model?

Short Answer

Expert verified
(a) \( R^2 = 0.75 \). (b) Adjusted \( R^2 \approx 0.7206 \). (c) \( F \approx 25.493 \), model is significant at both \( \alpha=0.05 \) and \( \alpha=0.01 \). (d) Adding third regressor increases \( R^2 \) from 0.75 to 0.785, potentially improving the model.

Step by step solution

01

Calculate R Squared

The formula to calculate the coefficient of determination \( R^2 \) is:\[ R^2 = \frac{\text{Model Sum of Squares}}{\text{Total Sum of Squares}} \]Given values:- Model Sum of Squares (MSS) = 750- Total Sum of Squares (TSS) = 1000Substituting in the values:\[ R^2 = \frac{750}{1000} = 0.75 \]So, the value of \( R^2 \) is 0.75.
02

Calculate Adjusted R Squared

The formula for adjusted \( R^2 \) is:\[ \text{Adjusted } R^2 = 1 - (1 - R^2) \times \frac{n-1}{n-p-1} \]where \( n \) is the number of observations (20), and \( p \) is the number of regressors (2).Substituting known values:\[ \text{Adjusted } R^2 = 1 - (1 - 0.75) \times \frac{20-1}{20-2-1} = 1 - 0.25 \times \frac{19}{17} \]\[ \text{Adjusted } R^2 = 1 - 0.25 \times 1.1176 \approx 1 - 0.2794 = 0.7206 \]The adjusted \( R^2 \) is approximately 0.7206.
03

Calculate F-statistic

The formula for the \( F \)-statistic is:\[ F = \frac{\text{Mean Square Regression}}{\text{Mean Square Error}} \]First, calculate Mean Square Regression (MSR) and Mean Square Error (MSE):- MSR = \( \frac{\text{Model Sum of Squares}}{p} = \frac{750}{2} = 375 \)Total number of observations is 20. So, degrees of freedom for error:- DF for error = \( n - p - 1 = 20 - 2 - 1 = 17 \)- Mean Squares Error (MSE) = \( \frac{\text{Residual Sum of Squares}}{17} \)Residual Sum of Squares is Total SS - Model SS:- Residual Sum of Squares (RSS) = 1000 - 750 = 250- Mean Square Error (MSE) = \( \frac{250}{17} \approx 14.7059 \)So, \( F \)-statistic is:\[ F = \frac{375}{14.7059} \approx 25.493 \]To determine significance, compare with critical value for \( F(2, 17) \) at \( \alpha = 0.05 \) and \( \alpha = 0.01 \). The model is likely significant as \( F \approx 25.493 \) is typically greater than critical values for common significance levels.
04

Evaluate Impact of Adding Third Regressor

After adding a third regressor, the new Model Sum of Squares (MSS) is 785. Calculate the change in \( R^2 \):Original \( R^2 \) = \( \frac{750}{1000} = 0.75 \)New \( R^2 \) = \( \frac{785}{1000} = 0.785 \)The \( R^2 \) increases from 0.75 to 0.785, indicating an improvement in model fit. However, this could also be due to adding more parameters, which always tends to increase \( R^2 \). Therefore, one should also consider adjusted \( R^2 \) to evaluate if the added complexity is justified. If adjusted \( R^2 \) does not increase, the new model may not be meaningfully better.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Determination
The Coefficient of Determination, denoted as \( R^2 \), is a key statistic in regression analysis. It indicates how well data fits a statistical model. In simpler terms, \( R^2 \) is a measure of how much of the variability in the dependent variable can be explained by the independent variables in the model.
For instance, when we calculated \( R^2 \) with a model sum of squares (MSS) of 750 and a total sum of squares (TSS) of 1000, the \( R^2 \) value came out to be 0.75. This means 75% of the variability in the dataset is explained by the model.
A higher \( R^2 \) value implies a better fit; however, a perfect \( R^2 \) does not guarantee an accurate model. Sometimes, a high \( R^2 \) can occur with overfitting, where more predictors than necessary are used, capturing noise rather than useful information.
It's essential to evaluate \( R^2 \) with caution, considering other model parameters as well.
Adjusted R-Squared
The Adjusted \( R^2 \) is an extended version of the \( R^2 \) metric that adjusts for the number of predictors in the model. Unlike \( R^2 \), which can sometimes misleadingly increase by just adding more regressors, Adjusted \( R^2 \) accounts for the number of predictors.
Its formula is:\[ \text{Adjusted } R^2 = 1 - (1 - R^2) \times \frac{n-1}{n-p-1} \]where \( n \) is the number of observations and \( p \) is the number of predictors.
In our exercise, with an \( R^2 \) of 0.75, 20 observations, and 2 regressors, the Adjusted \( R^2 \) was calculated to be approximately 0.7206.
This metric provides a more reliable statistic when comparing models because it considers both the fit and the number of variables used. A higher value of Adjusted \( R^2 \) indicates that the explained variation is due to meaningful factors, rather than an artifact of overfitting.
F-Statistic
The \( F \)-Statistic is used in regression analysis to determine whether the overall regression model is a good fit for the data. It tests the hypothesis that the regression coefficients are equal to zero, meaning they do not explain any variance.
The formula for the \( F \)-statistic is:\[ F = \frac{\text{Mean Square Regression}}{\text{Mean Square Error}} \]To calculate it, you need two components: Mean Square Regression (MSR) and Mean Square Error (MSE).
In our example, with an MSR of 375 and an MSE of approximately 14.7059, the \( F \)-statistic resulted in about 25.493.
An \( F \)-statistic like this, much larger than typical critical values at common significance levels (e.g., \( \alpha=0.05 \)), indicates that the regression model provides a significantly better fit than a model with no predictors. Hence, it suggests that at least some of the predictors are useful for explaining the variability in the dataset.
Model Evaluation
Evaluating a regression model involves analyzing key statistics to determine its effectiveness. This includes considering metrics such as \( R^2 \), Adjusted \( R^2 \), and the \( F \)-Statistic.
When adding a new predictor, it's tempting to look only at the \( R^2 \) value, which likely increased from 0.75 to 0.785 in our case. While this suggests a better fit, it's crucial to check the Adjusted \( R^2 \) too. If it does not increase proportionally or decreases, it might mean the new regressor does not add enough explanatory power and could represent mere noise.
Vital to model evaluation is recognizing overfitting. A model with too many predictors might fit the training data well but perform poorly on new, unseen data.
  • Always use a balance of metrics.
  • Cross-validate by using different datasets.
  • Consider simplicity alongside predictive accuracy.
These practices ensure a reliable and robust model.

