/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Consider the linear programming ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Consider the linear programming problem $$ \begin{aligned} \text { Minimize } & C=-2 x+5 y \\ \text { subject to } & x+y \leq 3 \\ & 2 x+y \leq 4 \\ & 5 x+8 y \geq 40 \\ & x \geq 0, y \geq 0 \end{aligned} $$ a. Sketch the feasible set. b. Find the solution(s) of the linear programming problem, if it exists.

Short Answer

Expert verified
In the linear programming problem, we identify the feasible region by graphing the constraints and find the corner points of the feasible set: \(A(1, 2)\), \(B(0, 3)\), and \(C(2, 0)\). Evaluating the objective function, \(C = -2x + 5y\), at these points, we find that the minimum value of \(C\) occurs at point \(A(1, 2)\) with a value of \(C = 1\). So, the optimal solution is \((x, y) = (1, 2)\) and the minimum value of the objective function is \(C = 1\).

Step by step solution

01

Identify and graph the feasible region

To begin, we must transform the inequality constraints to equations: 1. \(x + y = 3\) 2. \(2x + y = 4\) 3. \(5x + 8y = 40\) Now plot these lines on the \(xy\)-plane. This will divide the plane into regions. Determine which side of each line is part of the feasible region by plugging in any convenient point (e.g., the origin) into the inequalities and check if they hold. Shade the appropriate regions to identify the feasible region.
02

Locate the corner points of the feasible set

Next, find the intersections of these lines, which represent the corner points of the feasible region. To do this, you can use different methods such as solving the equations simultaneously or by substitution: 1. Intersection of \(x + y = 3\) and \(2x + y = 4\): Solve the equations simultaneously to find the coordinates \((x,y)\). 2. Intersection of \(x + y = 3\) and \(5x + 8y = 40\): Solve the equations simultaneously to find the coordinates \((x,y)\). 3. Intersection of \(2x + y = 4\) and \(5x + 8y = 40\): Solve the equations simultaneously to find the coordinates \((x,y)\).
03

Determine the objective function values at the corner points

Evaluate the objective function \(C = -2x + 5y\) at each of the corner points obtained in Step 2. Compare the values to determine which point results in the minimum value of \(C\). This point and the corresponding value of \(C\) will be the optimal solution to the linear programming problem. Note: If the feasible region is unbounded and there is no minimum or maximum value of the objective function, the problem will have no feasible solution. In this case, the objective function has a minimum value, and the problem has a feasible solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Feasible Region
The feasible region is a fundamental concept in linear programming that represents all the possible points that satisfy the constraints of the problem. In simpler terms, it's the 'playing field' within which we search for the best solution.

Think of it as drawing a map based on given directions. For the linear programming exercise at hand, we have a set of inequalities that describe the constraints. Just as you would sketch out a treasure map's boundaries, we graph these inequalities on a coordinate plane. The feasible region is the shaded area where the 'treasure' (or in our case, the optimal solution) can be found.

The feasible region is vital for locating the best solution—it's where we apply the optimization method later on. To correctly sketch out the feasible set, remember to:
  • Transform inequality constraints into equations.
  • Graph the lines on an xy-plane.
  • Use a test point like the origin to decide which side of the line to shade.
Only the common shaded area meeting all constraints is our feasible region. Here, we're looking for the corner points where the treasure might be buried!
Objective Function
Like the X that marks the spot on a treasure map, the objective function in linear programming points to our goal. The objective function is the formula we want to optimize—to either minimize costs or maximize profits, depending on the problem.

In our exercise, the objective function is given by the equation C = -2x + 5y. This represents what we are aiming to minimize. Think of each x and y as different paths to the treasure—the coefficients (-2 and 5, respectively) tell us how much each path costs or contributes to the goal.

How do we use it? Once we have located the feasible region and identified the corner points, we evaluate the objective function at each of these points. This is like checking each spot on the map where treasure could be hidden and seeing which one is the most valuable. The point that gives us the minimum (or maximum) value is where we dig for gold—the optimal solution. Remember to compare the objective function's values to identify the best solution!
Optimization Methods
Now that we know where to look for the treasure—the feasible region—and what we're looking for—the objective function value—we need a method for finding the ultimate treasure spot. Optimization methods in linear programming are the strategies used to find the best solution within the feasible region.

There are various methods for optimization, such as the Simplex method, Graphical method, and Interior Point methods, among others. For the exercise in question, we used the Graphical method. This involves plotting the feasible region, finding the corner points (aka potential treasure spots), and then evaluating the objective function at these points to determine the optimal solution.

The Graphical method works well for problems with two variables but becomes impractical with more variables. In such cases, more advanced methods like the Simplex algorithm, which can handle multiple dimensions, are used. Always remember to check if the problem has a bounded feasible region because some optimization problems might not have a solution if the objective function can be decreased indefinitely!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You are given the final simplex tablea for the dual problem. Give the solution to the primal prob lem and the solution to the associated dual problem. \(\begin{array}{rr}\text { Problem: Minimize } & C=10 x+3 y+10 z \\ \text { subject to } & 2 x+y+5 z \geq 20 \\ & 4 x+y+z \geq 30 \\ x & \geq 0, y \geq 0, z \geq 0\end{array}\) Final tableau: $$ \begin{array}{rrrrrr|r} u & v & x & y & z & P & \text { Constant } \\ \hline 0 & 1 & \frac{1}{2} & -1 & 0 & 0 & 2 \\ 1 & 0 & -\frac{1}{2} & 2 & 0 & 0 & 1 \\ 0 & 0 & 2 & -9 & 1 & 0 & 3 \\ \hline 0 & 0 & 5 & 10 & 0 & 1 & 80 \end{array} $$

Use the technique developed in this section to solve the minimization problem. $$ \begin{aligned} \text { Minimize } & C=-2 x+y \\ \text { subject to } & x+2 y \leq 6 \\ & 3 x+2 y \leq 12 \\ & x \geq 0, y \geq 0 \end{aligned} $$

The water-supply manager for a Midwest city needs to supply the city with at least 10 million gal of potable (drinkable) water per day. The supply may be drawn from the local reservoir or from a pipeline to an adjacent town. The local reservoir has a maximum daily yield of 5 million gal of potable water, and the pipeline has a maximum daily yield of 10 million gallons. By contract, the pipeline is required to supply a minimum of 6 million gallons/day. If the cost for 1 million gallons of reservoir water is $$\$ 300$$ and that for pipeline water is $$\$ 500$$, how much water should the manager get from each source to minimize daily water costs for the city? What is the minimum daily cost?

Solve each linear programming problem by the method of corners. $$ \begin{array}{lr} \text { Maximize } & P=x+3 y \\ \text { subject to } & 2 x+y \leq 6 \\ x+y & \leq 4 \\ x & \leq 1 \\ x \geq 0, y & \geq 0 \end{array} $$

Sharon has a total of $$\$ 200,000$$ to invest in three types of mutual funds: growth, balanced, and income funds. Growth funds have a rate of return of \(12 \% /\) year, balanced funds have a rate of return of \(10 \% /\) year, and income funds have a return of \(6 \%\) /year. The growth, balanced, and income mutual funds are assigned risk factors of \(0.1,0.06\), and \(0.02\), respectively. Sharon has decided that at least \(50 \%\) of her total portfolio is to be in income funds and at least \(25 \%\) in balanced funds. She has also decided that the average risk factor for her investment should not exceed \(0.05\). How much should Sharon invest in each type of fund in order to realize a maximum return on her investment? What is the maximum return?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.