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Bata Aerobics manufactures two models of steppers used for aerobic exercises. Manufacturing each luxury model requires \(10 \mathrm{lb}\) of plastic and \(10 \mathrm{~min}\) of labor. Manufacturing each standard model requires \(16 \mathrm{lb}\) of plastic and \(8 \mathrm{~min}\) of labor. The profit for each luxury model is $$\$ 40$$, and the profit for each standard model is $$\$ 30 .$$ If \(6000 \mathrm{lb}\) of plastic and 60 laborhours are available for the production of the steppers per day, how many steppers of each model should Bata produce each day in order to maximize its profit? What is the optimal profit?

Short Answer

Expert verified
Bata Aerobics should produce 600 luxury steppers and no standard steppers per day to maximize its profit. The optimal profit will be $24,000 per day.

Step by step solution

01

1. Identify the variables

Let \(x\) represent the number of luxury steppers and \(y\) represent the number of standard steppers.
02

2. Set up the objective function

The objective function represents the profit. The profit for each luxury model is \(40, and the profit for each standard model is \)30, so the total profit, P, can be written as: \(P = 40x + 30y\)
03

3. Set up the constraints

The constraints are based on the amounts of plastic and labor available: a) Plastic constraint: Each luxury model requires 10 lb of plastic, and each standard model requires 16 lb. Since there are 6000 lb of plastic available: \(10x + 16y \leq 6000\) b) Labor constraint: Each luxury model requires 10 minutes of labor, and each standard model requires 8 minutes. There are 60 labor hours available (3600 minutes): \(10x + 8y \leq 3600\) c) Non-negativity constraints: \(x \geq 0\) \(y \geq 0\)
04

4. Graph the feasible region

To graph the feasible region, we need to plot the constraints: a) For the plastic constraint, the line is: \(10x + 16y = 6000\) When \(x = 0\), \(y = 375\). When \(y = 0\), \(x = 600\). Plot these points and draw the line, shading towards the origin. b) For the labor constraint, the line is: \(10x + 8y = 3600\) When \(x = 0\), \(y = 450\). When \(y = 0\), \(x = 360\). Plot these points and draw the line, shading towards the origin. The feasible region is the area where the shaded regions overlap, including the axes due to the non-negativity constraints.
05

5. Determine the vertices of the feasible region

The vertices of the feasible region are where the constraint lines intersect, and the axes: Vertex 1: Intersection of plastic and labor lines: \(10x + 16y = 6000\) \(10x + 8y = 3600\) By solving the system of equations, we find: \(x = 120, y = 300\) Vertex 2: Intersection with the x-axis: \(x=600, y=0\) Vertex 3: Intersection with the y-axis: \(x=0, y=375\)
06

6. Test the vertices in the objective function

Evaluate the total profit at each vertex: Vertex 1: \(P = 40(120) + 30(300) = 4800 + 9000 = 13800\) Vertex 2: \(P = 40(600) + 30(0) = 24000\) Vertex 3: \(P = 40(0) + 30(375) = 11250\)
07

7. Find the optimal solution

The maximum profit occurs at Vertex 2. Thus, Bata should produce 600 luxury steppers and no standard steppers to maximize its profit, with the optimal profit being $24,000 per day.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Objective Function
The objective function in linear programming is like a formula that tells us what we want to achieve. In the case of Bata Aerobics, the aim is to maximize profit. Hence, the objective function represents how much money we can make based on the number of luxury and standard steppers produced.

For this problem, each luxury stepper sold brings a profit of \(40, and each standard stepper yields \)30. Thus, the objective function, denoted as \( P \) (standing for profit), is expressed as \( P = 40x + 30y \), where \( x \) is the number of luxury steppers and \( y \) is the number of standard steppers.

By using this objective function, we can calculate the total profit for any combination of \( x \) and \( y \). The goal is to find values of \( x \) and \( y \) that maximize the profit, subject to given constraints.
Constraints
Constraints are the limitations or restrictions that impact decision-making in linear programming. They define the feasible options available. In this context, Bata Aerobics faces constraints regarding the amount of resources available: plastic and labor.

There are two main constraints to consider:
  • Plastic Constraint: Each luxury model requires 10 lbs, and each standard model needs 16 lbs of plastic. With only 6000 lbs available, the constraint can be written as \( 10x + 16y \leq 6000 \).
  • Labor Constraint: Each luxury model demands 10 minutes, and each standard model takes 8 minutes of labor. Assuming 60 labor hours (or 3600 minutes) are available each day, the constraint can be expressed as \( 10x + 8y \leq 3600 \).
Furthermore, there are non-negativity constraints which state that the number of steppers produced cannot be negative, hence \( x \geq 0 \) and \( y \geq 0 \). Collectively, these constraints form the boundaries within which production must occur.
Feasible Region
The feasible region represents all possible combinations of luxury and standard steppers that can be produced, considering the constraints. It's like the "playground" of options we have.

To identify the feasible region, you plot each constraint on a graph. For example, by plotting the lines \( 10x + 16y = 6000 \) and \( 10x + 8y = 3600 \), you find their intersecting points and shade the region where all constraints overlap.

The non-negativity constraints ensure this region is bounded in the first quadrant, as both \( x \) and \( y \) must be non-negative. Within this feasible region lie potential solutions to the problem, and the optimal solution will always sit at one of the vertices (corners) of this area.
Optimal Solution
The optimal solution is the best choice among the feasible options, where the objective function reaches its highest value. In our exercise with Bata Aerobics, this means finding the combination of steppers that results in the maximum profit.

After graphing the feasible region, we pinpoint the vertices, which are calculated points where constraints intersect or where constraints meet the axes. For this scenario, the vertices were at: \((120, 300)\), \((600, 0)\), and \((0, 375)\). By substituting these points into the objective function \( P = 40x + 30y \), we assess the profit potential at each.

The calculations showed that the maximum profit of $24,000 was achieved at the vertex \((600, 0)\), meaning the best strategy for Bata would be to produce 600 luxury steppers and no standard steppers daily. Thus, the optimal solution directs decision-making by confirming which production strategy brings the greatest return.

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