Chapter 9: Problem 91
A researcher claims that at least \(10 \%\) of all football helmets have manufacturing flaws that could potentially cause injury to the wearer. A sample of 200 helmets revealed that 16 helmets contained such defects. (a) Does this finding support the researcher's claim? Use \(\alpha=0.01 .\) Find the \(P\) -value. (b) Explain how the question in part (a) could be answered with a confidence interval.
Short Answer
Step by step solution
State the Hypotheses
Identify the Test Statistic
Calculate the Test Statistic
Find the P-value
Make a Decision
Explain with Confidence Interval
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Population Proportion
The population proportion is essentially a snapshot that tells you the overall prevalence of a certain feature—in this case, defects in helmets.
- If you're dealing with large numbers, like 200 helmets in a study, you'll calculate the sample proportion to make inferences about the larger population.
Z-test
- This is a one-sample Z-test because we are comparing the sample's proportion to a known value or a claim, not to another sample.
- The key formula used is:
\[Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}\]
In this formula, \(\hat{p}\) is the sample proportion (0.08), \(p_0\) is the hypothesized population proportion (0.10), and \(n\) is the sample size (200).
Confidence Interval
- \[\hat{p} \pm Z_{\alpha/2} \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\]
- Here, \(\hat{p}\) is the sample proportion, about 8% in our example, \(Z_{\alpha/2}\) is a critical value from the Z-table (for a confidence level of 99%, \(Z\approx 2.576\)), and \(n\) is the sample size.
P-value
- If the P-value is low (typically less than 0.05 or 0.01), this would suggest our observed results are quite unlikely under the null hypothesis, and we might reject it.
- Conversely, a high P-value suggests that the null hypothesis can hold, as seen here with 0.1736, which is greater than the 0.01 level. This outcome means sticking with the null—10% might be a plausible defect rate.