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Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the red spectrum from 675 to \(700 \mathrm{nm}\). (a) What is the mean and variance of the wavelength distribution for this radiation? (b) If the wavelengths are uniformly distributed at integer nanometers from 75 to 100 nanometers, how does the mean and variance of the wavelength distribution compare to the previous part? Explain.

Short Answer

Expert verified
Part (a) Mean: 687.5, Variance: 56.33; Part (b) Mean: 87.5, Variance: 56.33. The variance is the same in both parts.

Step by step solution

01

Understand the Distribution

We are tasked with dealing with a uniform distribution of wavelengths within the given ranges. Specifically, we need to handle the red spectrum in part (a) from 675 nm to 700 nm and in part (b) from 75 nm to 100 nm.
02

Define the Uniform Distribution Parameters for Part (a)

For uniformly distributed wavelengths from 675 nm to 700 nm, the smallest value (\(a\)) is 675 and the largest value (\(b\)) is 700. The number of values \( n \) is the count of integers from 675 to 700. This makes it \(n = 700 - 675 + 1 = 26\).
03

Calculate Mean and Variance for Part (a)

For a uniform distribution, the mean \( \mu \) is given by \( \mu = \frac{a + b}{2} \). Thus, the mean for the wavelengths is \( \mu = \frac{675 + 700}{2} = 687.5 \). The variance \( \sigma^2 \) is given by \( \sigma^2 = \frac{(b - a + 1)^2 - 1}{12} \). Hence, \( \sigma^2 = \frac{(700 - 675 + 1)^2 - 1}{12} = \frac{676}{12} \approx 56.33 \).
04

Define the Uniform Distribution Parameters for Part (b)

For wavelengths from 75 nm to 100 nm, set \(a = 75\) and \(b = 100\). Again, we count the integers in this range, which is \( n = 100 - 75 + 1 = 26 \).
05

Calculate Mean and Variance for Part (b)

Using the formulas for uniform distribution, the mean \( \mu \) is \( \mu = \frac{75 + 100}{2} = 87.5 \). The variance will be the same as part (a) since the number of integers \(n\) and the difference \(b-a\) are the same: \( \sigma^2 = \frac{(100 - 75 + 1)^2 - 1}{12} = \frac{676}{12} \approx 56.33 \).
06

Draw a Comparison

The mean of the distribution in part (a) is higher, at 687.5 compared to 87.5 in part (b). However, both distributions have the same variance, approximately 56.33, indicating they share the same spread in terms of the distribution, due to having the same range count and uniform distribution nature.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean of Uniform Distribution
The mean of a uniform distribution is quite straightforward to calculate. In a uniform distribution, probabilities are spread evenly over a certain range of values. The formula to find the mean of a uniform distribution is \( \mu = \frac{a + b}{2} \),where \( a \) and \( b \) are the minimum and maximum values of the distribution, respectively. The mean, also known as the average, tells us the central value of this distribution.
  • In part (a) of our exercise, the wavelengths for photosynthetically active radiations ranged from 675 nm to 700 nm.Using the formula here, the mean is calculated as \( \mu = \frac{675 + 700}{2} = 687.5 \ \text{nm}\).
  • In part (b), the range was from 75 nm to 100 nm, resulting in a mean of \( \mu = \frac{75 + 100}{2} = 87.5 \ \text{nm}\).
This difference shows that while the spread (or variance) may be the same, the average or center point of the wavelengths can shift significantly with different ranges.
Variance of Uniform Distribution
Variance in a uniform distribution tells us about the spread or how much the values deviate from the mean. The formula for variance in a uniform distribution is \( \sigma^2 = \frac{(b - a + 1)^2 - 1}{12} \).The variance shows us how dispersed the values are across the range — a higher variance indicates a wider spread.
  • For the wavelengths distribution in part (a) between 675 nm and 700 nm, the variance was calculated as \( \sigma^2 = \frac{(700 - 675 + 1)^2 - 1}{12} = 56.33 \).
  • For part (b), from 75 nm to 100 nm, the variance calculated the same because the numbers of integer values and the difference between \( b \) and \( a \) remained constant.This reinforces that variance is dependent not just on the absolute values but primarily on the range size and count of values in a uniform distribution.
The key takeaway is that variance measures how much the values vary from the mean within the specified range.
Uniformly Distributed Wavelengths
Understanding that wavelengths can be uniformly distributed is crucial in studies of light and radiation such as photosynthetically active radiations (PAR). Uniform distribution implies that each wavelength within a specified range has an equal probability of occurring. In practical terms for this exercise, whether we consider red spectrum wavelengths from 675 to 700 nm or a range from 75 to 100 nm, the characteristic of uniform distribution remains consistent. It means each individual wavelength has the same chance of being observed within its respective range.
  • This exercise demonstrated that regardless of the wavelength range, if it’s uniformly distributed, the way we calculate mean and variance doesn’t change.
  • Although the specific wavelengths differ, the methods and mathematical formulas applied are universals for any uniformly distributed data set.
Uniform distribution helps simplify complex realities of natural phenomena, providing a base to apply statistical methods in diverse fields such as physics, chemistry, and environmental science.

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