/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 Find the indicated one-sided lim... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the indicated one-sided limit, if it exists. \(\lim _{x \rightarrow 2^{+}} \frac{x+1}{x^{2}-2 x+3}\)

Short Answer

Expert verified
The one-sided limit from the positive side exists and is equal to 1: \[\lim _{x \rightarrow 2^{+}} \frac{x+1}{x^{2}-2 x+3} = 1\]

Step by step solution

01

Factor the denominator (if possible)

In this case, the denominator is a quadratic function, \(x^{2}-2 x+3\). Let's try to factor it: The factors of 3 are (1, 3). Since the middle term is -2x, we need to find pairs that subtract to produce -2. None of these factors satisfy this condition, which means the denominator cannot be factored any further.
02

Simplify the function (if possible)

Since we couldn't factor the denominator, there are no common factors between the numerator and the denominator to be canceled or simplified. Hence, our function remains as-is: \[\frac{x+1}{x^{2}-2 x+3}\]
03

Analyze the function as x approaches 2 from the positive side

We need to find the limit: \[\lim _{x \rightarrow 2^{+}} \frac{x+1}{x^{2}-2 x+3}\] As x approaches 2 from the positive side, let's see what happens to the numerator and the denominator: Numerator: \(x + 1\) As x approaches 2, the numerator approaches 2 + 1 = 3. Denominator: \(x^{2} - 2x + 3\) As x approaches 2, the denominator approaches \(2^{2} - 2(2) + 3 = 4 - 4 + 3 = 3\).
04

Calculate the limit (if it exists)

As x approaches 2 from the positive side, the numerator approaches 3, and the denominator approaches 3. Therefore, the function approaches the value: \[\frac{3}{3} = 1\] Thus, the one-sided limit from the positive side exists and is equal to 1: \[\lim _{x \rightarrow 2^{+}} \frac{x+1}{x^{2}-2 x+3} = 1\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Factoring Quadratics
Quadratic expressions are functions that we can typically rewrite in the form of \( ax^2 + bx + c \), where \( a \), \( b \), and \( c \) are constants. Sometimes, we can factor these expressions to simplify them. Factoring means finding two parentheses (binomials) that can multiply to give the original expression.
  • **Example:** If you have \( x^2 - 4x + 4 \), you can factor it as \((x - 2)(x - 2)\) or \((x - 2)^2\).
  • Factors are integers that, when multiplied, produce the original constant \( c \). For instance, in \( x^2 - 4x + 4 \), the factors of \( 4 \) are \( (2,2) \) because\( 2 \times 2 = 4 \).
In some cases, like in our solution, the quadratic cannot be factored into simpler terms.When this occurs, it means that using factors won't help simplify the expression further.There are no integer numbers that satisfy the factor condition for the middle term\(-2x\). Breaking down complex quadratics by evaluating their components is crucialfor further analysis in limiting processes.
Calculating Limits
Calculating limits involves determining what value a function approaches as\( x \) moves closer to a specific number. In our case, we are checking the expression \( \lim _{x \rightarrow 2^{+}} \frac{x+1}{x^2-2x+3} \). This expression checks how the function behaves when approaching \( x = 2 \) fromthe right side, or as \( x \) becomes slightly larger than \( 2 \).
The process involves:
  • **Substitution**: Replace \( x \) with values very close to the targeted number (here, \( 2 \)). Directly substituting \( x = 2 \) gives us an idea of how the function behaves exactly at that point, if not undefined.
  • **Approaching Values**: As \( x \) trends to 2 from positive values, bothnumerator and denominator approach specific values. In our scenario,the numerator trends towards 3, and the denominator becomes 3. Thus,\( \frac{3}{3} = 1 \)
This limit calculation proves the function equates to \( 1 \) when approaching\( 2 \) from the positive side, indicating the function's behavior around thatlimit.
Denominator Simplification
Simplifying the denominator is crucial when evaluating limits if the expression feels complex. This involves both factoring strategies and also attempting direct simplification.
  • **Why Simplify?**: Simplicity allows recognizing common trends in expressions, which can sometimes make complex calculations more intuitive.
  • In the given exercise's quadratic \( x^{2}-2x+3 \), no communities offactors simplify to detract any terms. Recognizing the primal natureof expressions helps deduce that any further division can't integrate in this scenario,allowing for a quick conclusion: \( \frac{3}{3} \) after correctly handling efficiencies.
While the denominator \( x^{2}-2x+3 \) remained as is, having triedfactoring initially ensured the expression was at its simplest in termsof potentially canceled common factors. This preparation confirmedthere were no further actions needed for simplification in evaluating the limit.

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Most popular questions from this chapter

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