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An article in Knee Surgery, Sports Traumatology, Arthroscopy ["Arthroscopic Meniscal Repair with an Absorbable Screw: Results and Surgical Technique" \((2005,\) Vol. \(13,\) pp. \(273-279\) ) ] cites a success rate of more than \(90 \%\) for meniscal tears with a rim width of less than \(3 \mathrm{~mm}\), but only a \(67 \%\) success rate for tears of \(3-6 \mathrm{~mm}\). If you are unlucky enough to suffer a meniscal tear of less than \(3 \mathrm{~mm}\) on your left knee and one of width \(3-6 \mathrm{~mm}\) on your right knee, what is the probability mass function of the number of successful surgeries? Assume the surgeries are independent.

Short Answer

Expert verified
The PMF is: \( P(X = 0) = 0.033 \), \( P(X = 1) = 0.364 \), \( P(X = 2) = 0.603 \).

Step by step solution

01

Understand the Problem

The problem involves finding the probability mass function (PMF) for the number of successful surgeries given the success rates of two independent events: each knee surgery. We know the success rate for the left knee surgery is 90% and for the right knee surgery is 67%.
02

Define Random Variables

Let \( X \) be the random variable representing the number of successful surgeries. The possible values that \( X \) can take are 0, 1, and 2, corresponding to 0, 1, or both surgeries being successful.
03

Calculate Probability for Each Outcome

- The probability that neither surgery is successful (both are failures) is calculated as \( P( ext{0 successes}) = (1 - 0.90) \times (1 - 0.67) = 0.10 \times 0.33 = 0.033 \).- The probability that exactly one surgery is successful can be split into two cases: 1. Left knee successful, right knee not: \( P( ext{Left success, Right failure}) = 0.90 \times (1 - 0.67) = 0.90 \times 0.33 = 0.297 \). 2. Right knee successful, left knee not: \( P( ext{Left failure, Right success}) = (1 - 0.90) \times 0.67 = 0.10 \times 0.67 = 0.067 \).- The probability both surgeries are successful is \( P( ext{2 successes}) = 0.90 \times 0.67 = 0.603 \).
04

Construct the Probability Mass Function (PMF)

The PMF of \( X \), the number of successful surgeries, is given by combining the calculated probabilities:\[P(X = 0) = 0.033 \]\[P(X = 1) = 0.297 + 0.067 = 0.364 \]\[P(X = 2) = 0.603\]Thus, the PMF is:- \( P(X = 0) = 0.033 \)- \( P(X = 1) = 0.364 \)- \( P(X = 2) = 0.603 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
In probability theory, when we talk about independent events, we are referring to situations where the outcome of one event does not affect the outcome of another.
This concept is essential in understanding the scenario described in the exercise, where we consider the two knee surgeries.
Since the surgeries are classified as independent events, the probability of success for one knee does not influence the probability of success for the other.
To illustrate, imagine flipping two separate coins. The outcome of the first flip doesn't affect the second.
Similarly, if the left knee surgery is successful or not, it does not change the chances for the right knee.
This independence allows us to multiply probabilities of each event to find combined probabilities.
  • Left knee surgery: Success probability 90%
  • Right knee surgery: Success probability 67%
By understanding the concept of independent events, we can better calculate the probabilities associated with each possible scenario of surgery outcomes.
Success Rate
Success rate refers to the probability that a given procedure will achieve the desired outcome.
It is a crucial part of probability calculations, especially when determining likely outcomes in medical procedures like the surgeries mentioned.
In the article referenced in the exercise, there is a distinction made between surgeries with different rim widths.
The success rate for a meniscal tear less than 3 mm is cited as over 90%.
In contrast, the tear within the 3-6 mm range exhibits a 67% success rate. Success rate helps us determine the effectiveness of a procedure under specified conditions.
This rate is a foundational piece of information when building a probability mass function, as it determines the likelihoods associated with each surgery, guiding us in calculating the overall probabilities for different scenarios.
  • Overall, a high success rate indicates a greater probability of achieving the surgical goal,
  • meaning the patient's outcome is more favorable.
Random Variable
A random variable is a mathematical representation of possible outcomes in a probability space.
It assigns numerical values to each event of a probability experiment.
In the context of the exercise, the random variable represents the number of successful knee surgeries.Here, we define the random variable as \( X \), where \( X \) can be:
  • 0 if neither surgery is successful,
  • 1 if exactly one of the surgeries is successful,
  • 2 if both surgeries are successful.
By establishing \( X \) as a random variable, we can then calculate its probability mass function. This function helps us understand the likelihood of each possible outcome.The concept of random variables is fundamental because it allows us to systematically explore and assign probabilities to real-world situations.
Probability Calculation
Probability calculation involves determining the likelihood of various possible outcomes.
With independent events, we multiply the probabilities of individual events to get the total probability for a scenario.
In the given exercise, calculating probability involves applying this principle to each surgery outcome scenario:
  • For 0 successful surgeries: both operations fail. The probability is calculated as \((1 - 0.90) \times (1 - 0.67) = 0.033\).
  • For 1 successful surgery:
    • Left knee is successful, right knee fails: \(0.90 \times (1 - 0.67) = 0.297\)
    • Right knee is successful, left knee fails: \((1 - 0.90) \times 0.67 = 0.067\)
    Combined probability for one success is \(0.364\).
  • For 2 successful surgeries: \(0.90 \times 0.67 = 0.603\).
Probability calculations are critical in forming conclusions from data.
By understanding how to compute these probabilities, students can better model real-world situations using mathematical principles.

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