Chapter 2: Problem 1
Solve the heat equation \(\partial u / \partial t=k \partial^{2} u / \partial
x^{2}, 0
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Chapter 2: Problem 1
Solve the heat equation \(\partial u / \partial t=k \partial^{2} u / \partial
x^{2}, 0
These are the key concepts you need to understand to accurately answer the question.
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Consider $$ \frac{\partial u}{\partial t}=k \frac{\partial^{2} u}{\partial x^{2}}-\alpha u . $$ This corresponds to a one-dimensional rod either with heat loss through the lateral sides with outside temperature \(0^{\circ}(\alpha>0\), see Exercise 1.2.4) or with insulated lateral sides with a heat source proportional to the temperature. Suppose that the boundary conditions are $$ u(0, t)=0 \quad \text { and } \quad u(L, t)=0 \text {. } $$ (a) What are the possible equilibrium temperature distributions if \(\alpha>0\) ? (b) Solve the time-dependent problem \([u(x, 0)=f(x)]\) if \(\alpha>0\). Analyze the temperature for large time \((t \rightarrow \infty)\) and compare to part (a).
If \(L\) is a linear operator, show that \(L\left(\sum_{n=1}^{M} c_{n} u_{n}\right)=\sum_{n=1}^{M} c_{n} L\left(u_{n}\right) .\) Use this result to show that the principle of superposition may be extended to any finite number of homogeneous solutions.
Solve Laplace's equation inside a rectangle: $$ \nabla^{2} u=\frac{\partial^{2} u}{\partial x^{2}}+\frac{\partial^{2} u}{\partial y^{2}}=0 $$ subject to the boundary conditions $$ \begin{aligned} u(0, y) &=g(y) & & u(x, 0)=0 \\ u(L, y) &=0 & & u(x, H)=0 \end{aligned} $$
Consider the heat equation
$$
\frac{\partial u}{\partial t}=k \frac{\partial^{2} u}{\partial x^{2}}
$$
subject to the boundary conditions
$$
\begin{aligned}
&u(0, t)=0 \\
&u(L, t)=0
\end{aligned}
$$
Solve the initial value problem if the temperature is initially
(a) \(u(x, 0)=6 \sin \frac{9 \pi x}{L}\)
(b) \(u(x, 0)=3 \sin \frac{\pi x}{L}-\sin \frac{3 \pi x}{L}\)
*(c) \(u(x, 0)=2 \cos \frac{3 \pi x}{L}\)
(d) \(u(x, 0)= \begin{cases}1 & 0
(a) Show that \(L(u)=\frac{\partial}{\partial x}\left[K_{0}(x) \frac{\partial u}{\partial x}\right]\) is a linear operator. (b) Show that usually \(L(u)=\frac{\partial}{\partial x}\left[K_{0}(x, u) \frac{\partial u}{\partial x}\right]\) is not a linear operator.
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