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Suppose that the joint probability function of the continuous random variables \(X\) and \(Y\) is constant on the rectangle \(0 < x < a, 0 < y < b\). Show that \(X\) and \(Y\) are independent.

Short Answer

Expert verified
\(X\) and \(Y\) are independent.

Step by step solution

01

Understanding the Joint Probability Function

The joint probability density function (pdf) of continuous random variables \(X\) and \(Y\) being constant means that the pdf \(f(x, y)\) is a constant value \(c\) over the rectangle defined by the interval \(0 < x < a\) and \(0 < y < b\). Outside this rectangle, the probability is zero.
02

Calculating the Constant Value

Since the total probability over the entire range must be 1, we integrate the constant joint pdf \(c\) over the rectangle from \(x = 0\) to \(x = a\) and \(y = 0\) to \(y = b\). The integral is \(\int_0^a \int_0^b c \; dy \; dx = 1\). \(c\) must satisfy this, so \(c \cdot ab = 1\). Thus, \(c = \frac{1}{ab}\).
03

Finding the Marginal Distributions

The marginal distribution of \(X\), denoted \(f_X(x)\), is found by integrating the joint pdf \(f(x, y)\) over all \(y\): \[f_X(x) = \int_0^b \frac{1}{ab} \; dy = \frac{1}{ab} \times b = \frac{1}{a}.\]Similarly, the marginal distribution of \(Y\), denoted \(f_Y(y)\), is found by integrating over all \(x\):\[f_Y(y) = \int_0^a \frac{1}{ab} \; dx = \frac{1}{ab} \times a = \frac{1}{b}.\]
04

Verifying Independence

Two continuous random variables \(X\) and \(Y\) are independent if the joint pdf equals the product of the marginal pdfs, i.e., \(f(x, y) = f_X(x) \cdot f_Y(y)\). Here, \(f(x, y) = \frac{1}{ab}\), and the product of marginals is \(\frac{1}{a} \times \frac{1}{b} = \frac{1}{ab}\). Since these are equal, \(X\) and \(Y\) are independent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Joint Probability Function
In probability theory, the joint probability function plays a crucial role when dealing with two continuous random variables. It provides us with a framework to define the probability of two events occurring simultaneously. For the continuous random variables, this function takes the form of a joint probability density function (pdf), denoted as \( f(x, y) \). This function allows us to determine the likelihood of pairs \((x, y)\) for the random variables \(X\) and \(Y\).

When the joint pdf is constant, such as in a defined rectangle \( 0 < x < a \) and \( 0 < y < b \), it simplifies our calculations. Here, the joint pdf \( f(x, y) = c \) is constant over the rectangle and zero outside. To ensure this pdf is valid, the integral over this region must equate to 1. Hence, we adjust the constant \(c\) accordingly to satisfy this requirement.

The joint probability function helps us understand how variables interact and aligns with the conditions for independence, which can be crucial in practical applications.
Marginal Distribution
The marginal distribution offers insight into the behavior of a single variable within the context of its joint distribution with another variable. It is derived by integrating the joint pdf over the range of the other variable.

Think of it as collapsing the joint distribution into one dimension, focusing solely on one variable at a time. For variable \(X\), the marginal distribution \(f_X(x)\) is calculated by integrating over all possible values of \(Y\):
\[ f_X(x) = \int_0^b f(x, y) \; dy \]
This results in a function that models the distribution of \(X\) on its own, independent of \(Y\). Similarly, for \(Y\), we compute:
\[ f_Y(y) = \int_0^a f(x, y) \; dx \]
The marginal distributions are key when analyzing the variables individually, allowing us to see each variable's standalone distribution.
  • The dominance or presence of each variable can be easily interpreted from the integrals.
  • These integrals interpret the concentration of probability across each axis, revealing insights specific to each dimension separately.
They ensure you retain the complete perspective on each variable's behavior within the context of the joint distribution.
Continuous Random Variables
Continuous random variables are a fundamental concept in probability theory, representing values that can take an infinite number of possible points along a continuum. Unlike discrete variables, which are set to specific values, continuous random variables are characterized by their potential to assume any value within a given range.

For these types of variables, probability is defined over intervals rather than specific outcomes. For example, for a random variable \(X\) with a range \(a to b\), the probability of \(X\) falling within an interval is measured using integration. This is where the probability density function (pdf) comes into play, providing the value of probability per unit length.

The joint pdf for continuous random variables, such as \( f(x, y) \), extends this concept across dimensions. It allows us to analyze the probability of combinations of values between two variables. This makes understanding continuous random variables essential for modeling real-world phenomena that rely on precise, incremental measurements.
  • They require specialized mathematical tools like calculus for analysis and interpretation.
  • Continuous outcomes mean we always consider probability density rather than discrete probabilities.
The study of these variables provides deeper insights into statistical relationships and allows for more nuanced and flexible modeling.

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Most popular questions from this chapter

To evaluate the technical support from a computer manufacturer, the number of rings before a call is answered by a service representative is tracked. Historically, \(70 \%\) of the calls are answered in two rings or less, \(25 \%\) are answered in three or four rings, and the remaining calls require five rings or more. Suppose you call this manufacturer 10 times and assume that the calls are independent. (a) What is the probability that eight calls are answered in two rings or less, one call is answered in three or four rings, and one call requires five rings or more? (b) What is the probability that all 10 calls are answered in four rings or less? (c) What is the expected number of calls answered in four rings or less? (d) What is the conditional distribution of the number of calls requiring five rings or more given that eight calls are answered in two rings or less? (e) What is the conditional expected number of calls requiring five rings or more given that eight calls are answered in two rings or less? (f) Are the number of calls answered in two rings or less and the number of calls requiring five rings or more independent random variables?

In the manufacture of electroluminescent lamps, several different layers of ink are deposited onto a plastic substrate. The thickness of these layers is critical if specifications regarding the final color and intensity of light are to be met. Let \(X\) and \(Y\) denote the thickness of two different layers of ink. It is known that \(X\) is normally distributed with a mean of 0.1 millimeter and a standard deviation of 0.00031 millimeter and \(Y\) is also normally distributed with a mean of 0.23 millimeter and a standard deviation of 0.00017 millimeter. Assume that these variables are independent. (a) If a particular lamp is made up of these two inks only, what is the probability that the total ink thickness is less than 0.2337 millimeter? (b) A lamp with a total ink thickness exceeding 0.2405 millimeter lacks the uniformity of color demanded by the customer. Find the probability that a randomly selected lamp fails to meet customer specifications.

Let \(X\) and \(Y\) represent concentration and viscosity of a chemical product. Suppose \(X\) and \(Y\) have a bivariate normal distribution with \(\sigma_{X}=4, \sigma_{Y}=1, \mu_{X}=2,\) and \(\mu_{Y}=1 .\) Draw a rough contour plot of the joint probability density function for each of the following values of \(\rho\) : (a) \(\rho=0\) (b) \(\rho=0.8\) (c) \(\rho=-0.8\)

The weight of adobe bricks for construction is normally distributed with a mean of 3 pounds and a standard deviation of 0.25 pound. Assume that the weights of the bricks are independent and that a random sample of 25 bricks is chosen. (a) What is the probability that the mean weight of the sample is less than 2.95 pounds? (b) What value will the mean weight exceed with probability \(0.99 ?\)

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