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Find the derivative of each function. \(f(x)=\frac{x^{2}+2}{x^{2}+x+1}\)

Short Answer

Expert verified
\(f'(x) = \frac{-x^2 - 2x}{(x^2 + x + 1)^2}\)

Step by step solution

01

Identify the numerator and the denominator functions

Identify the numerator: \[u(x) = x^2 + 2\] And the denominator: \[v(x) = x^2 + x + 1\]
02

Find the derivatives of the numerator and the denominator

Differentiate the numerator function with respect to x: \[u'(x) = \frac{d}{dx}(x^2 + 2) = 2x\] Differentiate the denominator function with respect to x: \[v'(x) = \frac{d}{dx}(x^2 + x + 1) = 2x + 1\]
03

Apply the quotient rule

Apply the quotient rule: \[f'(x) = \frac{u'(x)v(x) - u(x)v'(x)}{(v(x))^2}\] Substitute the functions and their derivatives: \[f'(x) = \frac{(2x)(x^2 + x + 1) - (x^2 + 2)(2x + 1)}{(x^2 + x + 1)^2}\]
04

Simplify the expression

Simplify the numerator by performing the operations: \[f'(x) = \frac{(2x^3 + 2x^2 + 2x) - (2x^3 + x^2 + 4x + 2)}{(x^2 + x + 1)^2}\] Now, combine like terms in the numerator: \[f'(x) = \frac{-x^2 - 2x}{(x^2 + x + 1)^2}\] This is the derivative of the given function.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quotient Rule
Understanding how to find the derivative of a function when it is a fraction of two functions is crucial in calculus. This process is handled by the quotient rule, which is a fundamental technique for differentiation. In essence, the quotient rule is applied when you have a function that can be expressed as the quotient of two other functions, which in this case are denoted by the numerator function, \(u(x)\), and the denominator function, \(v(x)\).

The quotient rule states that the derivative of \(u(x) / v(x)\) is:\[f'(x) = \frac{\text{derivative of numerator function} \times \text{denominator function} - \text{numerator function} \times \text{derivative of denominator function}}{(\text{denominator function})^2}\]This rule is particularly useful because it simplifies what could be a complex limit process into a formula that can be straightforwardly applied. While using the quotient rule, it's essential to keep track of the numerator and denominator functions, as well as their derivatives, to correctly apply the formula.

For our example function \(f(x) = \frac{x^2 + 2}{x^2 + x + 1}\), identifying \(u(x)\) and \(v(x)\), and then finding their derivatives \(u'(x)\) and \(v'(x)\), sets the stage for using the quotient rule appropriately to determine the derivative \(f'(x)\).
Differentiation
Differentiation is the process of determining the rate at which a function is changing at any given point, which in mathematical terms is finding the derivative of the function. The derivative itself represents the slope of the tangent line to the curve of the function at a particular point. One can think of differentiation as a way to quantify how sensitive a function's output is to a change in its input value.

There are numerous rules to aid in differentiation, such as the power rule, chain rule, and the previously mentioned quotient rule. In the power rule, for example, if you have \(x^n\), its derivative is \(nx^{n-1}\). This basic rule was applied to both the numerator and denominator functions in the initial steps of our exercise to obtain \(u'(x)\) and \(v'(x)\).

The incorporation of these rules allows for the systematic computation of derivatives. By recognizing the form of the function \(f(x)\), whether it be a power, product, quotient, or another familiar shape, the appropriate rule can be selected and applied to find \(f'(x)\). In calculus, mastering the art of differentiation is foundational as it applies to almost every aspect of the subject, from simple curve sketching to solving complex differential equations.
Simplifying Expressions
Once the derivative of a function has been found using rules for differentiation, the resulting expression may need to be simplified to make it clear and more easily usable. Simplifying an expression involves combining like terms, factoring, expanding, and reducing fractions when possible. This process can reveal further insights into the function's behavior and make subsequent calculations more manageable.

In our solution, after applying the quotient rule, we're left with a complex expression for \(f'(x)\) that can be further simplified by combining like terms. Simplification is a careful and sometimes tedious process that involves attention to detail in arithmetic, keeping track of both positive and negative signs, and properly combining terms with the same variables and exponents.

The outcome of simplifying the expression for our problem, \(f'(x) = \frac{(2x^3 + 2x^2 + 2x) - (2x^3 + x^2 + 4x + 2)}{(x^2 + x + 1)^2}\), results in a cleaner version, \(f'(x) = \frac{-x^2 - 2x}{(x^2 + x + 1)^2}\). This methodical reduction allows for a greater understanding of the derivative's behavior and, in some cases, can also provide insights into the critical points and inflection points of the original function.

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Most popular questions from this chapter

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