/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 Find and simplify $$ \frac{f... [FREE SOLUTION] | 91Ó°ÊÓ

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Find and simplify $$ \frac{f(a+h)-f(a)}{h} \quad(h \neq 0) $$ for each function. \(f(x)=\sqrt{x}\)

Short Answer

Expert verified
The short answer is: \(\frac{1}{\sqrt{a+h} + \sqrt{a}}\).

Step by step solution

01

Substitute the function into the expression

First, we need to substitute the function \(f(x) = \sqrt{x}\) into the expression \(\frac{f(a+h)-f(a)}{h}\). We will replace \(f(a+h)\) with \(\sqrt{a+h}\) and \(f(a)\) with \(\sqrt{a}\). So the given expression becomes: \[ \frac{\sqrt{a+h} - \sqrt{a}}{h} \]
02

Rationalize the numerator

To simplify the expression, we need to rationalize the numerator, which means eliminating the radicals from the numerator. We can do this by multiplying the numerator and denominator by the conjugate of the numerator. The conjugate of the numerator is \(\sqrt{a+h} + \sqrt{a}\). So, we multiply the numerator and denominator by this conjugate: \[ \frac{\sqrt{a+h} - \sqrt{a}}{h} \cdot \frac{\sqrt{a+h} + \sqrt{a}}{\sqrt{a+h} + \sqrt{a}} \]
03

Multiply the numerators and denominators

Now we need to multiply the numerators and denominators. We'll first multiply the numerators: \[ (\sqrt{a+h} - \sqrt{a})(\sqrt{a+h} + \sqrt{a}) = (\sqrt{a+h})^2 - (\sqrt{a})^2 \] This is a difference of squares. Simplifying further, we get: \[ a + h - a \] which becomes just: \[ h \] Now, we'll multiply the denominators: \[ h(\sqrt{a+h} + \sqrt{a}) \] Our new expression is: \[ \frac{h}{h(\sqrt{a+h} + \sqrt{a})} \]
04

Simplify the expression

We can now simplify the expression further by cancelling out the common factor of h in the numerator and denominator: \[ \frac{h}{h(\sqrt{a+h} + \sqrt{a})} \cdot \frac{1}{h} = \frac{1}{\sqrt{a+h} + \sqrt{a}} \] The simplified expression for \(\frac{f(a+h)-f(a)}{h}\) for the given function \(f(x)=\sqrt{x}\) is: \[ \frac{1}{\sqrt{a+h} + \sqrt{a}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rationalizing the Numerator
Rationalizing the numerator is a technique used to simplify expressions that contain a square root in their numerator. The goal is to eliminate the radicals, making the expression easier to work with or more presentable.

When you have a difference involving square roots, such as \(\sqrt{a+h} - \sqrt{a}\), rationalizing involves multiplying both the numerator and the denominator by the conjugate of the numerator. The conjugate of \(\sqrt{a+h} - \sqrt{a}\) is \(\sqrt{a+h} + \sqrt{a}\). By applying this operation, you take advantage of the special property for conjugates: when they are multiplied together, they give you a difference of squares, effectively removing the square roots.

This technique is vital for calculus and algebra because it often simplifies complex fractions, allowing you to cancel terms or proceed with other operations. In this exercise, the rationalized numerator became \(h\) after using the conjugate. This technique transformed the expression into something much simpler and easier to handle. Remember that rationalizing the numerator is particularly useful when you need to deal with limits or derivatives.
Difference of Squares
The difference of squares formula is a fascinating and useful algebraic tool. It allows you to simplify expressions where two square terms are subtracted. The formula is expressed as:\[(a - b)(a + b) = a^2 - b^2\]

In the given exercise, after multiplying by the conjugate, the expression \((\sqrt{a+h} - \sqrt{a})(\sqrt{a+h} + \sqrt{a})\) fits the pattern of a difference of squares. Here, \(a = \sqrt{a+h}\) and \(b = \sqrt{a}\). When you apply the formula, you get \((\sqrt{a+h})^2 - (\sqrt{a})^2\), which simplifies to \(a + h - a\).

The beauty of the difference of squares is that it quickly simplifies what initially appears as a complex expression into something straightforward. Even if terms are initially nested within square roots, the difference of squares can neatly remove these, streamlining the expression to its simplest form. This is incredibly helpful in simplifying rational expressions and plays an important role in the analysis of functions.
Simplifying Expressions
Simplifying expressions is an essential skill in algebra and calculus. It's the process of altering an expression to make it more manageable or easier to understand, often by reducing it into its simplest form.

In this exercise, after rationalizing the numerator and applying the difference of squares, the expression becomes \(\frac{h}{h(\sqrt{a+h} + \sqrt{a})}\). The next logical step is simplifying.

You simplify by canceling common factors in the numerator and the denominator. Here, \(h\) is present in both, so you can cancel it out. The expression simplifies entirely to \(\frac{1}{\sqrt{a+h} + \sqrt{a}}\). This final expression is much less cumbersome and easier for further mathematical operations like evaluating limits.

Simplification helps in understanding the behavior of functions, especially when we look at limits approaching zero or infinity. Remember, the process of simplifying isn't just about making it shorter, it's also about making the expression more functional for its intended use, be it integration, differentiation, or solving equations.

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