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If \(P(A)=0.3, P(B)=0.2,\) and \(P(A \cap B)=0.1\), determine the following probabilities: (a) \(P\left(A^{\prime}\right)\) (b) \(P(A \cup B)\) (c) \(P\left(A^{\prime} \cap B\right)\) (d) \(P\left(A \cap B^{\prime}\right)\) (e) \(P\left[(A \cup B)^{\prime}\right]\) (f) \(P\left(A^{\prime} \cup B\right)\)

Short Answer

Expert verified
(a) 0.7, (b) 0.4, (c) 0.1, (d) 0.2, (e) 0.6, (f) 0.8

Step by step solution

01

Calculate Complement Probability P(A')

The complement of an event A, denoted as \(A^{\prime}\), is given by \(P(A^{\prime}) = 1 - P(A)\). We know that \(P(A) = 0.3\). Therefore,\[P(A^{\prime}) = 1 - 0.3 = 0.7\].
02

Calculate Union Probability P(A ∪ B)

Use the formula for the union of two events: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\). Substituting the given probabilities:\[P(A \cup B) = 0.3 + 0.2 - 0.1 = 0.4\].
03

Calculate P(A' ∩ B)

Since \(A^{\prime} \cap B\) means B occurs and A does not, use \(P(A^{\prime} \cap B) = P(B) - P(A \cap B)\). Given \(P(B) = 0.2\) and \(P(A \cap B) = 0.1\), we find:\[P(A^{\prime} \cap B) = 0.2 - 0.1 = 0.1\].
04

Calculate P(A ∩ B')

For \(A \cap B^{\prime}\), A occurs and B does not. Apply \(P(A \cap B^{\prime}) = P(A) - P(A \cap B)\). With \(P(A) = 0.3\) and \(P(A \cap B) = 0.1\):\[P(A \cap B^{\prime}) = 0.3 - 0.1 = 0.2\].
05

Calculate Complement of Union P((A ∪ B)')

The complement of \(A \cup B\) is \((A \cup B)^{\prime}\), calculated as \(P((A \cup B)^{\prime}) = 1 - P(A \cup B)\). From Step 2, \(P(A \cup B) = 0.4\), so:\[P((A \cup B)^{\prime}) = 1 - 0.4 = 0.6\].
06

Calculate P(A' ∪ B)

Use De Morgan's Laws: \(A^{\prime} \cup B = (A \cap B^{\prime})^{\prime}\), so \(P(A^{\prime} \cup B) = 1 - P(A \cap B^{\prime})\). From Step 4, \(P(A \cap B^{\prime}) = 0.2\):\[P(A^{\prime} \cup B) = 1 - 0.2 = 0.8\].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Complementary Events
In probability, complementary events are crucial to understand as they deal with scenarios where one event does not occur. If you have an event, say **A**, its complement, denoted as \(A^{\prime}\), represents all outcomes where the event **A** does not happen. The probability of the complement can be determined using the formula:
  • \(P(A') = 1 - P(A)\)
This formula captures the idea that the total probability for any given event and its complement must sum up to 1. For instance, if the probability of rain today is 0.3 (or 30%), then the probability of it not raining, or \(P(A')\), would be 70%. This simple yet powerful idea helps solve several probability problems by providing a straightforward method to find the probability of an event not happening.
Union of Events
The union of events is a concept that describes the probability of either one event, another event, or both occurring at the same time. For two events, **A** and **B**, the union is denoted by \(A \cup B\), and its probability is given by:
  • \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\)
This equation accounts for the overlap between **A** and **B** because counting it twice would inflate the probability. Think of it like two overlapping circles (or sets), where you add the probability of both but subtract the intersection that was counted to ensure accuracy. For example, if there's a 30% chance it will rain and a 20% chance of a public holiday, and they overlap 10% of the time, the formula ensures that the two events don't double-count their intersection.
Intersection of Events
The intersection of events pertains to the likelihood of both events occurring simultaneously. When you have two events, **A** and **B**, the intersection is denoted by \(A \cap B\). This represents the outcomes that both **A** and **B** share similar, much like the overlap in a Venn diagram. If you're calculating the probability of an intersection, you'll often rely on provided data such as \(P(A \cap B)\), which is sometimes derived from past data or experiments. Understanding intersections is vital when multiple criteria must be true for an event to occur, like pulling a red card from a standard deck and ensuring it's also a face card. This is a foundational concept in many probabilistic calculations for complex events.
De Morgan's Laws
De Morgan's Laws are essential tools when working with probabilities, particularly with complements and unions/intersections of events. These laws provide a way to transform intersections into unions and vice versa, involving complements. The two laws are:
  • \((A \cup B)' = A' \cap B'\)
  • \((A \cap B)' = A' \cup B'\)
These equations simplify problems by converting an event and its complement into an alternative form that's often easier to work with. For example, if you are tasked with finding the probability of neither **A** nor **B** happening, De Morgan's Laws allow you to reformulate it to understand better and compute it using the probabilities of their individual complements. This ability to switch perspectives from direct computation to using complements leverages known probabilities to solve for what's unknown.

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Most popular questions from this chapter

A Web ad can be designed from four different colors, three font types, five font sizes, three images, and five text phrases. A specific design is randomly generated by the Web server when you visit the site. Let \(A\) denote the event that the design color is red and let \(B\) denote the event that the font size is not the smallest one. Use the addition rules to calculate the following probabilities. (a) \(P(A \cup B)\) (b) \(P\left(A \cup B^{\prime}\right)\) (c) \(P\left(A^{\prime} \cup B^{\prime}\right)\)

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