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An inspector working for a manufacturing company has a \(99 \%\) chance of correctly identifying defective items and a \(0.5 \%\) chance of incorrectly classifying a good item as defective. The company has evidence that its line produces \(0.9 \%\) of nonconforming items. (a) What is the probability that an item selected for inspection is classified as defective? (b) If an item selected at random is classified as nondefective, what is the probability that it is indeed good?

Short Answer

Expert verified
(a) 0.0139 (b) 0.995

Step by step solution

01

Define events and given probabilities

Let's define the events: \(D\) is the event that an item is defective, \(ND\) is the event that an item is non-defective, \(C_d\) is the event that an item is classified as defective, and \(C_{nd}\) is the event that an item is classified as non-defective. We are given: \(P(D)=0.009\), \(P(C_d|D)=0.99\), \(P(C_d|ND)=0.005\), and \(P(ND)=1-P(D)=0.991\).
02

Calculate the probability of being classified as defective

We need \(P(C_d)\). Using the law of total probability, we sum the probabilities of classifying both defective and non-defective items as defective: \[P(C_d) = P(C_d|D)P(D) + P(C_d|ND)P(ND)\] Plug in the values: \[P(C_d) = (0.99)(0.009) + (0.005)(0.991)\] Solve: \[P(C_d) = 0.00891 + 0.004955 = 0.013865\]
03

Calculate the probability that a non-defective item is actually good

We need \(P(ND|C_{nd})\) which is the probability that an item is non-defective given that it is classified as non-defective. Using Bayes’ theorem: \[P(ND|C_{nd}) = \frac{P(C_{nd}|ND)P(ND)}{P(C_{nd})} = \frac{(1 - P(C_d|ND))P(ND)}{1 - P(C_d)}\] Calculate \(P(C_{nd}|ND)\): \(P(C_{nd}|ND) = 1 - P(C_d|ND) = 0.995\). Now substitute values into Bayes’ theorem: \[P(ND|C_{nd}) = \frac{(0.995)(0.991)}{0.986135} \] Solve: \[P(ND|C_{nd}) \approx 0.995 \]
04

Conclusion

For part (a), the probability an item is classified as defective is \(0.0139\). For part (b), the probability that a classified non-defective item is indeed good is approximately \(0.995\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bayes' Theorem
In probability theory, Bayes' Theorem is a helpful tool to solve problems that involve conditional probabilities. It allows us to update our probability estimate for a hypothesis based on new evidence. This theorem is particularly useful in cases where we need to determine the likelihood of an event given that another event has already occurred. In this exercise, Bayes' theorem helps in calculating the probability that an item is actually non-defective, given it was classified as non-defective during inspection.

The formula for Bayes’ Theorem is:
  • \( P(A|B) = \frac{P(B|A)P(A)}{P(B)} \)
Where:
  • \( P(A|B) \) is the probability of event A occurring given B is true.
  • \( P(B|A) \) is the probability of event B given A is true.
  • \( P(A) \) and \( P(B) \) are the probabilities of events A and B independently.
In this context, it allows the inspector to ascertain how reliable the test classification is, based on the known probabilities.
Law of Total Probability
The Law of Total Probability is a fundamental rule related to probability calculations. It provides a way to break down complex probabilities into simpler components, allowing the calculation of a probability that depends on several mutually exclusive events. This law is key when we need to consider all possible paths that may lead to an outcome.

When inspecting manufactured items, this law helps calculate the probability of an item being classified as defective, regardless of whether it is actually defective or not. This is done by summing the probabilities of the item being correctly or incorrectly classified as defective.

The formula for the law is:
  • \( P(B) = P(B|A_1)P(A_1) + P(B|A_2)P(A_2) + ... + P(B|A_n)P(A_n) \)
Where:\( A_1, A_2, ... A_n \) are all the mutually exclusive events. By utilizing this law, the inspector can effectively determine the overall probability of classifying any given item as defective.
Statistical Quality Control
Statistical Quality Control (SQC) refers to the use of statistical methods to monitor and control a process. This ensures that a manufacturing process operates at its most efficient level, producing fewer defective items.

Using SQC allows manufacturers to maintain consistent quality and reduce waste by promptly identifying issues in the production process. This includes using techniques like sampling and inspection, which are crucial for industries reliant on maintaining strict quality standards.

In the context of the provided exercise, statistical quality control is applied through inspections to identify defective versus non-defective items. The probabilities of correct and incorrect classifications feed into the larger quality control system, informing decisions on necessary corrections and improvements.
Defective and Non-defective Classification
In manufacturing and quality control settings, a critical task is the classification of products as defective or non-defective. This classification is pivotal because it directly impacts customer satisfaction and production efficiency.

Defective items are those that do not meet the predefined standards or specifications, while non-defective items fulfill the required criteria. Accurate classification is essential to avoid distributing subpar products or wasting resources by rejecting good products.

In the exercise, items are subjected to inspection, where the probability calculations involve determining the likelihood of accurately classifying items as either defective or non-defective. The real-world implication is significant, as even a slight error in classification (like misclassifying good items) can lead to operational and reputational costs for the company. Effective classification processes mean a robust, reliable quality control system, reducing defects reaching end consumers.

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