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91Ó°ÊÓ

A researcher claims that at least \(10 \%\) of all football helmets have manufacturing flaws that could potentially cause injury to the wearer. A sample of 200 helmets revealed that 16 helmets contained such defects. (a) Does this finding support the researcher's claim? Use \(\alpha=0.01 .\) Find the \(P\) -value. (b) Explain how the question in part (a) could be answered with a confidence interval.

Short Answer

Expert verified
The P-value is 0.1736; we do not reject the null hypothesis. The confidence interval (0.0469, 0.1131) supports this conclusion.

Step by step solution

01

State the Hypotheses

We are conducting a hypothesis test to evaluate a claim about a population proportion. Let \( p \) be the true proportion of helmets with defects.- Null hypothesis \( H_0: p \geq 0.10 \)- Alternative hypothesis \( H_a: p < 0.10 \)
02

Identify the Test Statistic

We will use the one-sample z-test for a proportion:\[Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}\]where \( \hat{p} = \frac{16}{200} = 0.08 \), \( p_0 = 0.10 \), and \( n = 200 \).
03

Calculate the Test Statistic

Substitute the values into the formula:\[Z = \frac{0.08 - 0.10}{\sqrt{\frac{0.10 \times 0.90}{200}}} = \frac{-0.02}{\sqrt{0.00045}} \approx \frac{-0.02}{0.0212} \approx -0.943\]
04

Find the P-value

The P-value for this one-tailed test (left-tail) is the probability of observing a z-value as extreme as -0.943 or more extreme. Using a standard normal table or calculator, the P-value is approximately 0.1736.
05

Make a Decision

Compare the P-value with the significance level \( \alpha = 0.01 \). Since 0.1736 > 0.01, we do not reject the null hypothesis \( H_0 \).
06

Explain with Confidence Interval

To construct a confidence interval for the proportion, use the formula:\[\hat{p} \pm Z_{\alpha/2} \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\]For a 99% confidence level, \(Z_{\alpha/2}\approx 2.576 \):\[0.08 \pm 2.576 \times \sqrt{\frac{0.08 \times 0.92}{200}} \approx 0.08 \pm 0.0331 \]This results in (0.0469, 0.1131), which includes 0.10, thus supporting that we cannot reject \( H_0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
When we talk about population proportion, we're referring to the fraction or percentage of a population that exhibits a specific characteristic. In the realm of hypothesis testing, it's essential to understand what this means. Imagine you have a large group—hundreds or even thousands of football helmets, for example. You're interested in knowing what proportion of these helmets are flawed.
The population proportion is essentially a snapshot that tells you the overall prevalence of a certain feature—in this case, defects in helmets.
  • If you're dealing with large numbers, like 200 helmets in a study, you'll calculate the sample proportion to make inferences about the larger population.
In our football helmet scenario, we calculate the sample proportion: 16 helmets out of 200 had defects. This gives a proportion of 0.08, or 8%. This is your eye into the population's proportion.
Z-test
The Z-test is a statistical tool used to compare whether your sample data matches what you expect under a specific hypothesis, particularly when dealing with proportions. In simple terms, this test allows us to determine if the observed proportion in our sample (in our example, 0.08 or 8%) is significantly different from the assumed population proportion (0.10 or 10%).
  • This is a one-sample Z-test because we are comparing the sample's proportion to a known value or a claim, not to another sample.
  • The key formula used is:
    \[Z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}\]
    In this formula, \(\hat{p}\) is the sample proportion (0.08), \(p_0\) is the hypothesized population proportion (0.10), and \(n\) is the sample size (200).
Once you've computed your Z-value, you use it to find the P-value, which helps determine the support regarding your hypothesis.
Confidence Interval
A confidence interval gives a range of values which is likely to contain the true population proportion. It's like saying, "we're fairly sure the real number is between this and that."To construct a confidence interval around the sample proportion, you'll calculate something like:
  • \[\hat{p} \pm Z_{\alpha/2} \times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\]
  • Here, \(\hat{p}\) is the sample proportion, about 8% in our example, \(Z_{\alpha/2}\) is a critical value from the Z-table (for a confidence level of 99%, \(Z\approx 2.576\)), and \(n\) is the sample size.
The idea is to create a range where we expect the true population proportion to fall most of the time. For our flawed helmets, this interval (0.0469, 0.1131) suggests that 10% could indeed be plausible if it lies within this interval, so the null hypothesis isn't rejected.
P-value
The P-value is a crucial concept in hypothesis testing, representing the probability of observing the test results under the null hypothesis. It's like asking, "What's the chance of seeing these results if our initial assumption were correct?" In our helmet study, the calculation yielded a Z-value of approximately -0.943. From the standard normal distribution, the P-value associated with this Z-value calculates to about 0.1736.
  • If the P-value is low (typically less than 0.05 or 0.01), this would suggest our observed results are quite unlikely under the null hypothesis, and we might reject it.
  • Conversely, a high P-value suggests that the null hypothesis can hold, as seen here with 0.1736, which is greater than the 0.01 level. This outcome means sticking with the null—10% might be a plausible defect rate.
Thus, P-value is a powerful tool for inference—showing whether your sample provides enough evidence to reject the null hypothesis.

