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Let \(X\) be a binomial random variable with \(p=0.25\) and \(n=3\). Find the probability distribution of the random variable \(Y=X^{2}\).

Short Answer

Expert verified
\(P(Y=0) = 0.421875\), \(P(Y=1) = 0.421875\), \(P(Y=4) = 0.140625\), \(P(Y=9) = 0.015625\).

Step by step solution

01

Identify the Probability Distribution

The random variable \(X\) is binomially distributed with \(n=3\) and \(p=0.25\). Thus, \(X\) can take values \(0, 1, 2,\) and \(3\).
02

Calculate Binomial Probabilities

We calculate \(P(X=k)\) using the binomial formula: \(P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\).\- \(P(X=0) = \binom{3}{0} (0.25)^0 (0.75)^3 = 0.421875\)\- \(P(X=1) = \binom{3}{1} (0.25)^1 (0.75)^2 = 0.421875\)\- \(P(X=2) = \binom{3}{2} (0.25)^2 (0.75)^1 = 0.140625\)\- \(P(X=3) = \binom{3}{3} (0.25)^3 (0.75)^0 = 0.015625\)
03

Find the Values of Y

Since \(Y = X^2\), the possible values \(Y\) can take are determined by squaring the values of \(X\): \(0^2 = 0\), \(1^2 = 1\), \(2^2 = 4\), \(3^2 = 9\). Thus, \(Y\) can take the values \(0, 1, 4,\) and \(9\).
04

Determine the Probability Mass Function of Y

To find \(P(Y=y)\) for each \(y\), we sum the probabilities of \(X\) values that give \(Y=y\).\- \(P(Y=0) = P(X=0) = 0.421875\)\- \(P(Y=1) = P(X=1) = 0.421875\)\- \(P(Y=4) = P(X=2) = 0.140625\)\- \(P(Y=9) = P(X=3) = 0.015625\)
05

Construct the Probability Distribution of Y

The probability distribution of \(Y\) is as follows: \(P(Y=0) = 0.421875\), \(P(Y=1) = 0.421875\), \(P(Y=4) = 0.140625\), and \(P(Y=9) = 0.015625\). This gives the complete distribution of \(Y\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Mass Function
The Probability Mass Function, often abbreviated as PMF, is a crucial concept when dealing with discrete random variables. In probability theory, a PMF assigns probabilities to all possible outcomes of a discrete random variable. This function, mathematically expressed as \( P(X=k) \), describes the likelihood of a random variable \( X \) taking on a particular value \( k \).
  • For instance, in the given problem, \( X \) is a binomial random variable that can assume the values \( 0, 1, 2, \) and \( 3 \).
  • Each of these potential outcomes is associated with a calculated probability using the Binomial PMF formula.
Applying the binomial formula \( P(X=k) = \binom{n}{k} p^k (1-p)^{n-k} \), we derived specific probabilities corresponding to each value of \( X \). For example, the PMF for \( X=0 \) is 0.421875, indicating there is a 42.1875% chance that \( X \) equals 0.
In essence, the PMF is a vital tool for understanding the distribution of a discrete random variable's probabilities.
Random Variable
A Random Variable is a variable whose possible values are numerical outcomes of a random process. It can be thought of as a way to quantify outcomes of random phenomena numerically.
In our scenario, we have the random variable \( X \) which is governed by the binomial distribution parameters \( n=3 \) and \( p=0.25 \). The possible values that \( X \) can take are \( 0, 1, 2, \) and \( 3 \), each associated with a particular probability.
  • These outcomes occur due to the random nature of the binomial experiment where each trial is independent, and there is a fixed probability of success (\( p=0.25 \)).
  • The square of \( X \), denoted \( Y=X^2 \), represents another random variable derived from \( X \) and has its own possible outcomes \( 0, 1, 4, \) and \( 9 \).
Understanding random variables and their probabilities is crucial for analyzing and interpreting statistical data.
Probability Distribution
Probability Distribution refers to the mathematical function that provides the probabilities of occurrence of different possible outcomes in an experiment. For a discrete random variable, this entails listing the potential values the random variable can assume, alongside their respective probabilities.
In our example, the probability distribution of the random variable \( Y \) can be summarized as follows:
  • \( P(Y=0) = 0.421875 \)
  • \( P(Y=1) = 0.421875 \)
  • \( P(Y=4) = 0.140625 \)
  • \( P(Y=9) = 0.015625 \)
A probability distribution gives us a comprehensive picture of how the total probability of \( 1 \), or 100%, is spread across the different possible values of \( Y \).
Each probability indicates how likely a particular squared outcome is to occur in the process described by the random experiment.
Binomial Random Variable
A Binomial Random Variable is a specific type of random variable that arises from a series of repeated, independent trials of a binary outcome process, such as flipping a coin. The binomial distribution is determined by two parameters: \( n \), the number of trials, and \( p \), the probability of success in each trial.
For example, in our exercise, \( X \) is a binomial random variable with parameters \( n=3 \) and \( p=0.25 \). This means we conduct three trials, each with a 25% probability of success.
  • The possible outcomes for \( X \) can range from 0 successes (none) to 3 successes (all trials are successful).
  • These outcomes follow a pattern dictated by the binomial probabilities derived from the formula: \( P(X=k) = \binom{n}{k} p^k (1-p)^{n-k}\).
Understanding binomial random variables is essential in probability and statistics as they serve as a model for many real-world processes that involve binary outcomes.

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