Chapter 2: Problem 9
Solve Laplace's equation inside a \(90^{\circ}\) sector of a circular annulus
\((a
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Chapter 2: Problem 9
Solve Laplace's equation inside a \(90^{\circ}\) sector of a circular annulus
\((a
These are the key concepts you need to understand to accurately answer the question.
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Solve Laplace's equation inside a semicircle of radius \(a(0
Solve Laplace's equation inside the quarter-circle of radius \(1(0 \leqslant \theta \leqslant \pi / 2\), \(0 \leqslant r \leqslant 1\) ) subject to the boundary conditions: *(a) \(\frac{\partial u}{\partial \theta}(r, 0)=0, \quad u(r, \pi / 2)=0, \quad u(1, \theta)=f(\theta)\) (b) \(\frac{\partial u}{\partial \theta}(r, 0)=0, \quad \frac{\partial u}{\partial \theta}(r, \pi / 2)=0, \quad u(1, \theta)=f(\theta)\) *(c) \(u(r, 0)=0, \quad u(r, \pi / 2)=0, \quad \frac{\partial u}{\partial r}(1, \theta)=f(\theta)\) (d) \(\frac{\partial u}{\partial \theta}(r, 0)=0, \quad \frac{\partial u}{\partial \theta}(r, \pi / 2)=0, \quad \frac{\partial u}{\partial r}(1, \theta)-g(\theta)\) Show that the solution [part (d)] exists only if \(\int_{0}^{\pi / 2} g(\theta) d \theta=0\). Explain this condition physically.
Solve Laplace's equation inside a rectangle: $$ \nabla^{2} u=\frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0 $$ subject to the boundary conditions $$ \begin{aligned} u(0, y) &=g(y) & & u(x, 0)=0 \\ u(L, y) &=0 & & u(x, H)=0 \end{aligned} $$
Prove that the temperature satisfying L.aplace's equation cannot attain its minimum in the interior.
Show that any linear combination of linear operators is a linear operator.
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