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The compound interest formula is a crucial tool for calculating how investments grow over time. In mathematical terms, the formula is represented as:\[A = P(1 + \frac{r}{n})^{nt}\]Where:

• \(A\) is the future value of the investment, or the amount of money accumulated after the stated time, including interest.
• \(P\) is the principal investment amount, which is the initial amount of money invested.
• \(r\) is the annual interest rate expressed in decimal form. For example, if the interest rate is 8%, \(r\) would be 0.08.
• \(n\) is the number of times interest is compounded per year. In the case of daily compounding, \(n\) would be 365.
• \(t\) is the time in years for which the money is invested or borrowed.

With this formula, we can predict how much an initial investment grows over time with compound interest. In this exercise, we're interested in finding out how long it will take until the investment triples.

Exponential equations involve variables as exponents. They often emerge in growth scenarios such as population growth, radioactive decay, and financial investments. In these equations, the variable is positioned in the exponent, making them uniquely challenging compared to linear or quadratic equations.
In our context, for the investment to triple, the final value \(A\) will be three times the initial investment \(P\), turning our compound interest equation into:\[3(5000) = 5000(1 + \frac{0.08}{365})^{365t}\]After simplifying, it becomes:\[3 = (1 + \frac{0.08}{365})^{365t}\]Exponential equations like this one are solved by isolating the variable on one side of the equation. In such cases, logarithms are employed to "bring down" the exponents to the level of the other operations.

Logarithms are essential for solving exponential equations where the variable is in the exponent. They help by allowing us to isolate the time variable \(t\) in the compound interest context.
Starting with the simplified exponential equation:\[3 = (1 + \frac{0.08}{365})^{365t}\]we apply a logarithm to both sides. Using a natural logarithm (\(\ln\)), as it's particularly effective for these types of calculations:\[\ln{3} = \ln{(1 + \frac{0.08}{365})^{365t}}\]This allows us to use the property \(\ln{(x^y)} = y\ln{x}\), bringing the exponent \(365t\) to the front:\[\ln{3} = 365t\ln{(1 + \frac{0.08}{365})}\]Now, we solve for \(t\) by dividing both sides by \(365\ln{(1 + \frac{0.08}{365})}\):\[t = \frac{\ln{3}}{365\ln{(1 + \frac{0.08}{365})}}\]Calculating this, we find out that \(t\) is approximately 13.94 years. Thus, it will take just under 14 years for the investment to triple under the given conditions.