/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Find the indicated one-sided lim... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the indicated one-sided limit, if it exists. \(\lim _{x \rightarrow 0^{+}} f(x)\) and \(\lim _{x \rightarrow 0^{-}} f(x)\), where $$ f(x)=\left\\{\begin{array}{ll} -x+1 & \text { if } x \leq 0 \\ 2 x+3 & \text { if } x>0 \end{array}\right. $$

Short Answer

Expert verified
The one-sided limits for the given piecewise function are: \(\lim _{x \rightarrow 0^{-}} f(x) = 1\) and \(\lim _{x \rightarrow 0^{+}} f(x) = 3\).

Step by step solution

01

Find the limit as x approaches 0 from the negative side (-)

To find the limit as x approaches 0 from the left side, we will use the part of the function defined for \(x \leq 0\), which is \(f(x) = -x + 1\). We need to find \(\lim _{x \rightarrow 0^{-}} f(x)\). Since the function is continuous for values less than or equal to 0, we can plug in x=0 directly into the function to find the limit: \[ \lim _{x \rightarrow 0^{-}} f(x) = - (0) + 1 = 1 \]
02

Find the limit as x approaches 0 from the positive side (+)

To find the limit as x approaches 0 from the right side, we will use the part of the function defined for \(x > 0\), which is \(f(x) = 2x + 3\). We need to find \(\lim _{x \rightarrow 0^{+}} f(x)\). Since the function is continuous for values greater than 0, we can plug in x=0 directly into the function to find the limit: \[ \lim _{x \rightarrow 0^{+}} f(x) = 2(0) + 3 = 3 \]
03

Conclusion

The one-sided limits for the given function are: \(\lim _{x \rightarrow 0^{-}} f(x) = 1\) and \(\lim _{x \rightarrow 0^{+}} f(x) = 3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Piecewise Functions
Understanding piecewise functions is crucial as they allow us to describe situations where a function behaves differently based on the input value. In this type of function, different rules or expressions are used to calculate the output, based on specified conditions. A piecewise function is expressed using multiple sub-functions, each with its specific domain, which together form the overall function. Given the function:- For values where \(x \leq 0\), the function is defined as \(f(x) = -x + 1\). - For values where \(x > 0\), the function is defined as \(f(x) = 2x + 3\).These distinct definitions allow the function to express different patterns across particular domain segments. When approaching limits in piecewise functions, it's important to assess the function within the context of the specific interval. This ensures accurate analysis at points where the function's rule changes, which is especially relevant at boundaries like \(x = 0\) in this example. By comprehending the constituent parts of piecewise functions, students can better understand how to handle each distinct component during calculations.
Continuity
Continuity is a fundamental property of functions indicating how they behave at certain points and intervals. A function is termed continuous at a point if, intuitively speaking, you can draw it without lifting your pencil. This means there are no sudden jumps, breaks, or holes at that point.For piecewise functions, continuity often becomes a critical point of interest at boundaries where the function's behavior changes. For the given function:- The part \(-x + 1\) is defined for \(x \leq 0\), allowing evaluation directly at \(x = 0\).- The part \(2x + 3\) applies when \(x > 0\).In this case, when evaluating limits, examining both sides as they approach a boundary like \(x = 0\) can reveal a lack of continuity. Here, one-sided limits differ: approaching from the left gives a limit of 1, while from the right, it's 3. Since these limits don't equal, it indicates a discontinuity at \(x = 0\). Being able to identify and explore these nuances allows students to understand where functions are smooth and where they are not, which is crucial for solving higher-level calculus problems.
Limit Calculation
Calculating limits, especially one-sided limits, is essential for understanding function behavior as input values near specific points. Limits help to cast light on what values a function approaches, which is particularly useful when functions are not straightforward.To find one-sided limits:- For \(x \rightarrow 0^{-}\), the left-side limit uses \(-x + 1\). Direct substitution yields a limit of 1, as shown: \[ \lim _{x \rightarrow 0^{-}} f(x) = 1 \]- For \(x \rightarrow 0^{+}\), the right-side limit applies \(2x + 3\). Directly evaluating at \(0\), results in: \[ \lim _{x \rightarrow 0^{+}} f(x) = 3 \]These calculations, utilizing direct substitution where applicable, instantly reveal the approaching behavior of each function part. They exemplify how to confidently handle piecewise functions' boundaries, even if the ultimate conclusions, such as both-side limits, might signal discontinuity.Learning to accurately compute limits prepares students for more complex calculus concepts, providing strong foundational skills that extend beyond basic problems. Understanding the distinct values from checking both sides also enriches students' analysis techniques for various function types.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find an equation of the tangent line to the graph of the function at the given point. \(f(x)=\left(\frac{x+1}{x-1}\right)^{2} ;(3,4)\)

In Exercises 49-54, find \(\frac{d y}{d u^{\prime}} \frac{d u}{d x^{\prime}}\) and \(\frac{d y}{d x}\). \(y=u^{4 / 3}\) and \(u=3 x^{2}-1\)

CRUISE SHIP BookINGS The management of Cruise World, operators of Caribbean luxury cruises, expects that the percentage of young adults booking passage on their cruises in the years ahead will rise dramatically. They have constructed the following model, which gives the percentage of young adult passengers in year \(t\) : $$ p=f(t)=50\left(\frac{t^{2}+2 t+4}{t^{2}+4 t+8}\right) \quad(0 \leq t \leq 5) $$ Young adults normally pick shorter cruises and generally spend less on their passage. The following model gives an approximation of the average amount of money \(R\) (in dollars) spent per passenger on a cruise when the percentage of young adults is \(p\) : $$ R(p)=1000\left(\frac{p+4}{p+2}\right) $$ Find the rate at which the price of the average passage will be changing 2 yr from now.

Find the derivative of each function. \(f(u)=(2 u+1)^{3 / 2}+\left(u^{2}-1\right)^{-3 / 2}\)

AIR PoLLuTION According to the South Coast Air Quality Management District, the level of nitrogen dioxide, a brown gas that impairs breathing, present in the atmosphere on a certain May day in downtown Los Angeles is approximated by $$ A(t)=0.03 t^{3}(t-7)^{4}+60.2 \quad(0 \leq t \leq 7) $$ where \(A(t)\) is measured in pollutant standard index and \(t\) is measured in hours, with \(t=0\) corresponding to 7 a.m.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.