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Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. A system of linear equations having more equations than variables has no solution, a unique solution, or infinitely many solutions.

Short Answer

Expert verified
The statement is true. A system of linear equations with more equations than variables can have no solution, a unique solution, or infinitely many solutions based on the presence of contradictory rows, every variable column being leading in the RREF, or having a free variable in the system, respectively.

Step by step solution

01

Possibilities for a system of linear equations

A system of linear equations can have: 1. No solution: This occurs when there is a contradiction among the equations. 2. A unique solution: This takes place when the system is consistent, and there is exactly one set of values for the variables that satisfy all the equations. 3. Infinitely many solutions: This happens when the system is consistent and has a free variable.
02

Systems with more equations than variables

Consider a system with more equations than variables. This means that the number of rows in the augmented matrix is more than the number of columns (not counting the constant column). Suppose we try to row reduce this augmented matrix to its reduced row-echelon form (RREF). Since there are more equations, at least one row must have a non-zero constant (otherwise, we could eliminate one row). If there is not at least one row that has all zeros before the constant, the system will be inconsistent, and there will be no solution. However, if there is at least one row with all zeros before the constant, we can continue to row reduce the system. If the system has a unique variable for every column, there will be a unique solution. But if there is a free variable in the system, there will be infinitely many solutions.
03

Conclusion

The statement, "A system of linear equations having more equations than variables has no solution, a unique solution, or infinitely many solutions," is true. This is because a system with more equations than variables can lead to: 1. No solution if there are contradictory rows in its RREF. 2. A unique solution if every variable column is leading in the RREF. 3. Infinitely many solutions if there is a free variable in the system.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

No Solution in Linear Systems
In the context of linear algebra, a system of equations may sometimes have no solutions. This situation is also known as an inconsistent system. It arises when the equations represent lines, planes, or hyperplanes that do not intersect at any point. For instance, two parallel lines that never meet are an example of a system with no solution.

Mathematically, in the augmented matrix of such a system, you would find at least one row where the coefficients of all the variables are zero, but the constant term is non-zero after applying row reduction techniques. This indicates that there's an equation like '0x + 0y = c' (where 'c' isn't zero), which is a contradiction. In simple terms, it's like saying '0 = 5', which is, of course, an impossible scenario and thus, no solution exists for the system.
Unique Solution in Linear Systems
A unique solution occurs when there is precisely one set of values for the variables in a linear system that satisfies all of the equations involved. If we were to visualize this solution graphically, the lines or planes represented by each equation would all intersect at a single point, which denotes the unique solution.

In technical terms, for a unique solution to exist, the system must be consistent, and the rank of the matrix (the number of non-zero rows in its row-echelon form) must equal the number of variables. No rows should consist entirely of zeros, and no variables can be 'free' - meaning that each has to correspond to a pivot position in the matrix after it has been reduced to the reduced row-echelon form (RREF).
Infinitely Many Solutions in Linear Systems
A fascinating aspect of linear systems is the scenario where there are infinitely many solutions. This occurs when the system is consistent, and at least one of the variables is not tied to a unique value—this variable is called a 'free variable.' Free variables can take an infinite range of values, and for each value, a corresponding set of solutions for the other variables can be found.

To offer a concrete example, consider a system where two planes intersect along a line; every point on that line is a solution to the system, thus there are infinitely many solutions. In terms of matrix algebra, a system has infinitely many solutions if, when you reduce its augmented matrix to RREF, at least one variable does not lead its own row, meaning it is free to take various values.
Reduced Row-Echelon Form (RREF)
The reduced row-echelon form (RREF) of a matrix is a style of matrix that satisfies certain criteria, making it fundamental for solving systems of linear equations. RREF is characterized by having each leading coefficient (also known as a pivot) equal to one, being the only non-zero entry in its column, and having every leading term to the right of any leading term in rows above. In essence, this form allows for the immediate reading of solutions if they exist, or identification of inconsistent systems or those with free variables.

To achieve RREF, one typically uses a sequence of elementary row operations: row swapping, row multiplication, and row addition. These operations are performed until the matrix meets the criteria for RREF. The end goal is to simplify the system to a point where the solutions, if any, are straightforward to obtain. The process of row reduction and achieving RREF is fundamental in understanding the nature of the system's solutions - be it no solution, a unique solution, or infinitely many solutions.

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Most popular questions from this chapter

Jackson Farms has allotted a certain amount of land for cultivating soybeans, corn, and wheat. Cultivating 1 acre of soybeans requires 2 labor-hours, and cultivating 1 acre of corn or wheat requires 6 labor-hours. The cost of seeds for 1 acre of soybeans is \(\$ 12\), for 1 acre of corn is \(\$ 20\), and for 1 acre of wheat is \(\$ 8\). If all resources are to be used, how many acres of each crop should be cultivated if the following hold? a. 1000 acres of land are allotted, 4400 labor-hours are available, and \(\$ 13,200\) is available for seeds. b. 1200 acres of land are allotted, 5200 labor-hours are available, and \(\$ 16,400\) is available for seeds.

Compute the indicated products. \(\left[\begin{array}{ll}0.1 & 0.9 \\ 0.2 & 0.8\end{array}\right]\left[\begin{array}{ll}1.2 & 0.4 \\ 0.5 & 2.1\end{array}\right]\)

Determine whether the statement is true or false. If it is true, explain why it is true. If it is false, give an example to show why it is false. When simple interest is used, the accumulated amount is a linear function of \(t\).

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The property damage claim frequencies per 100 cars in Massachusetts in the years 2000,2001 , and 2002 are \(6.88,7.05\), and \(7.18\), respectively. The corresponding claim frequencies in the United States are 4.13, \(4.09\), and \(4.06\), respectively. Express this information using \(2 \times 3\) matrix.

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