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Most popular questions from this chapter

An article in Technometrics (1974, Vol. 16, pp. \(523-531\) ) considered the following stack-loss data from a plant oxidizing ammonia to nitric acid. Twenty-one daily responses of stack loss (the amount of ammonia escaping) were measured with air flow \(x_{1},\) temperature \(x_{2}\), and acid concentration \(x_{3}\). $$ \begin{aligned} y=& 42,37,37,28,18,18,19,20,15,14,14,13,11,12,8,7, \\ & 8,8,9,15,15 \\ x_{1}=& 80,80,75,62,62,62,62,62,58,58,58,58,58,58,50,50, \\ & 50,50,50,56,70 \\ x_{2}=& 27,27,25,24,22,23,24,24,23,18,18,17,18,19,18,18, \\ & 19,19,20,20,20 \\ x_{3}=& 89,88,90,87,87,87,93,93,87,80,89,88,82,93,89,86, \\ & 72,79,80,82,91 \end{aligned} $$ (a) Fit a linear regression model relating the results of the stack loss to the three regressor varilables. (b) Estimate \(\sigma^{2}\). (c) Find the standard error \(\operatorname{se}\left(\hat{\boldsymbol{\beta}}_{j}\right)\). (d) Use the model in part (a) to predict stack loss when \(x_{1}=60\), \(x_{2}=26,\) and \(x_{3}=85\)

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A regression model is to be developed for predicting the ability of soil to absorb chemical contaminants. Ten observations have been taken on a soil absorption index \((y)\) and two regressors: \(x_{1}=\) amount of extractable iron ore and \(x_{2}=\) amount of bauxite. We wish to fit the model \(y=\beta_{0}+\beta_{1} x_{1}+\beta_{2} x_{2}+\epsilon\). Some necessary quantities are: $$ \begin{aligned} \left(\mathbf{X}^{\prime} \mathbf{X}\right)^{-1} &=\left[\begin{array}{lll} 1.17991 & -7.30982 \mathrm{E}-3 & 7.3006 \mathrm{E}-4 \\ -7.30982 \mathrm{E}-3 & 7.9799 \mathrm{E}-5 & -1.23713 \mathrm{E}-4 \\ 7.3006 \mathrm{E}-4 & -1.23713 \mathrm{E}-4 & 4.6576 \mathrm{E}-4 \end{array}\right] \\ \mathbf{X}^{\prime} \mathbf{y} &=\left[\begin{array}{r} 220 \\ 36,768 \\ 9,965 \end{array}\right] \end{aligned} $$ (a) Estimate the regression coefficients in the model specified. (b) What is the predicted value of the absorption index \(y\) when \(x_{1}=200\) and \(x_{2}=50 ?\)

A sample of 25 observations is used to fit a regression model in seven variables. The estimate of \(\sigma^{2}\) for this full model is \(M S_{E}=10\). (a) A forward selection algorithm has put three of the original seven regressors in the model. The error sum of squares for the three-variable model is \(S S_{E}=300 .\) Based on \(C_{p}\), would you conclude that the three- variable model has any remaining bias? (b) After looking at the forward selection model in part (a), suppose you could add one more regressor to the model. This regressor will reduce the error sum of squares to \(275 .\) Will the addition of this variable improve the model? Why?

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