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Find the derivative of each function. \(f(t)=\sqrt{3 t^{2}-t}\)

Short Answer

Expert verified
The derivative of the function \(f(t) = \sqrt{3t^2 - t}\) is: \[f'(t) = \frac{6t - 1}{2\sqrt{3t^2 - t}}\]

Step by step solution

01

Identify the outer and inner functions

In this case, the outer function is the square root, which we can rewrite as a power of 1/2: \[f(t) = (3t^2 - t)^{1/2}\] The inner function is the polynomial inside the square root: \(g(t) = 3t^2 - t\)
02

Find the derivatives of the outer and inner functions

First, find the derivative of the outer function with respect to its argument, using the power rule: \[\frac{df(u)}{du} = \frac{1}{2}u^{-1/2} = \frac{1}{2}u^{-1/2}\] where u is a placeholder for the inner function. Next, find the derivative of the inner function with respect to t: \[\frac{dg(t)}{dt} = \frac{d(3t^2 - t)}{dt} = 6t - 1\]
03

Use the chain rule to find the derivative of the original function

The chain rule states that the derivative of a composite function is the product of the derivative of the outer function and the derivative of the inner function, or in our case: \[\frac{df(t)}{dt} = \frac{df(u)}{du} \times \frac{dg(t)}{dt}\]
04

Substitute the expressions found in Step 2 into the chain rule formula

Replace \(u\) with the inner function \(g(t)\), and substitute the derivatives found in Step 2: \[\frac{df(t)}{dt} = \left(\frac{1}{2}(3t^2 - t)^{-1/2}\right) \times (6t - 1)\]
05

Simplify the final expression

Now, we need to simplify the expression to find the final derivative of the original function: \[\frac{df(t)}{dt} = \frac{1}{2}(3t^2 - t)^{-1/2} \times (6t - 1) = \frac{6t - 1}{2\sqrt{3t^2 - t}}\] The derivative of the function \(f(t) = \sqrt{3t^2 - t}\) is: \[f'(t) = \frac{6t - 1}{2\sqrt{3t^2 - t}}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chain Rule
The chain rule is a fundamental concept in calculus, especially when you deal with composite functions. A composite function is essentially a function within another function. For instance, in our exercise, the function \(f(t)=\sqrt{3t^2-t}\) is composed of two functions: the outer square root function and the inner polynomial function \(3t^2-t\).
The chain rule helps us find the derivative of such composite functions efficiently. It states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function, times the derivative of the inner function itself. In simple terms:
  • Differentiate the outer function.
  • Evaluate it with the inner function unchanged.
  • Multiply this result by the derivative of the inner function.
Using this rule is crucial as it compartmentalizes derivative calculation, making it methodical and error-free. Remember, the chain rule formula is neatly expressed as:\[\frac{d}{dx} f(g(x)) = f'(g(x)) \cdot g'(x)\] This methodical approach simplifies even the most tangled functions.
Power Rule
The power rule is a straightforward and commonly used rule in calculus to find the derivative of functions expressed as powers of \(x\). It states that if you have a function \(f(x) = x^n\), the derivative will be \(f'(x) = nx^{n-1}\). In the exercise, we initially rewrote the square root function as a power: \(f(t) = (3t^2 - t)^{1/2}\). By doing so, applying the power rule becomes more apparent, and it aids in the stepwise differentiation process.
  • Determine the power of the expression.
  • Multiply by the power.
  • Decrease the power by one.
This process gives us the derivative of the outer function with respect to its argument, which in this case was \((3t^2 - t)\). The power rule is essential for breaking down complexities into manageable parts, simplifying tasks like employing the chain rule further down the line.
Outer and Inner Functions
Identifying outer and inner functions is a critical step when using the chain rule. It involves a keen look at the structure of your function to separate it into layers.
In the provided exercise, we define:
  • The outer function as the square root, \(f(u) = u^{1/2}\), after rewriting the original square root as a power for easier differentiation.
  • The inner function is the polynomial \(g(t) = 3t^2 - t\) that resides within the outer square root function.
Understanding which part is your inner function and which is your outer function smooths the way for applying the chain rule. It ensures each part is correctly differentiated. This layered understanding decouples complex function differentiation into simpler tasks, thereby reducing potential mistakes during calculations.

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Most popular questions from this chapter

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