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Suppose \(X\) has an exponential distribution with me: equal to \(10 .\) Determine the following: (a) \(P(X>10)\) (b) \(P(X>20)\) (c) \(P(X<30)\) (d) Find the value of \(x\) such that \(P(X

Short Answer

Expert verified
(a) 0.3679, (b) 0.1353, (c) 0.9502, (d) x ≈ 29.96

Step by step solution

01

Identify the parameters of the exponential distribution

An exponential distribution is defined by the rate parameter \( \lambda \). This parameter is the reciprocal of the mean. Given the mean is 10, the rate parameter is \( \lambda = \frac{1}{10} = 0.1 \). This will help us in various calculations involving the exponential distribution.
02

Calculate the probability for (a) P(X > 10)

The probability \( P(X > x) \) is given by \( e^{-\lambda x} \). Here, \( x = 10 \) and \( \lambda = 0.1 \). Thus, \( P(X > 10) = e^{-0.1 \times 10} = e^{-1} \). Evaluating \( e^{-1} \), we find \( P(X > 10) \approx 0.3679 \).
03

Calculate the probability for (b) P(X > 20)

Repeating the process for \( x = 20 \), we have \( P(X > 20) = e^{-0.1 \times 20} = e^{-2} \). Evaluating \( e^{-2} \), we find \( P(X > 20) \approx 0.1353 \).
04

Calculate the probability for (c) P(X < 30)

The probability \( P(X < x) \) is given by \( 1 - e^{-\lambda x} \). Here, \( x = 30 \), so \( P(X < 30) = 1 - e^{-0.1 \times 30} = 1 - e^{-3} \). Evaluating \( e^{-3} \), we find \( P(X < 30) \approx 0.9502 \).
05

Find the value of x such that P(X < x) = 0.95

We need to find \( x \) such that \( 1 - e^{-0.1x} = 0.95 \). Solving for \( x \), we get \( e^{-0.1x} = 0.05 \). Taking the natural logarithm, \(-0.1x = \ln(0.05)\), hence \( x = -\frac{\ln(0.05)}{0.1} \). Calculating this gives approximately \( x \approx 29.96 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculations
Probability calculations in the context of an exponential distribution involve determining the likelihood of certain events, such as an event happening after a specific time. In exponential distributions, we often focus on the probability of the random variable being greater or less than a particular value. This is due to its memoryless property, meaning that the future probability does not depend on past events.

For example, to calculate the probability that a random variable, say \(X\), is greater than a certain value \(x\), we use the formula: \[ P(X > x) = e^{-\lambda x} \] This represents the probability that more time passes than \(x\) between occurrences when \(\lambda\) is the rate parameter. The probability formula for \(P(X < x)\) flips slightly, using:\[ P(X < x) = 1 - e^{-\lambda x} \] This determines the probability of the occurrence happening before \(x\). These calculations are foundational for understanding how random processes unfold over time, particularly in fields requiring reliability and risk assessment.
Rate Parameter
The rate parameter, denoted as \( \lambda \), is a key component of the exponential distribution. It indicates how often an event occurs. Specifically, it is the inverse of the mean of the distribution. For instance, if the mean waiting time is 10 seconds, then the rate parameter is \( \lambda = \frac{1}{10} = 0.1 \).

This parameter is crucial because it impacts the steepness of the distribution's decay function. A higher rate parameter means events happen more frequently, resulting in a more rapid decay of the distribution. Conversely, a lower rate parameter means events are rarer, which is reflected in a gradual decay. Understanding \( \lambda \) helps predict and analyze the timing of future events, making it vital for risk management and operational forecasting.
Decay Function
The decay function of an exponential distribution describes how the probability decreases as the value of the random variable increases. This function is exponentially decreasing, meaning that probabilities diminish quickly at first and then level out as time progresses.

The decay function is expressed mathematically as: \[ e^{-\lambda x} \] This equation helps analyze situations where the occurrence frequency is declining over time. The rapid decrease at smaller values of \(x\) signifies that shorter intervals between events are more common.

Understanding the decay function is essential for fields like queuing theory and reliability engineering, where efficient service and resource allocation are critical. By anticipating when events are likely to occur, organizations can better manage time resources and minimize downtime.
Cumulative Distribution Function
The cumulative distribution function (CDF) of the exponential distribution gives the probability that a random variable \(X\) will take a value less than or equal to \(x\). Formally, it's given by: \[ F(x) = 1 - e^{-\lambda x} \] This function accumulates probabilities, so it starts at 0 and increases to 1 as \(x\) increases, aligning with the idea that the chance of an event occurring only rises over time.

The CDF is a powerful tool for finding percentiles, such as determining the value of \(x\) where the probability reaches a certain threshold, like 0.95 (or 95%). Essentially, it answers the question, "What is the maximum time before most events occur?" This understanding is critical for assessments in life data analysis, such as calculating failure rates and designing warranties, helping to bring quantitative backing to decision-making processes.

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