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If \(X\) is a Weibull random variable with \(\beta=1\) and \(\delta=1000\), what is another name for the distribution of \(X\) and what is the mean of \(X ?\)

Short Answer

Expert verified
The distribution is an exponential distribution with a mean of 1000.

Step by step solution

01

Recognizing Distribution Type

The Weibull distribution with parameters \( \beta = 1 \) and \( \delta \) is a special case of the Weibull distribution. When \( \beta = 1 \), the Weibull distribution simplifies to the exponential distribution with rate parameter \( \lambda = \frac{1}{\delta} \). Therefore, the distribution of \( X \) is also called an exponential distribution.
02

Determining the Mean of Exponential Distribution

For an exponential distribution with rate parameter \( \lambda = \frac{1}{\delta} \), the mean is given by \( \mu = \frac{1}{\lambda} = \delta \). Since \( \delta = 1000 \), the mean of \( X \) is 1000.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Distribution
An exponential distribution is a type of probability distribution commonly used to model the time between events in a process where events occur continuously and independently at a constant average rate. It is characterized by a single parameter, usually denoted as \( \lambda \), which is the rate parameter. This parameter is essentially the inverse of the mean, capturing how frequently events occur. The exponential distribution has a memoryless property, meaning the future probability of an event does not depend on past events. This makes it unique among common probability distributions found in statistical modeling.

When dealing with an exponential distribution, the probability density function (PDF) is expressed as:
  • \( f(x; \lambda) = \lambda e^{-\lambda x} \) for \( x \geq 0 \)
This function describes the likelihood of a time to occur being exactly \( x \) given the constant rate \( \lambda \). The key to understanding is recognizing how \( \lambda \) frames the distribution — a larger \( \lambda \) suggests a quicker occurrence rate.
Mean of a Distribution
The mean of a distribution provides a measure of the central tendency, or the expected value, of a random variable. For any distribution, the mean is the point where the distribution would balance if it were plotted on a graph. It provides insight into the average outcome, if the process could be repeated many times.

For the exponential distribution, deriving the mean is straightforward owing to its simplicity in structure. The formula for the mean \( \mu \) in terms of the rate parameter \( \lambda \) is:
  • \( \mu = \frac{1}{\lambda} \)
This inverse relationship implies that a higher occurrence rate corresponds to a shorter expected time until the next event. In the specific case of the exponential distribution that's derived from a Weibull distribution with \( \beta = 1 \), as in our exercise, the mean turns out to be equivalent to \( \delta \), the scale parameter, which provides an intuitive grasp of the average size of the random variable involved.
Weibull Parameters
The Weibull distribution is a flexible statistical model used widely to represent reliability and life data. It is described by two parameters, \( \beta \) (shape parameter) and \( \delta \) (scale parameter), which determine the distribution's form and features.

The shape parameter \( \beta \) significantly affects the distribution’s behavior:
  • If \( \beta = 1 \), the Weibull distribution simplifies to the exponential distribution.
  • If \( \beta < 1 \), the distribution models decreasing failure rate, often used in early-life failure studies.
  • If \( \beta > 1 \), it models an increasing failure rate, suitable for aging or wear-out phenomena.
The scale parameter \( \delta \) effectively stretches or compresses the distribution along the x-axis. It adjusts the scale of data being considered, translating to the mean in the exponential form. Thus, \( \delta \) provides insightful data into the scale or expectation of measured events or lifespans in the dataset context.

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Most popular questions from this chapter

The volume of a shampoo filled into a container is uniformly distributed between 374 and 380 milliliters. (a) What are the mean and standard deviation of the volume of shampoo? (b) What is the probability that the container is filled with less than the advertised target of 375 milliliters? (c) What is the volume of shampoo that is cxceeded by \(95 \%\) of the containers? (d) Iivery milliliter of shampoo costs the producer \(\$ 0.002\). Any more shampoo in the container than 375 milliliters is an cxtra cost to the produecr. What is the mean extra cost?

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The length of an injection-molded plastic case that holds magnetic tape is normally distributed with a length of 90.2 millimeters and a standard deviation of 0.1 millimeter. (a) What is the probability that a part is longer than 90.3 millimeters or shorter than 89.7 millimeters? (b) What should the process mean be set at to obtain the greatest number of parts between 89.7 and 90.3 millimeters? (c) If parts that are not between 89.7 and 90.3 millimeters are scrapped, what is the yield for the process mean that you selected in part (b)? Assume that the process is centered so that the mean is 90 millimeters and the standard deviation is 0.1 millimeter. Suppose that 10 cases are measured, and they are assumed to be independent. (d) What is the probability that all 10 cases are between 89.7 and 90.3 millimeters? (e) What is the expected number of the 10 cases that are between 89.7 and 90.3 millimeters?

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