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Use the laws of logarithms to solve the equation. $$\log _{3} x=2$$

Short Answer

Expert verified
To solve the logarithmic equation \(\log_3{x} = 2\), first convert it to an exponential equation using the property \(\log_b{a} = c \Leftrightarrow b^c = a \). This gives us \(3^2 = x\), which results in the solution \(x = 9\).

Step by step solution

01

Understand the logarithmic equation

We are given a logarithmic equation in the form of: \(\log_3{x} = 2\) Here, the base of the logarithm is 3, and we are trying to solve for x.
02

Convert the logarithmic equation to an exponential equation

Recall that a logarithmic equation with base b can be converted into an exponential equation as follows: \(\log_b{a} = c \Leftrightarrow b^c = a \) Using this property, we can rewrite our given equation as: \(3^2 = x\)
03

Solve for x

Now that we have the exponential equation, we can solve for x easily: \(3^2 = x\) \(x = 3^2\) \(x = 9\) So the solution for the given logarithmic equation \(\log_3{x} = 2\) is \(x = 9\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laws of Logarithms
Understanding the laws of logarithms is crucial in solving logarithmic equations. These laws help in simplifying expressions and converting logarithmic equations into exponential form, which can be easier to solve. There are three main laws:
  • Product Law: This states that the logarithm of a product is the sum of the logarithms of the factors. Expressed as: \(\log_b{(MN)} = \log_b{M} + \log_b{N}\).

  • Quotient Law: This law implies that the logarithm of a quotient is the difference of the logarithms. It is given by:\(\log_b{\left(\frac{M}{N}\right)} = \log_b{M} - \log_b{N}\).

  • Power Law: It asserts that the logarithm of a number raised to an exponent is the exponent times the logarithm of the number. Written as: \(\log_b{M^k} = k \cdot \log_b{M}\).
These fundamental laws are the backbone of manipulating and solving logarithmic equations. Knowing when and how to apply them makes handling complex logarithmic equations straightforward.
Exponential Equations
Exponential equations are equations where variables appear in the exponent. They are closely linked to logarithmic equations, as you can use one to solve the other. Understanding this connection is vital.

In exponential equations like \(b^c = a\), the base \(b\) is raised to the power \(c\) which results in \(a\). Converting a logarithmic equation to exponential form can make it simpler to find a solution. For example, the logarithmic equation \(\log_3{x} = 2\) converts to \(3^2 = x\). After conversion, solving for \(x\) is much more direct, as you simply calculate the power on the base.
  • Step 1: Identify the base and the exponent from the logarithmic form.
  • Step 2: Convert using the relation \(\log_b{a} = c \Leftrightarrow b^c = a\).
  • Step 3: Solve the resulting equation for the unknown variable.
Grasping the link between these two types of equations is essential in problem-solving, making it easier to switch forms and solve effectively.
Problem Solving in Mathematics
Problem solving in mathematics involves applying various concepts and methods to find solutions. For solving logarithmic equations, follow these strategies:

  • Understanding the Problem: Start by carefully reading the equation and identifying its components, such as the base and the unknowns.

  • Utilizing Known Concepts: Apply known properties and laws, like the laws of logarithms and the relationship between exponential and logarithmic equations, to manipulate and simplify the equation.

  • Logical Reasoning: Break down the problem into smaller, more manageable steps. Using logical sequences helps in systematically approaching the solution.
  • Verification: After obtaining a solution, verify by substituting it back into the original equation to ensure it satisfies all given conditions.
Engage in practice to become proficient at using these strategies, which will enhance your problem-solving skills in mathematics.

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