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Most popular questions from this chapter

In each of the following situations, state whether it is a correctly stated hypothesis testing problem and why. (a) \(H_{0}: \mu=25, H_{1}: \mu \neq 25\) (b) \(H_{0}: \sigma>10, H_{1}: \sigma=10\) (c) \(H_{0}: \bar{x}=50, H_{1}: \bar{x} \neq 50\) (d) \(H_{0}: p=0.1, H_{1}: p=0.5\) (e) \(H_{0}: s=30, H_{1}: s>30\)

The number of cars passing eastbound through the in.tersection of Mill and University Avenues has been tabulated by a group of civil engineering students. They have obtained the data in the adjacent table: (a) Does the assumption of a Poisson distribution seem appropriate as a probability model for this process? Use \(\alpha=0.05\) (b) Calculate the \(P\) -value for this test. $$ \begin{array}{cccc} \hline \begin{array}{c} \text { Vehicles } \\ \text { per } \\ \text { Minute } \end{array} & \begin{array}{c} \text { Observed } \\ \text { Frequency } \end{array} & \begin{array}{c} \text { Vehicles } \\ \text { per } \\ \text { Minute } \end{array} & \begin{array}{c} \text { Observed } \\ \text { Frequency } \end{array} \\ \hline 40 & 14 & 53 & 102 \\ 41 & 24 & 54 & 96 \\ 42 & 57 & 55 & 90 \\ 43 & 111 & 56 & 81 \\ 44 & 194 & 57 & 73 \\ 45 & 256 & 58 & 64 \\ 46 & 296 & 59 & 61 \\ 47 & 378 & 60 & 59 \\ 48 & 250 & 61 & 50 \\ 49 & 185 & 62 & 42 \\ 50 & 171 & 63 & 29 \\ 51 & 150 & 64 & 18 \\ 52 & 110 & 65 & 15 \\ \hline \end{array} $$

Ten samples were taken from a plating bath used in an electronics manufacturing process, and the bath pH was determined. The sample \(\mathrm{pH}\) values are 7.91,7.85,6.82,8.01 \(7.46,6.95,7.05,7.35,7.25,\) and \(7.42 .\) Manufacturing engineering believes that \(\mathrm{pH}\) has a median value of 7.0 . (a) Do the sample data indicate that this statement is correct? Use the sign test with \(\alpha=0.05\) to investigate this hypothesis. Find the \(P\) -value for this test. (b) Use the normal approximation for the sign test to test \(H_{0}: \widetilde{\mu}=7.0\) versus \(H_{1}: \tilde{\mu} \neq 7.0 .\) What is the \(P\) -value for this test?

A melting point test of \(n=10\) samples of a binder used in manufacturing a rocket propellant resulted in \(\bar{x}=154.2^{\circ} \mathrm{F}\). Assume that the melting point is normally distributed with \(\sigma=1.5^{\circ} \mathrm{F}\) (a) Test \(H_{0}: \mu=155\) versus \(H_{1}: \mu \neq 155\) using \(\alpha=0.01\). (b) What is the \(P\) -value for this test? (c) What is the \(\beta\) -error if the true mean is \(\mu=150 ?\) (d) What value of \(n\) would be required if we want \(\beta<0.1\) when \(\mu=150 ?\) Assume that \(\alpha=0.01\).

State the null and alternative hypothesis in each case. (a) A hypothesis test will be used to potentially provide evidence that the population mean is greater than \(10 .\) (b) A hypothesis test will be used to potentially provide evidence that the population mean is not equal to 7 . (c) A hypothesis test will be used to potentially provide evidence that the population mean is less than \(5 .\)

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