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The number of failures of a testing instrument from contamination particles on the product is a Poisson random variable with a mean of 0.02 failure per hour. (a) What is the probability that the instrument does not fail in an eight-hour shift? (b) What is the probability of at least one failure in a 24 -hour day?

Short Answer

Expert verified
(a) 0.852 (b) 0.381

Step by step solution

01

Define the Poisson Random Variable

Given that the average rate of failure is \( \lambda = 0.02 \) failures per hour. For an eight-hour shift, the mean \( \lambda_1 = 8 \times 0.02 = 0.16 \). For a 24-hour period, the mean \( \lambda_2 = 24 \times 0.02 = 0.48 \).
02

Calculate Probability for No Failure (8-hour shift)

For a Poisson distribution, the probability of observing \( k \) failures is given by the formula: \( P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!} \). For no failures (\( k = 0 \)), in an eight-hour shift, substitute \( \lambda_1 = 0.16 \) into the formula: \[ P(X = 0) = \frac{e^{-0.16} \times 0.16^0}{0!} = e^{-0.16} \approx 0.852 \].
03

Calculate Probability for At Least One Failure (24-hour day)

The probability of at least one failure is the complement of the probability of zero failures. First calculate the probability of zero failures for a 24-hour period: \( P(X = 0) = e^{-0.48} \approx 0.619 \). Then, the probability of at least one failure is: \( P(X \geq 1) = 1 - P(X = 0) = 1 - 0.619 \approx 0.381 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculations are essential for understanding the likelihood of certain events occurring under specified conditions. In our exercise, we delve into a Poisson distribution, which is a probability distribution often used for counting the number of times an event occurs in a fixed interval of time or space.
  • The Poisson formula is defined as: \( P(X = k) = \frac{e^{-\lambda} \lambda^k}{k!} \), where \( \lambda \) is the average rate of occurrence, and \( k \) is the number of occurrences (failures in our case).
  • For example, to find the probability of zero failures in an eight-hour shift, we use \( \lambda_1 = 0.16 \) and substitute into our formula to find \( P(X = 0) \).
Probability calculations allow us to make informed predictions and decisions based on statistical models. Whether predicting machine failures or any other events, mastering basic probability is a fundamental skill.
Random Variable
A random variable is a fundamental concept in probability and statistics. It represents numerical outcomes of a random phenomenon. In the case of the Poisson distribution discussed in the exercise, the random variable specifically denotes the number of failures in a given time period.
  • In our example, \( X \) represents the number of failures during either an eight-hour shift or a 24-hour day.
  • The Poisson random variable is characterized by a mean rate, \( \lambda \), which in this context is based on the failure rate per hour (0.02).
Understanding random variables is crucial because they form the basic building blocks of probability distributions. They help in quantifying uncertainty and modeling different scenarios.
Failure Rate
In the context of the Poisson distribution, the failure rate is the expected number of occurrences of an event within a specified period. It is directly tied to the parameter \( \lambda \). For the exercise's scenario, \( \lambda = 0.02 \) failures per hour expresses the failure rate for the instrument.

Key Points about Failure Rate:

  • The failure rate is typically constant within the period considered, making it suitable for Poisson models.
  • The calculation of the mean \( \lambda \) over different time frames involves scaling the hourly rate proportionately. For instance, eight-hour and 24-hour periods yield rate parameters \( \lambda_1 = 0.16 \) and \( \lambda_2 = 0.48 \), respectively.
The failure rate helps determine the feasibility of maintenance schedules and operating procedures by giving insight into expected reliability over time.
Complement Rule
The complement rule in probability helps to compute the likelihood of the complementary event occurring. The rule states that the probability of an event's complement (not happening) equals one minus the probability of the event.In the exercise:
  • To find the probability of "at least one failure" (event \( A \)) in a 24-hour day, we use the complement of having zero failures (event \( A^c \)).
  • Using \( P(X = 0) = e^{-0.48} \approx 0.619 \), the complement rule allows us to calculate \( P(X \geq 1) = 1 - P(X = 0) = 1 - 0.619 \approx 0.381 \).
The complement rule is a handy tool for simplifying complex probability problems, especially when the direct calculation of the probability is challenging.

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