/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Let \(g\) be the function define... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(g\) be the function defined by \(g(u)=(3 u-2)^{3 / 2}\). Find \(g(1), g(6), g\left(\frac{11}{3}\right)\), and \(g(u+1)\)

Short Answer

Expert verified
g(1) = 1, g(6) = 64, g(11/3) = 27, g(u+1) = \((3u + 1)^{\frac{3}{2}}\)

Step by step solution

01

Evaluate g(1)

To find the value of g(1), we can plug in 1 for u in the given equation \(g(u)=(3u-2)^{\frac{3}{2}}\): \[g(1) = (3(1) - 2)^{\frac{3}{2}}\] \[g(1) = (3 - 2)^{\frac{3}{2}}\] \[g(1) = (1)^{\frac{3}{2}} = 1\]
02

Evaluate g(6)

Now let's find the value of g(6) by plugging in 6 for u: \[g(6)=(3(6)-2)^{\frac{3}{2}}\] \[g(6)=(18-2)^{\frac{3}{2}}\] \[g(6)=(16)^{\frac{3}{2}}\] \[g(6)= (2^4)^{\frac{3}{2}} = 2^{\frac{4\times3}{2}} = 2^6 = 64\]
03

Evaluate g(11/3)

Next, let's find the value of \(g\left(\frac{11}{3}\right)\) by plugging in \(\frac{11}{3}\) for u: \[g\left(\frac{11}{3}\right) = \left(3\left(\frac{11}{3}\right) - 2\right)^{\frac{3}{2}}\] \[g\left(\frac{11}{3}\right) = (11 - 2)^{\frac{3}{2}}\] \[g\left(\frac{11}{3}\right) = (9)^{\frac{3}{2}}\] \[g\left(\frac{11}{3}\right) = (3^2)^{\frac{3}{2}} = 3^3 = 27\]
04

Find g(u+1)

Lastly, we need to find an expression for the value of g(u+1). To do this, we can replace u with (u+1) in the given equation and then simplify: \(g(u+1) = (3(u + 1) - 2)^{\frac{3}{2}}\) \(g(u+1) = (3u + 3 - 2)^{\frac{3}{2}}\) \[g(u+1) = (3u + 1)^{\frac{3}{2}}\] So, the expressions we found are: g(1) = 1 g(6) = 64 g(11/3) = 27 g(u+1) = \((3u + 1)^{\frac{3}{2}}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mathematical Functions
A mathematical function is a relationship between a set of inputs and a set of possible outputs where each input is related to exactly one output. You can think of it like a machine that has an input and an output: for every input value, the function gives you an output value. In the exercise, the function is represented as g(u) where u is the input variable, and the output is determined by the algebraic expression (3u - 2)^{3/2}.

Evaluating a function means finding the result of the function for a given value of the input variable. When the exercise asks for g(1), g(6), or g(11/3), it's looking for the outputs when the input is 1, 6, and 11/3 respectively. Similarly, to find g(u+1), you're asked to determine the function's output when the input is u+1 instead of just u. By substituting the input values into the function and simplifying, we obtain the corresponding outputs.
Exponents
An exponent is a number that indicates how many times to multiply a base number by itself. The operation is known as exponentiation. In the expression (3u - 2)^{3/2}, the exponent 3/2 signifies that after calculating the base (3u - 2), it must be raised to the power of 1.5 (since 3/2 is 1.5). In simpler terms, that base is first squared, and then the square root is taken (since squaring is the exponent 2, and the square root corresponds to the exponent 1/2).

Understanding Fractional Exponents

Fractional exponents, like the one in the exercise, might seem confusing at first glance. A fractional exponent like a^{b/c} means the base a is raised to the power of b, followed by taking the c-th root of the result. The procedure used in the exercise simplifies the calculation by breaking down the exponent into more manageable parts, especially when dealing with integers and their known powers.
Algebraic Expressions
An algebraic expression is a combination of numbers, variables (like u), and arithmetic operations (like addition, subtraction, multiplication, and division). In the context of the exercise, (3u - 2)^{3/2} is an algebraic expression where u is the variable, and it's involved in multiplication by 3, subtraction of 2, and exponentiation. These operations are done following the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

Manipulating Algebraic Expressions

To solve algebraic expressions, you must be comfortable with various arithmetic rules and properties, like the distributive property used to expand g(u+1) in the fourth step of the solution. When evaluating functions or simplifying expressions, it’s essential to perform the operations correctly according to PEMDAS and to be familiar with how to manipulate exponents effectively.

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