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Suppose that the log-ons to a computer network follow a Poisson process with an average of 3 counts per minute. (a) What is the mean time between counts? (b) What is the standard deviation of the time between counts? (c) Determine \(x\) such that the probability that at least one count occurs before time \(x\) minutes is \(0.95 .\)

Short Answer

Expert verified
Mean and standard deviation are 0.333 minutes; x is 0.9986 minutes.

Step by step solution

01

Identify Mean Calculation

In a Poisson process, the rate \(\lambda\) is the average number of counts occurring in a fixed interval of time. Here, \(\lambda = 3\) counts per minute. The mean time between counts is given by \(\frac{1}{\lambda}\). Thus, calculate \(\frac{1}{3}\) minutes.
02

Compute the Mean Time Between Counts

Calculate the mean time using the formula \(\frac{1}{\lambda} = \frac{1}{3} = 0.333\) minutes. This represents the expected time between two consecutive counts.
03

Identify Standard Deviation Calculation

For the exponential distribution (which models the time between counts in a Poisson process), the standard deviation is equal to the mean. Thus, we use the previously calculated mean: \(0.333\) minutes.
04

Calculate Standard Deviation

Since the standard deviation equals the mean, the standard deviation of time between log-ons is also \(0.333\) minutes.
05

Set Up the Probability Equation

The probability that at least one count occurs before time \(x\) can be expressed as: \( P(T < x) = 1 - e^{-\lambda x} \). We are given \( P(T < x) = 0.95 \), solve this equation for \(x\).
06

Solve the Equation for 'x'

Start with the equation \( 1 - e^{-3x} = 0.95 \), which simplifies to \( e^{-3x} = 0.05 \). Taking the natural log of both sides gives \( -3x = \ln(0.05) \). Therefore, solve for \(x\) to get \( x = -\frac{\ln(0.05)}{3} \). Compute this to find \(x\).
07

Calculate 'x'

Compute \( x = -\frac{\ln(0.05)}{3} \). Using a calculator, \( \ln(0.05) \approx -2.9957 \), so \( x \approx -\frac{-2.9957}{3} \approx 0.9986 \) minutes.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Time Calculation
In a Poisson process, calculating the mean time between events is an essential concept. The Poisson process is characterized by a constant average rate at which events occur. This is denoted by \( \lambda \), representing the average number of events per unit time.

To determine the mean time between events, you use the reciprocal of the rate \( \lambda \). Essentially, you compute \( \frac{1}{\lambda} \). For instance, if \( \lambda \) is 3 counts per minute, the mean time is calculated as follows:
  • Mean Time Formula: \( \frac{1}{\lambda} = \frac{1}{3} \)
Thus, the mean time is \( 0.333 \) minutes, or approximately 20 seconds, between consecutive events. This tells you how much time, on average, will pass between each occurrence in the process. Understanding this helps to predict and analyze events more precisely in scenarios modeled by a Poisson distribution.
Standard Deviation in Poisson Process
The Poisson process is a foundational concept in statistics, often used because of its simplicity and ability to model real-world scenarios. A unique aspect of the Poisson process is its relationship with the exponential distribution when considering time between events.

In this context, the standard deviation is equal to the mean. This happens because for an exponential distribution, which describes the time between events in a Poisson process, both the mean and the standard deviation share the same value.

This implies that if the mean time between counts is \( 0.333 \) minutes, the standard deviation is also
  • Standard Deviation: \( 0.333 \) minutes
This results from the inherent properties of the exponential distribution, simplifying various analyses and interpretations related to the timing of events in a Poisson process.
Exponential Distribution
The exponential distribution plays a vital role in modeling the time between events in a Poisson process. It is defined by the mean, which is the reciprocal of the rate \( \lambda \). In the Poisson process, this distribution can provide insights into the probability of event occurrences within certain time periods.

Let's explore how the probability is calculated. If you want to find the time \( x \) before at least one event occurs, the formula to use is:
  • Probability Expression: \( P(T < x) = 1 - e^{-\lambda x} \)
To solve for \( x \) when you want a certain probability, like 0.95 (95%), you'd substitute and solve:
  • Set Equation: \( 1 - e^{-3x} = 0.95 \)
  • Solution: \( e^{-3x} = 0.05 \)
  • Natural Logarithm: \( -3x = \ln(0.05) \)
  • Solve for \( x \): \( x = -\frac{\ln(0.05)}{3} \approx 0.9986 \) minutes
This tells us that within approximately 0.9986 minutes, there's a 95% probability that at least one event will occur. The exponential distribution is thus crucial for determining such probabilities in the context of a Poisson process.

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