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The total service time of a multistep manufacturing operation has a gamma distribution with mean 18 minutes and standard deviation 6 . (a) Determine the parameters \(\lambda\) and \(r\) of the distribution. (b) Assume each step has the same distribution for service time. What distribution for each step and how many steps produce this gamma distribution of total service time?

Short Answer

Expert verified
(a) \( r = 9 \), \( \lambda = \frac{1}{2} \). (b) Exponential distribution with \( \lambda = \frac{1}{2} \), 9 steps.

Step by step solution

01

Gamma Distribution Mean Formula

The mean of a gamma distribution is given by \( \text{mean} = \frac{r}{\lambda} \), where \( r \) is the shape parameter and \( \lambda \) is the rate parameter. Given that the mean is 18, we have:\[\frac{r}{\lambda} = 18\]
02

Gamma Distribution Standard Deviation Formula

The standard deviation of a gamma distribution is \( \text{std} = \frac{\sqrt{r}}{\lambda} \). We know that the standard deviation is 6, so we have:\[\frac{\sqrt{r}}{\lambda} = 6\]
03

Solving for \\lambda

From the standard deviation formula, rearrange to solve for \( \lambda \):\[\lambda = \frac{\sqrt{r}}{6}\]
04

Substitute \\lambda into Mean Equation

Substitute \( \lambda = \frac{\sqrt{r}}{6} \) into the mean equation:\[\frac{r}{\frac{\sqrt{r}}{6}} = 18\]Simplifying gives:\[6\sqrt{r} = 18\]\[\sqrt{r} = 3\]
05

Solve for \\r

Square both sides to solve for \( r \):\[(\sqrt{r})^2 = 3^2\]\[r = 9\]
06

Solve for \\lambda Using \\r

Using \( r = 9 \) in our expression for \( \lambda \):\[\lambda = \frac{\sqrt{9}}{6} = \frac{3}{6} = \frac{1}{2}\]
07

Determine the Distribution of Each Step

Each step in a process modeled by a gamma distribution can be represented by an exponential distribution with the same rate \( \lambda \). Since the process consists of \( r = 9 \) steps, each step has an exponential distribution with \( \lambda = \frac{1}{2} \).
08

Conclusion

The total service time follows a gamma distribution with parameters \( r = 9 \) and \( \lambda = \frac{1}{2} \). Therefore, each step's service time follows an exponential distribution with parameter \( \lambda = \frac{1}{2} \), and there are 9 steps in the total process.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Distribution
The Exponential Distribution is one of the simplest forms of probability distributions and is a special case of the Gamma Distribution. It is extensively used to model the time between events in a Poisson process, where events occur continuously and independently at a constant average rate. This distribution is characterized by the rate parameter, often denoted by \( \lambda \), and has a mean of \( \frac{1}{\lambda} \) and a variance of \( \frac{1}{\lambda^2} \). This makes it particularly useful for modeling waiting times, such as the time until a radioactive particle decays or the time between arrivals of customers to a service point. One interesting feature of the exponential distribution is its memoryless property. This means that the probability of waiting an additional amount of time does not depend on how much time has already passed. This property significantly simplifies scenario modeling, making it practical for various real-world applications. In the context of the given problem, each step in the manufacturing process can be modeled by an exponential distribution with the rate parameter \( \lambda = \frac{1}{2} \), showing that each step is independently and consistently completed over time.
Probability Distribution Parameters
In probability theory, the parameters of a probability distribution fundamentally determine its nature and behavior. For the Gamma Distribution, two important parameters stand out: the shape parameter \( r \) and the rate parameter \( \lambda \). Understanding these parameters can provide deep insights into the dynamics of data patterns.
  • Shape Parameter \( r \): This parameter defines the shape of the distribution curve. In the case of the gamma distribution, \( r \) not only dictates the skewness but also influences the number of events or stages involved in a process. When \( r \) is an integer, it is often related to the sum of \( r \) exponentially distributed random variables.
  • Rate Parameter \( \lambda \): This parameter inversely relates to time, defining how quickly events occur. A higher \( \lambda \) indicates a rapid occurrence of events, while a lower value suggests less frequent events.
Using the problem solution, the shape parameter \( r = 9 \) and rate parameter \( \lambda = \frac{1}{2} \) were calculated, indicating a scenario where the total service time is effectively the sum of multiple exponential stages, providing a comprehensive view of the entire process from start to finish.
Service Time Analysis
Service Time Analysis is essential in operations research, helping to optimize processes, especially in manufacturing and service industries. The goal is to assess the time required to complete tasks, allowing for better resource allocation, improved productivity, and customer satisfaction.By using probability distributions like the gamma distribution, one can model service time more realistically. This distribution is perfect for situations where a task involves multiple stages, whose individual times might follow an exponential distribution. Utilizing the Gamma Distribution, businesses can:
  • Identify Bottlenecks: By examining the different stages, managers can pinpoint which parts of a process take the longest and may need improvements.
  • Estimate Total Time: Understand how long a complete operation will take on average, helping with planning and scheduling.
  • Enhance Efficiency: Use statistical insights to streamline operations and improve service efficiency.
In the manufacturing operation described in the problem, service time analysis reveals that the operation consists of 9 distinct steps. Each of these steps follows an exponential distribution with \( \lambda = \frac{1}{2} \). This shows a controlled, predictable service time that managers can use to optimize overall productivity.

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Most popular questions from this chapter

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