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Find the derivative of each function. \(f(x)=\left(x^{2}+1\right)^{3}-\left(x^{3}+1\right)^{2}\)

Short Answer

Expert verified
The short answer for the derivative of \(f(x) = \left(x^{2}+1\right)^{3} - \left(x^{3}+1\right)^{2}\) is: \[f'(x) = 6x(x^2+1)^2 - 6x^2(x^3+1)\]

Step by step solution

01

Identify the terms and apply the chain rule

The given function is: \[f(x) = (x^{2}+1)^{3} - (x^{3}+1)^{2}\] The function has two terms: \( (x^{2}+1)^{3}\) and \(-(x^{3}+1)^{2}\). We'll use the chain rule to differentiate each term separately. The chain rule states that: \[\frac{d}{dx}\left[ u(v(x)) \right] = u'(v(x)) \cdot v'(x)\] where \(u\) is an outer function and \(v(x)\) is an inner function.
02

Differentiate the first term

For the first term, \((x^{2}+1)^{3}\), we have: Outer function: \(u(v) = v^3\) Inner function: \(v(x) = x^2 + 1\) Now we find the derivatives of the outer and inner functions: \(u'(v) = 3v^2\) \(v'(x) = \frac{d}{dx}(x^2+1) = 2x\) Applying the chain rule: \[\frac{d}{dx}\left[ (x^{2}+1)^{3} \right] = u'\left(v(x)\right) \cdot v'(x) = 3\left(x^2+1\right)^2 \cdot 2x\]
03

Differentiate the second term

For the second term, \(-(x^{3}+1)^{2}\), we have: Outer function: \(u(v) = -v^2\) Inner function: \(v(x) = x^3 + 1\) Now we find the derivatives of the outer and inner functions: \(u'(v) = -2v\) \(v'(x) = \frac{d}{dx}(x^3+1) = 3x^2\) Applying the chain rule: \[\frac{d}{dx}\left[ -(x^{3}+1)^{2} \right] = u'\left(v(x)\right) \cdot v'(x) = -2\left(x^3+1\right) \cdot 3x^2\]
04

Combine the derivatives of the terms

Now combine the derivatives of the two terms to find the derivative of the whole function: \[\frac{d}{dx}\left[ f(x) \right] = \frac{d}{dx}\left[ (x^{2}+1)^{3} \right] - \frac{d}{dx}\left[ (x^{3}+1)^{2} \right]\] \[\frac{d}{dx}f(x) = 3\left(x^2+1\right)^2 \cdot 2x - 2\left(x^3+1\right) \cdot 3x^2\] The derivative of the given function, \(f'(x)\), is: \[f'(x) = 6x(x^2+1)^2 - 6x^2(x^3+1)\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Derivative Chain Rule
Understanding the derivative chain rule is essential for tackling complex differentiation problems. It's like having a secret decoder for nested functions, where each function is wrapped inside another. Imagine you're dealing with a Russian nesting doll, with layers of functions instead of wooden figures. The chain rule helps you to differentiate these layers one by one.

Let's say you have a function wrapped inside another function, which in technical terms means you have an outer function (let's call it 'u') and an inner function (v(x)). The chain rule tells you that the derivative of this combined function is the derivative of the outer function with respect to the inner function, multiplied by the derivative of the inner function with respect to x. In mathematical speak, for any function u(v(x)), the chain rule is expressed as \[\frac{d}{dx}u(v(x)) = u'(v(x)) \cdot v'(x)\] It's like peeling an onion, layer by layer, to get to the core. In practice, this rule is a lifesaver for functions that aren't straightforward to differentiate.
Derivative of a Function
In calculus, the derivative of a function is the cornerstone concept that measures how a function changes as its input changes. Loosely speaking, it's the rate of change or the slope of the function at any given point. Think of it as a snapshot of a rocket's speedometer at a precise moment during its flight - it tells you how fast the rocket is accelerating or decelerating at that instant.

In more formal terms, if you have a function f(x) and you want to know its derivative at a point x, you're looking at the function's instantaneous rate of change at that point. This is usually denoted as f'(x) for the derivative of f in terms of x. Applying this to our function from the textbook example, the overall derivative is a combination of the derivatives of its parts, signifying how each individual component's rate of change contributes to the whole.
Power Rule Differentiation
The power rule is one of the simplest and most powerful tools in your differentiation toolkit. It allows you to take the derivative of any function that can be written in the form f(x) = x^n, where n is any real number. If you're scaling a mountain, the power rule is your trusty grappling hook that helps you easily climb straight up steep cliffs of exponential functions.

Applying the power rule is straightforward: to find the derivative of f(x) = x^n, you simply multiply by the exponent n and then subtract 1 from the exponent. Mathematically, this is expressed as \[\frac{d}{dx}x^n = nx^{n-1}\] For example, if your function is f(x) = x^3, the derivative is f'(x) = 3x^(3-1) or simply 3x^2. When combined with the chain rule, as seen in our textbook example, the power rule enables you to differentiate more complex expressions involving powers neatly and efficiently.

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Most popular questions from this chapter

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